📚 Year 7 Edexcel Maths: Answer Writing Framework and Model Answers | Year 7 Edexcel数学：解题写作框架与范文
In Year 7 Edexcel Maths, many questions require you to “show your working” or “explain your reasoning”. Writing a clear, step-by-step solution is much like composing a short essay: it needs a logical flow, correct terminology, and a strong conclusion. This guide introduces a simple five-step framework to help you structure maths answers for topics ranging from fractions and decimals to perimeter and basic algebra. You will also find two fully worked model answers to illustrate what examiners expect.
在Year 7 Edexcel数学考试中，很多题目要求你“展示解题过程”或“解释你的推理”。写清楚、有步骤的解答就像写一篇小短文：要有逻辑顺序、正确的术语和有力的结论。本指南介绍一个简单的五步框架，帮助你搭建从分数、小数到周长和基础代数等各类数学题的答案结构。你还将看到两篇完整范文，直观展示阅卷官的期待。
1. Why Structured Answers Matter in Year 7 Maths | 为什么Year 7数学需要结构化作答
Edexcel assessments reward not only correct answers but also the quality of written communication. Marks are often allocated for method steps, so a well-structured response can help you earn marks even if a small arithmetic slip occurs. In addition, writing in a clear essay-like style trains you to think logically and spot your own mistakes.
Edexcel考评不仅奖励正确答案，也看重书面表达的质量。步骤分经常占一部分，因此结构清晰的作答即使有一处计算小错误也能拿到大部分分数。另外，像写短文一样清楚作答能训练逻辑思维，帮助你发现自己的错误。
2. The Five-Part Maths Answer Framework | 数学解答五步框架
Every fully-explained maths answer can be built using five blocks: Given, Strategy, Working, Answer and Check. Think of these as the introduction, body and conclusion of your solution essay. The table below summarises what to include in each part.
每个完整的数学解答都可以用五个模块搭建：已知条件、解题策略、计算过程、最终答案和检验。你可以把它们看作解答短文的引言、正文和结论。下表总结了每个部分需要写什么。
| Part | Purpose | Key sentence starters |
|---|---|---|
| Given | List the known numbers and what you need to find. | From the question: … / We know that … / Let … be … |
| Strategy | State which method, formula or operation you will use. | To find … we can use … / The formula is … / I will … |
| Working | Show each calculation step clearly, one line at a time. | First, … / Next, … / This gives … |
| Answer | Write the final answer with units, rounding or simplest form. | Therefore, … / The answer is … |
| Check | Verify by reversing the operation or using an estimate. | To check: … / The reverse calculation gives … |
3. Model Answer 1: Perimeter of a Rectangle | 范文1：长方形的周长
Question: A rectangle has length 12 cm and width 8 cm. Calculate the perimeter. Show each step of your reasoning.
题目：一个长方形的长是12厘米，宽是8厘米。计算它的周长。请展示推理的每一步。
Now, let’s apply the five-part framework. | 现在我们来应用五步框架。
Given: Length, L = 12 cm; width, W = 8 cm. Need perimeter, P. | 已知：长L=12 cm；宽W=8 cm。求周长P。
Strategy: The perimeter of a rectangle is the total distance around the shape. Formula: P = 2 × (L + W) or P = 2L + 2W. I will use P = 2(L + W). | 策略：长方形周长是四周的总长度。公式：P = 2 × (L + W) 或 P = 2L + 2W。我用 P = 2(L + W)。
Working:
Step 1: L + W = 12 + 8 = 20
Step 2: P = 2 × 20 = 40
So the perimeter equals 40 cm.
计算过程：
第一步：L + W = 12 + 8 = 20
第二步：P = 2 × 20 = 40
因此周长等于40 cm。
Answer: The perimeter of the rectangle is 40 cm.
答案：长方形的周长是40厘米。
Check: Work backwards using division. If P = 40 cm, then half the perimeter is P/2 = 20 cm. Subtract length W: 20 − 8 = 12 cm, which matches the given length. ✓ | 检验：用除法逆推。如果P=40 cm，则半周长P/2=20 cm。减去宽8 cm得12 cm，与已知长一致。✓
4. Model Answer 2: Fraction Problem Solving | 范文2：分数应用题
Question: Maya spent 3/10 of her pocket money on a game and 2/5 on a book. What fraction of her money is left? Give your answer in its simplest form.
