📚 Mastering Quadratic Equations and Functions | 掌握二次方程与函数
Quadratic equations and functions are a cornerstone of the IGCSE Mathematics syllabus. Understanding their structure, solutions, and graphs will not only help you score highly but also build a strong foundation for advanced topics.
二次方程与函数是 IGCSE 数学教学大纲的基石。理解它们的结构、解法和图像,不仅能帮助你在考试中获得高分,还能为更高级的数学主题打下坚实基础。
1. The General Form of a Quadratic Function | 二次函数的一般形式
A quadratic function is any function that can be written in the form f(x) = ax² + bx + c, where a, b and c are constants with a ≠ 0. The highest power of x is always 2.
二次函数是指可以写成 f(x) = ax² + bx + c 形式的函数,其中 a、b、c 为常数,且 a ≠ 0。x 的最高次数始终为 2。
If a > 0, the graph opens upwards like a smile. If a < 0, the graph opens downwards like a frown. The value of a also controls how “steep” the curve is.
当 a > 0 时,图像向上开口,如同微笑;当 a < 0 时,图像向下开口,如同皱眉。a 的值还控制着曲线的“陡峭”程度。
2. Standard Form and the Shape of the Parabola | 标准形式与抛物线形状
The standard form y = ax² + bx + c is easy to evaluate but not easy to sketch. To understand the shape, we find three important features: the y-intercept, the roots (x-intercepts), and the vertex (turning point).
标准形式 y = ax² + bx + c 便于求值,但不便于画图。要理解其形状,我们需要找到三个重要特征:y 截距、根(x 截距)以及顶点(转向点)。
- The y-intercept is always at (0, c).
- y 截距总是在 (0, c) 处。
- The x-intercepts are the solutions of ax² + bx + c = 0.
- x 截距是方程 ax² + bx + c = 0 的解。
- The vertex lies on the axis of symmetry x = −b / (2a).
- 顶点位于对称轴 x = −b / (2a) 上。
Axis of symmetry: x = −b ÷ (2a)
对称轴:x = −b ÷ (2a)
3. Solving by Factorisation | 因式分解法求解
Factorisation is the fastest method when the quadratic has simple integer roots. We rewrite the quadratic as a product of two linear brackets.
当二次方程具有简单的整数根时,因式分解是最快的方法。我们将二次式重写为两个一次括号的乘积。
For example, solve x² − 5x + 6 = 0. We look for two numbers that multiply to 6 and add to −5. These are −2 and −3, so (x − 2)(x − 3) = 0. Therefore x = 2 or x = 3.
例如,解 x² − 5x + 6 = 0。我们需要找到两个数,它们乘积为 6,和为 −5。这两个数是 −2 和 −3,所以 (x − 2)(x − 3) = 0。因此 x = 2 或 x = 3。
Always rearrange the equation into the form ax² + bx + c = 0 before factorising. If the coefficient of x² is not 1, use the method of splitting the middle term or trial and error.
在因式分解之前,务必先将方程整理成 ax² + bx + c = 0 的形式。如果 x² 的系数不为 1,可以使用拆中项法或试错法。
4. Solving by Completing the Square | 配方法求解
Completing the square transforms ax² + bx + c into a(x + h)² + k. This form reveals the vertex directly: the vertex is (−h, k).
配方法将 ax² + bx + c 变换为 a(x + h)² + k。这种形式直接揭示顶点:顶点为 (−h, k)。
For example, complete the square for x² + 6x + 1. Take half of 6, which is 3, and square it to get 9. Then x² + 6x = (x + 3)² − 9. Hence x² + 6x + 1 = (x + 3)² − 8.
例如,对 x² + 6x + 1 配方。取 6 的一半等于 3,平方得到 9。于是 x² + 6x = (x + 3)² − 9。因此 x² + 6x + 1 = (x + 3)² − 8。
To solve an equation, set the completed-square form equal to zero and take the square root of both sides.
