📚 Year 7 AQA Physics: Unit Test Mock Paper Walkthrough | AQA 7年级物理：单元测试模拟卷解析
This walkthrough breaks down a typical Year 7 AQA Physics unit test mock paper, covering key topics such as energy, electricity, forces, motion, and waves. Each section explains a question style, identifies common pitfalls, and models the best approach to secure top marks. Use this guide to build confidence and deepen understanding before your real assessment.
本文详细解析一份典型的AQA 7年级物理单元测试模拟卷，涵盖能量、电学、力、运动和波等核心主题。每个部分都会拆解一种题型，指出常见错误，并示范获得高分的答题方法。利用这份指南，你可以在正式评估前建立信心、加深理解。
1. Identifying Forms of Energy | 识别能量的形式
Question example: ‘A moving skateboard has kinetic energy. Name two other energy stores present when the skateboard is moving up a ramp.’ This question tests your ability to recognise energy stores in a real scenario. Kinetic energy is given; you might add gravitational potential energy (as height increases) and thermal energy (from friction). Always link each store to a clear cause.
题目示例：“一个运动的滑板具有动能。请说出当滑板沿斜坡向上运动时存在的另外两种能量储存形式。”这道题考查你在真实情景中识别能量储存的能力。动能已经给出；你可以补充重力势能（随着高度增加）和热能（来自摩擦力）。始终要将每种能量储存与明确的原因联系起来。
2. Energy Transfers in Everyday Objects | 日常物体中的能量转移
You might see a diagram of a battery‑powered fan. The question asks: ‘Describe the main energy transfer that occurs when the fan is switched on.’ The correct answer is: electrical energy ➝ kinetic energy (of the blades) + thermal energy (wasted). Avoid vague phrases like ‘energy is used’. Use labelled arrows to show the pathway clearly.
你可能会看到一幅电池驱动风扇的示意图。题目问：“描述风扇打开时发生的主要能量转移。”正确答案是：电能 → 动能（扇叶的）+ 热能（浪费的）。避免使用“能量被使用”这样的模糊表述。用带箭头的标注清晰地展示转移路径。
3. Building a Simple Circuit | 构建简单电路
Expect a question on drawing circuit symbols. You must know the standard symbol for a cell, battery, bulb, switch, buzzer, and motor. When drawing, use a ruler and do not cross wires unnecessarily. A common mark‑loser is forgetting to draw the switch in the correct position to control the component.
预计会有一道关于绘制电路符号的题目。你必须知道电池、电池组、灯泡、开关、蜂鸣器和马达的标准符号。绘图时使用直尺，并且不要让导线不必要地交叉。一个常见的失分点是忘记将开关画在能控制该元件的正确位置。
4. Measuring Current and its Path | 测量电流及其路径
A typical table shows current readings on either side of a bulb in a series circuit. The question: ‘Explain why the current reading is the same at both positions.’ The answer is that in a series circuit, current is the same everywhere because there is only one loop for charge to flow. Mention ‘conservation of charge’ if you want to impress.
一道典型的表格题会展示串联电路中灯泡两侧的电流读数。问题：“解释为什么两个位置的电流读数相同。”答案是：在串联电路中，电流处处相等，因为只有一条回路供电荷流动。如果你想表现得更出色，可以提到“电荷守恒”。
5. Voltage and Energy Per Charge | 电压与单位电荷的能量
When asked ‘What is voltage a measure of?’, the correct scientific statement is: voltage measures the energy transferred per unit of electric charge. Many students confuse voltage with current. Use the model: higher voltage means more energy given to each coulomb of charge passing through the cell.
当被问到“电压是衡量什么的物理量？”时，正确的科学表述是：电压衡量每单位电荷所转移的能量。许多学生会混淆电压和电流。可以采用这个模型来理解：更高的电压意味着电池给予每库仑通过电荷的能量更多。
6. Forces: Contact and Non‑contact | 力：接触力与非接触力
Question: ‘State one example of a contact force and one example of a non‑contact force.’ Acceptable answers: friction (contact) and gravitational force (non‑contact). You might also use magnetism or electrostatic force for non‑contact. Always include the type of object involved to make your answer complete.
