Cambridge Year 7 Geography: Interdisciplinary Exam Practice | 剑桥七年级地理：跨学科综合题型训练

📚 Cambridge Year 7 Geography: Interdisciplinary Exam Practice | 剑桥七年级地理：跨学科综合题型训练

Geography is not just about memorising places; it requires you to combine skills from mathematics, science, history, and even economics. In the Cambridge Year 7 exam, you will encounter interdisciplinary questions that test your ability to apply knowledge across subjects. This article provides a set of guided practice tasks to build your confidence in tackling these cross-curricular challenges.

地理学不只是记忆地名；它要求你综合运用数学、科学、历史甚至经济学的技能。在剑桥七年级考试中，你会遇到跨学科题型，考查你综合运用各科知识的能力。本文提供一系列指导性练习，帮助你增强应对这些跨学科挑战的信心。

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1. Map Scale and Distance Calculations | 地图比例尺与距离计算

Every map has a scale that links distances on paper to real-world distances. This skill uses ratios and unit conversions from mathematics. You must be able to read a scale as a ratio, a written statement, or a linear bar.

每张地图都有一个比例尺，将图上的距离与实际距离联系起来。这项技能运用数学中的比例和单位换算。你必须能读懂比例式、文字说明或线段比例尺。

Example: A map has a scale of 1:25,000. Two villages are 6 cm apart on the map. Calculate the actual distance in kilometres.

例题：一张地图的比例尺是 1:25000。两个村庄在图上相距 6 厘米。计算实际距离，单位为千米。

Step 1: Understand that 1 cm on the map represents 25,000 cm on the ground. Multiply the map distance by the scale factor: 6 × 25,000 = 150,000 cm.

步骤1：明白图上 1 厘米代表地面 25000 厘米。将图上距离乘以比例因子：6 × 25000 = 150000 厘米。

Step 2: Convert centimetres to metres by dividing by 100 (150,000 ÷ 100 = 1,500 m). Then convert to kilometres by dividing by 1,000 (1,500 ÷ 1,000 = 1.5 km). Final answer: 1.5 km.

步骤2：将厘米转换为米，除以 100（150000 ÷ 100 = 1500 米）。再转换为千米，除以 1000（1500 ÷ 1000 = 1.5 千米）。最终答案：1.5 千米。

Always write the units in your answer! If you were given a bar scale instead, you would measure its segments and apply the same logic.

答案中务必写出单位！如果给出的是线段比例尺，你只需量取线段长度并运用同样的逻辑即可。

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2. Interpreting Topographic Contours | 解读地形等高线

Contour lines show height above sea level. They let you calculate the steepness of a slope, which combines map reading with simple mathematical formulas for gradient.

等高线表示海拔高度。它们能让你计算坡度，这结合了地图阅读和简单的数学坡度公式。

Gradient (%) = (Vertical rise ÷ Horizontal run) × 100

坡度 (%) = (垂直高差 ÷ 水平距离) × 100

Example: On a 1:10,000 topographic map, point A has an elevation of 120 m and point B has 240 m. The straight-line distance between them on the map is 4 cm. Find the average gradient.

例题：在一幅 1:10000 地形图上，点 A 海拔 120 米，点 B 海拔 240 米。两点在图上的直线距离是 4 厘米。求平均坡度。

Step 1: Calculate the vertical rise: 240 m − 120 m = 120 m. Step 2: Find the real horizontal run: 4 cm on the map × 10,000 = 40,000 cm = 400 m. Step 3: Apply the formula: (120 ÷ 400) × 100 = 30% gradient.

步骤1：计算垂直高差：240 米 − 120 米 = 120 米。步骤2：求实际水平距离：图上的 4 厘米 × 10000 = 40000 厘米 = 400 米。步骤3：代入公式：(120 ÷ 400) × 100 = 30% 坡度。

A steep gradient means the land rises quickly. This is important in deciding where to build roads or houses.

坡度越大，地势升高越快。这在决定道路或房屋选址时非常重要。

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3. Climate Graphs and Data Analysis | 气候图表与数据分析

Climate graphs display temperature and precipitation data for a location. You must be able to read tables, draw bar and line graphs, and perform statistical calculations using the same data-handling skills you learn in maths and science.

气候图表展示某地的气温和降水数据。你必须能读懂表格、绘制柱状图和折线图，并运用数学与科学课上学到的数据处理技能进行统计计算。

Month	J	F	M	A	M	J	J	A	S	O	N	D
Temp (°C)	5	6	9	12	16	19	22	21	18	13	9	6
Rain (mm)	70	50	60	45	50	55	40	60	55	80	85	75

Questions: Use the table above for London. (a) Calculate the total annual precipitation. (b) Find the mean annual temperature. (c) What is the annual temperature range?

问题：使用上表伦敦数据。(a) 计算年总降水量。(b) 求年平均气温。(c) 气温年较差是多少？

Answers: (a) Add all 12 rainfall figures: 70+50+60+45+50+55+40+60+55+80+85+75 = 725 mm. (b) Add all temperatures: 5+6+9+12+16+19+22+21+18+13+9+6 = 156. Divide by 12 → mean = 13°C. (c) Range = warmest − coldest = 22°C − 5°C = 17°C.