要解方程,将配方后的形式设为零,然后两边开平方。
5. The Quadratic Formula | 二次公式
The quadratic formula works for all quadratics, including those that cannot be factorised. For ax² + bx + c = 0:
二次公式适用于所有二次方程,包括无法因式分解的方程。对于 ax² + bx + c = 0:
x = [−b ± √(b² − 4ac)] ÷ (2a)
x = [−b ± √(b² − 4ac)] ÷ (2a)
Memorise this formula carefully. In the IGCSE Edexcel exam, you may be expected to use it without a calculator, so practise substituting values accurately.
请仔细记住这个公式。在 Edexcel IGCSE 考试中,你可能需要在不使用计算器的情况下使用它,因此要练习准确代入数值。
6. The Discriminant | 判别式
The expression b² − 4ac inside the square root is called the discriminant. It tells us the number and type of roots without fully solving the equation.
根号内的表达式 b² − 4ac 称为判别式。它无需完整解方程就能告诉我们根的数量和类型。
- If b² − 4ac > 0, there are two distinct real roots.
- 若 b² − 4ac > 0,则有两个不同实根。
- If b² − 4ac = 0, there is one repeated real root.
- 若 b² − 4ac = 0,则有一个重根(两个相等实根)。
- If b² − 4ac < 0, there are no real roots.
- 若 b² − 4ac < 0,则没有实根。
The discriminant also helps in sketching: positive means the parabola crosses the x-axis twice, zero means it touches once, and negative means it never crosses the x-axis.
判别式也有助于画图:正值意味着抛物线与 x 轴相交两次,零意味着相切一次,负值意味着永不与 x 轴相交。
7. Sum and Product of Roots | 根的和与积
For a quadratic equation ax² + bx + c = 0 with roots α and β, we can find relationships without solving:
对于具有根 α 和 β 的二次方程 ax² + bx + c = 0,我们无需解方程即可找到关系:
Sum of roots: α + β = −b ÷ a
根的和:α + β = −b ÷ a
Product of roots: αβ = c ÷ a
根的积:αβ = c ÷ a
These formulas are useful for checking answers and for forming new quadratics with given roots. If the roots are α and β, the quadratic can be written as x² − (α + β)x + αβ = 0.
这些公式可用于检查答案,以及根据给定根构造新的二次方程。若根为 α 和 β,则可以写成 x² − (α + β)x + αβ = 0。
8. Sketching Quadratic Graphs | 二次函数图像的画法
A good sketch of a quadratic needs five key features: shape (upwards or downwards), y-intercept, x-intercepts, vertex, and axis of symmetry.
一个高质量的二次函数草图需要五个关键特征:开口方向(向上或向下)、y 截距、x 截距、顶点和对称轴。
- Determine the sign of a to decide the shape.
- 确定 a 的正负以决定开口方向。
- Find the y-intercept by substituting x = 0.
- 通过代入 x = 0 求 y 截距。
- Solve f(x) = 0 to find the x-intercepts.
- 解 f(x) = 0 求 x 截距。
- Use x = −b/(2a) to find the axis of symmetry, then substitute back to find the vertex.
- 使用 x = −b/(2a) 求对称轴,然后代回求顶点。
If the quadratic has no real roots, you only need the vertex and the y-intercept, and you must label the graph clearly.
如果二次方程没有实根,你只需要顶点和 y 截距,但必须清楚地标注图像。
9. Solving Quadratic Inequalities | 二次不等式
Quadratic inequalities require you to first solve the corresponding equation, then decide which intervals satisfy the inequality.
二次不等式需要你先解对应的方程,然后判断哪些区间满足不等式。
For example, solve x² − x − 6 < 0. Factorise: (x − 3)(x + 2) < 0. The critical points are x = −2 and x = 3. Test values in the three intervals:
例如,解 x² − x − 6 < 0。因式分解:(x − 3)(x + 2) < 0。临界点为 x = −2 和 x = 3。在三个区间内测试数值:
- x < −2: both brackets negative, product positive → not a solution.
- x < −2:两个括号均为负,乘积为正 → 不是解。
- −2 < x < 3: one negative, one positive, product negative → solution.
- −2 < x < 3:一负一正,乘积为负 → 是解。
- x > 3: both positive, product positive → not a solution.