问题：“分别举一个接触力和一个非接触力的例子。”可接受的答案：摩擦力（接触）和重力（非接触）。你也可以用磁力或静电力作为非接触力的例子。回答时始终包含所涉及的物体类型，以使答案完整。
7. Resultant Force and Motion | 合力与运动
A diagram shows two horizontal forces on a car: 500 N thrust and 300 N air resistance. ‘Calculate the resultant force and describe the motion.’ Resultant force = 500 N − 300 N = 200 N forward. The car accelerates to the right. If the forces were balanced, the car would move at constant speed or remain stationary.
一幅图显示一辆汽车上的两个水平力：500 N的推力和300 N的空气阻力。“计算合力并描述运动状态。”合力 = 500 N − 300 N = 200 N，方向向前。汽车将向右加速。如果两个力平衡，汽车将保持匀速运动或静止。
8. Speed Calculations Using the Formula | 用公式计算速度
You will need to recall and apply the speed equation. The formula is:
你需要回忆并应用速度公式。公式为：
average speed = distance travelled ÷ time taken
Question: ‘A cyclist covers 450 metres in 30 seconds. Calculate the average speed.’ Step 1: Write the formula. Step 2: Substitute: 450 ÷ 30. Step 3: Answer = 15 m/s. Always include the unit (m/s or m s⁻¹) to gain the marks for working.
题目：“一名自行车手在30秒内行驶了450米。计算平均速度。”第一步：写出公式。第二步：代入数值：450 ÷ 30。第三步：答案 = 15 m/s。始终记得写上单位（m/s或m s⁻¹），以获得计算过程的分值。
9. Interpreting Distance–Time Graphs | 解读距离—时间图
A distance–time graph with a sloping straight line indicates constant speed. A horizontal line means the object is stationary. Steeper gradient = higher speed. When asked to calculate speed from the graph, pick two points on the straight section and divide the change in distance by the change in time.
距离—时间图中倾斜的直线表示匀速运动。水平线表示物体静止。斜率越大，速度越高。当要求从图中计算速度时，在直线段上选取两点，用距离变化量除以时间变化量。
10. The Effect of Friction on Moving Objects | 摩擦力对运动物体的影响
Explain why a sliding block eventually stops on a rough surface. The friction force acts in the opposite direction to motion, causing a resultant force that reduces speed. Energy is transferred to the thermal store of the surfaces. This is not ‘using up energy’ but transferring it to less useful stores.
解释为什么一个滑动的物块在粗糙表面上最终会停下来。摩擦力与运动方向相反，产生一个使速度减小的合力。能量被转移到接触面的热能储存中。这并非“能量用完了”，而是能量被转移到了不那么有用的储存形式。
11. Gravity, Mass and Weight | 重力、质量与重量
Mass (kg) is the amount of matter; weight (N) is the force due to gravity. Use the formula correctly:
质量（kg）是物质多少的量度；重量（N）是由于重力而产生的力。正确使用公式：
weight (N) = mass (kg) × gravitational field strength (N/kg)
On Earth, g ≈ 9.8 N/kg, but your exam may use 10 N/kg. If mass = 5 kg, weight = 5 × 10 = 50 N. Never confuse mass and weight in your explanation of gravity.
在地球上，g ≈ 9.8 N/kg，但考试可能会使用10 N/kg。如果质量为5 kg，则重量 = 5 × 10 = 50 N。在解释重力时，切勿混淆质量和重量这两个概念。
12. Law of Reflection and Ray Diagrams | 反射定律与光线图
Question: ‘Draw and label a ray diagram showing light hitting a plane mirror. State the law of reflection.’ Use a ruler for straight rays and a normal line at 90° to the mirror surface. Label incident ray, reflected ray, angle of incidence (i) and angle of reflection (r). The law: i = r. Angles are measured from the normal, not the mirror surface.
问题：“画出并标注一束光照射在平面镜上的光线图。陈述反射定律。”使用直尺绘制笔直的射线，并在镜面处画出与之成90°的法线。标注入射光线、反射光线、入射角（i）和反射角（r）。定律为：i = r。角度必须从法线量起，而不是从镜面量起。
Published by TutorHao | Physics Revision Series | aleveler.com
更多咨询请联系16621398022（同微信）
屏轩国际教育cambridge primary/secondary checkpoint, cat4, ukiset,ukcat,igcse,alevel,PAT,STEP,MAT, ibdp,ap,ssat,sat,sat2课程辅导，国外大学本科硕士研究生博士课程论文辅导