📚 Projectile Motion Formulae | 抛体运动公式
In Edexcel A-Level Mechanics, projectile motion is treated as two independent linear motions: constant horizontal velocity and constant vertical acceleration due to gravity. The formulae below connect initial speed, angle of projection, time, displacement and velocity.
在 Edexcel A-Level 力学中,抛体运动被分解为两个独立的直线运动:水平方向速度恒定,竖直方向受重力加速度影响。以下公式将初速度、抛射角、时间、位移和速度联系起来。
1. Modelling Assumptions for Projectile Motion | 抛体运动的基本假设
In projectile motion questions, the object is treated as a particle moving under gravity alone. This means air resistance is ignored, the horizontal acceleration is zero, and the vertical acceleration is constant with magnitude g = 9.8 m s⁻² directed downward.
在抛体运动题目中,物体被视为仅在重力作用下的质点。这意味着忽略空气阻力,水平加速度为零,竖直加速度恒为 g = 9.8 m s⁻²,方向向下。
These assumptions allow the horizontal and vertical motions to be analysed separately using SUVAT equations. The horizontal and vertical components are linked only by the time of flight t.
这些假设使我们能够使用匀加速运动公式分别分析水平与竖直运动。水平分量和竖直分量只通过飞行时间 t 相互联系。
2. Resolving Initial Velocity into Components | 初速度的正交分解
If the initial speed is u and the angle of projection is θ above the horizontal, resolve the initial velocity into two perpendicular components.
若初速度为 u,发射角为水平上方 θ,则将初速度分解为两个正交分量。
Horizontal component: u cos θ
Vertical component: u sin θ
The horizontal component is the adjacent side of the right-angled vector triangle, so it uses cos θ. The vertical component is opposite the angle, so it uses sin θ.
水平分量是速度矢量直角三角形中的邻边,因此使用 cos θ。竖直分量是该角的对边,因此使用 sin θ。
3. Horizontal Motion Formula | 水平方向运动公式
The horizontal component of velocity is constant because there is no horizontal force. Therefore the horizontal displacement after time t is found directly from speed × time.
由于没有水平力,水平速度分量保持不变。因此时间 t 后的水平位移可直接用速度 × 时间求得。
x = u cos θ × t
This equation is valid for the entire flight, regardless of the vertical motion. In suvat form, horizontal acceleration is zero and initial horizontal velocity is u cos θ.
该方程在整个飞行过程中都成立,与竖直运动无关。在匀加速公式中,水平加速度为零,初始水平速度为 u cos θ。
4. Vertical Motion Formula | 竖直方向运动公式
Taking upward as positive, vertical motion has constant acceleration a = −g. The two main vertical equations are the displacement equation and the velocity equation.
取向上为正方向,竖直运动具有恒定加速度 a = −g。两个主要的竖直方程是位移方程和速度方程。
y = u sin θ × t − ½ g t²
Vertical velocity: v_y = u sin θ − g t
In these equations, y is the vertical displacement above the launch point and v_y is the vertical component of velocity at time t. The term ½ g t² is subtracted because gravity acts downward while upward is positive.
在这些方程中,y 是相对于抛出点的竖直位移,v_y 是时间 t 时的竖直
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