- x > 3:两个括号均为正,乘积为正 → 不是解。
Solution: −2 < x < 3
解:−2 < x < 3
Be careful with the direction of the inequality when multiplying by a negative number.
当乘以负数时,要小心不等式方向的变化。
10. Applications: Area and Projectile Motion | 实际应用:面积与抛体运动
Quadratic equations often appear in geometry. For example, a rectangle has length (x + 3) cm and width (x − 1) cm. If the area is 12 cm², find x.
二次方程经常出现在几何问题中。例如,一个矩形的长为 (x + 3) cm,宽为 (x − 1) cm。如果面积为 12 cm²,求 x。
Area = length × width, so (x + 3)(x − 1) = 12. Expanding gives x² + 2x − 3 = 12, so x² + 2x − 15 = 0. Factorising: (x + 5)(x − 3) = 0, so x = 3 or x = −5. Since a length cannot be negative, x = 3.
面积 = 长 × 宽,所以 (x + 3)(x − 1) = 12。展开得 x² + 2x − 3 = 12,即 x² + 2x − 15 = 0。因式分解得 (x + 5)(x − 3) = 0,所以 x = 3 或 x = −5。由于长度不能为负,因此 x = 3。
In physics, the height of a projectile is often modelled by h(t) = −4.9t² + vt + h₀. Setting h = 0 gives the time when it lands. Always interpret the roots in context and discard impossible values.
在物理中,抛体的高度通常用 h(t) = −4.9t² + vt + h₀ 模型表示。令 h = 0 可求出落地时间。始终根据实际背景解释根,并舍弃不可能的值。
11. Common Mistakes to Avoid | 避免常见错误
Many students lose marks on quadratic questions due to avoidable errors. Here are the most frequent pitfalls:
许多学生在二次方程题目中因为可避免的错误而丢分。以下是最常见的陷阱:
- Forgetting to rearrange the equation to equal zero before factorising.
- 忘记先将方程整理成等于零的形式再进行因式分解。
- Misapplying the quadratic formula by using −b incorrectly.
- 错误地使用二次公式中的 −b。
- When completing the square, forgetting to divide all terms by a if a ≠ 1.
- 配方时,若 a ≠ 1,忘记将所有项除以 a。
- Swapping the signs when using the sum and product of roots.
- 使用根的和与积时弄错符号。
- In inequalities, not testing all intervals.
- 在不等式中,没有测试所有区间。
Always check your solutions by substituting back into the original equation.
始终通过代入原方程来检验你的解。
12. Practice Summary and Exam Tips | 练习总结与考试技巧
Quadratic questions appear in both Paper 1 (non-calculator) and Paper 2 (calculator). A quick revision checklist:
二次方程题目在 Paper 1(非计算器)和 Paper 2(计算器)中都会出现。快速复习清单如下:
| Skill | 技能 | Key Point | 要点 |
| Factorisation | 因式分解 | Find two numbers with correct sum and product | 找两个数,使其和与积正确 |
| Completing the square | 配方 | Vertex = (−h, k) in a(x + h)² + k | 顶点 = (−h, k) |
| Quadratic formula | 二次公式 | x = [−b ± √(b² − 4ac)] / (2a), memorise it | 牢记公式 |
| Discriminant | 判别式 | b² − 4ac determines number of real roots | 决定实根个数 |
In the exam, read the question carefully: does it ask for exact values or rounded to a certain degree? Draw clear graphs using a ruler for straight lines, but quadratic curves should be smooth and symmetric.
考试中请仔细读题:要求精确值还是四舍五入到指定精度?画图时直线用直尺,二次曲线要平滑且对称。
Practice every method until it becomes automatic. Mastering quadratics will guarantee many easy marks across both papers.
将每种方法练习到自动熟练的程度。掌握二次方程将确保你在两份试卷中稳定获得大量分数。
Published by TutorHao | Mathematics Revision Series | aleveler.com
更多咨询请联系16621398022(同微信)
屏轩国际教育cambridge primary/secondary checkpoint, cat4, ukiset,ukcat,igcse,alevel,PAT,STEP,MAT, ibdp,ap,ssat,sat,sat2课程辅导,国外大学本科硕士研究生博士课程论文辅导Cancel reply