IB CCEA Chemistry: Mole Calculations – Key Points Review | IB CCEA 化学：摩尔计算 考点精讲

📚 IB CCEA Chemistry: Mole Calculations – Key Points Review | IB CCEA 化学：摩尔计算 考点精讲

The mole is the cornerstone of quantitative chemistry, underpinning everything from stoichiometry to solution concentrations. For both IB and CCEA specifications, a solid grasp of mole calculations is essential to succeed in exams and practical assessments. This article breaks down key concepts, formulas, and typical exam applications to help you master mole calculations with confidence.

摩尔是定量化学的基石，支撑着从化学计量到溶液浓度等各个领域。无论是IB还是CCEA课程大纲，扎实掌握摩尔计算对于考试和实验评估都至关重要。本文将深入解析关键概念、公式和常见考题应用，帮助你自信掌握摩尔计算。

1. The Mole and Avogadro’s Constant | 摩尔与阿伏伽德罗常数

The mole (symbol mol) is the SI unit for amount of substance. One mole contains exactly 6.02214076 × 10²³ elementary entities, known as the Avogadro constant, Nₐ. Entities can be atoms, molecules, ions, electrons, or formula units. This number allows chemists to count particles by weighing.

摩尔（符号 mol）是物质的量的国际单位。一摩尔精确包含 6.02214076 × 10²³ 个基本单元，这个数值被称为阿伏伽德罗常数 Nₐ。基本单元可以是原子、分子、离子、电子或化学式单元。这个数字使化学家能够通过称量来计数微粒。

The number of moles, n, can be calculated from the number of particles, N, using n = N / Nₐ. Conversely, N = n × Nₐ.

物质的量 n 可由微粒数 N 通过公式 n = N / Nₐ 计算得出，反之 N = n × Nₐ。

Avogadro’s constant applies universally; for example, 1 mol of CO₂ contains 1 mol of CO₂ molecules, 1 mol of carbon atoms, and 2 mol of oxygen atoms.

阿伏伽德罗常数普遍适用；例如，1 mol CO₂ 含有 1 mol CO₂ 分子、1 mol 碳原子和 2 mol 氧原子。

n = N / Nₐ

2. Molar Mass and Mass–Mole Conversions | 摩尔质量与质量–摩尔转换

The molar mass (M) of a substance is the mass of one mole of its entities, expressed in g mol⁻¹. It is numerically equal to the relative atomic mass (Aᵣ) or relative formula mass (Mᵣ).

物质的摩尔质量（M）是一摩尔该物质基本单元的质量，单位为 g mol⁻¹。在数值上等于相对原子质量（Aᵣ）或相对化学式质量（Mᵣ）。

To convert mass to moles, use the equation n = m / M, where m is mass in grams and M is molar mass. To find mass from moles, rearrange: m = n × M.

要将质量转换为物质的量，使用公式 n = m / M，其中 m 是质量（克），M 是摩尔质量。由物质的量求质量，则使用 m = n × M。

Example: Calculate the moles in 10.0 g of CaCO₃ (M = 100.1 g mol⁻¹). n = 10.0 / 100.1

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