答案：(a) 将 12 个月的降水量相加：70+50+60+45+50+55+40+60+55+80+85+75 = 725 毫米。(b) 把各月气温相加：5+6+9+12+16+19+22+21+18+13+9+6 = 156。除以 12 → 平均值为 13°C。(c) 较差 = 最热月 − 最冷月 = 22°C − 5°C = 17°C。

Always double-check that you are reading the correct units: millimetres for rain and degrees Celsius for temperature.

务必再次检查单位是否正确：降水量用毫米，气温用摄氏度。

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4. Population Pyramids and Historical Change | 人口金字塔与历史变迁

Population pyramids show the age and sex structure of a country. Their shape can reveal historical events such as wars, baby booms, or migration. You can also use the data to calculate dependency ratios.

人口金字塔展示一个国家的人口年龄和性别结构。它们的形状可以揭示战争、婴儿潮或迁移等历史事件。你还可以用这些数据计算抚养比。

Example: A country in 1950 has the following age group percentages: 0–14: 30%, 15–64: 58%, 65+: 12%. The pyramid has a wide base and a narrow top.

例题：1950 年某国各年龄组百分比如下：0–14 岁：30%，15–64 岁：58%，65 岁以上：12%。金字塔底部宽，顶部窄。

Question (a): Explain, using historical knowledge, why the base might be so wide. (b) Calculate the youth dependency ratio.

问题 (a)：结合历史知识，解释为什么金字塔底部可能如此宽。(b) 计算少年儿童抚养比。

Answer (a): Many countries experienced a post-war baby boom after World War II, combined with high birth rates and improvements in child healthcare. This led to a larger proportion of young people.

答案 (a)：许多国家在二战后经历了婴儿潮，加上高出生率和儿童医疗条件的改善，导致年轻人口比例较高。

Answer (b): Youth dependency ratio = (0–14 population ÷ 15–64 population) × 100 = (30 ÷ 58) × 100 ≈ 51.7%. This means there are about 52 young dependents for every 100 working-age people.

答案 (b)：少年儿童抚养比 = (0–14 人口 ÷ 15–64 人口) × 100 = (30 ÷ 58) × 100 ≈ 51.7%。这意味着每 100 个劳动年龄人口要抚养约 52 个少年儿童。

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5. Rock Cycle and Earth Science | 岩石循环与地球科学

The rock cycle shows how igneous, sedimentary and metamorphic rocks are linked by processes such as weathering, erosion, heat and pressure. This topic blends geography with chemistry and physics.

岩石循环展示了火成岩、沉积岩和变质岩如何通过风化、侵蚀、热力和压力等过程相互转化。这一主题将地理与化学和物理知识融为一体。

Example question: Granite is an igneous rock. Describe the steps that can transform it into a sedimentary rock like sandstone.

例题：花岗岩是一种火成岩。请描述它如何转变为沉积岩（如砂岩）的步骤。

Step 1: Weathering breaks the granite into small particles. Physical weathering (freeze-thaw) and chemical weathering weaken the rock.

步骤1：风化作用将花岗岩破碎成小颗粒。物理风化（冻融作用）和化学风化使岩石变弱。

Step 2: Erosion transports the particles by rivers, wind or ice to a new location where they are deposited as sediment.

步骤2：侵蚀作用通过河流、风或冰将颗粒搬运到新的地点，在那里沉积为沉积物。

Step 3: Over time, layers of sediment build up. Compaction presses the grains together and cementation by minerals binds them into solid rock — forming sedimentary rock.

步骤3：随着时间推移，沉积物层层堆积。压实作用将颗粒挤紧，胶结作用用矿物将其黏结成固体岩石——从而形成沉积岩。

Understanding the rock cycle helps explain landscapes and the distribution of natural resources.

理解岩石循环有助于解释地貌和自然资源的分布。

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6. River Processes and Energy | 河流过程与能量

Rivers transfer energy and shape the landscape. Calculating river discharge uses a formula that connects geography with physics and mathematics.

河流传递能量并塑造地貌。计算河流流量需要一个公式，它连接了地理与物理和数学。

Discharge (Q) = Cross-sectional area (A) × Velocity (v)

流量 (Q) = 过水断面面积 (A) × 流速 (v)

Example: A river channel has a cross-sectional area of 5.5 m² and the water flows at an average speed of 1.2 m/s. Calculate the discharge in cubic metres per second.

例题：某河道过水断面面积为 5.5 平方米，平均流速为 1.2 米/秒。计算流量，单位是立方米每秒。

Q = 5.5 m² × 1.2 m/s = 6.6 m³/s. This volume of water carries energy that can erode the river bed and transport sediment. Higher discharge usually means more erosive power.

Q = 5.5 平方米 × 1.2 米/秒 = 6.6 立方米/秒。这一水体携带能量，能够侵蚀河床并搬运泥沙。流量越大，通常侵蚀力越强。

When interpreting hydrographs, you

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