题目：Maya用她零花钱的3/10买了一个游戏，用2/5买了一本书。她还剩下几分之几？答案需化为最简分数。
Given: Fraction spent on game = 3/10; fraction spent on book = 2/5. Need fraction left. | 已知：游戏花费比例 = 3/10；书花费比例 = 2/5。求剩余分数。
Strategy: First, find total fraction spent by adding the two fractions. Since denominators are different, rewrite 2/5 as an equivalent fraction with denominator 10. Then subtract from 1 (the whole). | 策略：先通过加法求出总花费分数。由于分母不同，把2/5改写为分母为10的等价分数。再从整体1中减去。
Working:
Step 1: Convert 2/5 to tenths. 2/5 = (2×2)/(5×2) = 4/10.
Step 2: Total spent = 3/10 + 4/10 = 7/10.
Step 3: Fraction left = 1 − 7/10. Write 1 as 10/10.
10/10 − 7/10 = 3/10.
计算过程：
第一步：把2/5化为十分之几。2/5 = (2×2)/(5×2) = 4/10。
第二步：总花费 = 3/10 + 4/10 = 7/10。
第三步：剩余分数 = 1 − 7/10。把1写成10/10。
10/10 − 7/10 = 3/10。
Answer: Maya has 3/10 of her pocket money left (already in simplest form).
答案：Maya还剩下3/10的零花钱（已是最简分数）。
Check: Add 3/10 (left) to 7/10 (spent): 7/10 + 3/10 = 10/10 = 1 whole. Correct. | 检验：用剩余3/10加上已花费7/10：7/10 + 3/10 = 10/10 = 1整体。无误。
5. Tackling Word Problems with the Framework | 用框架攻克文字题
Word problems often hide the given numbers inside a story. Your first job is to underline or list the key data. Then decide what operation to use. For instance, words like “altogether” or “increase” usually mean addition, while “difference” or “how many left” signal subtraction. Always write a simple statement to introduce your method.
文字题常常把已知数据藏在故事里。你的第一个任务是划出或列出关键数据。然后决定使用什么运算。例如，“总共”、“增加”通常表示加法，而“差”、“剩下多少”则提示减法。始终先写一句简短的话说明你的解题方法。
6. Algebraic Expressions: Laying Out Steps Logically | 代数表达式：有逻辑地安排步骤
When simplifying expressions like 3a + 2a + 7, show grouping clearly. Write: “Collect like terms: 3a + 2a = 5a, so the expression becomes 5a + 7.” For substitution, write: “When a = 4, 5a + 7 = 5 × 4 + 7 = 20 + 7 = 27.” Avoid cramming all working into one line—separate each transformation for clarity.
在化简如3a + 2a + 7这样的表达式时，要清楚展示合并同类项。写出：“合并同类项：3a + 2a = 5a，因此表达式变为5a + 7。” 代入求值时，写出：“当a = 4，5a + 7 = 5 × 4 + 7 = 20 + 7 = 27。” 避免把所有计算挤在一行——分开每一步变换才清晰。
7. Geometry Reasoning: Angles and Shapes | 几何推理：角与图形
In angle problems, always state the rule you are using. For example: “Angles on a straight line sum to 180°.” Then write the equation: x + 72 = 180, so x = 180 − 72 = 108°. This links your working to geometric facts and earns method marks. For shape properties, describe symmetry or side relationships in full sentences.
在角度题中，始终说明你使用的几何事实。例如：“直线上的角之和为180°。” 然后写下方程：x + 72 = 180，所以x = 180 − 72 = 108°。这能将你的计算与几何定理联系起来，并赢得步骤分。关于图形性质，要用完整的句子描述对称性或边的关系。
8. Common Mistakes to Avoid in Written Answers | 书面作答的常见错误
Skipping steps: Jumping from question to answer without showing working loses valuable marks. Missing units: Always include cm, m, kg, °, or £ as appropriate. No simplification: Leaving fractions such as 4/8 without simplifying to 1/2 can cost a mark. Illegible layout: If your numbers run into each other, the examiner may misread. Use a new line for each step.
跳过步骤：从题目直接跳到答案而不写过程会丢失宝贵的分数。遗漏单位：总是加上合适的单位，如cm、m、kg、°或£。未化简：把分数如4/8留着而不化简成1/2可能扣分。字迹/排版不清：如果数字挤在一起，阅卷官可能会看错。每步另起一行。
9. Practice Exercise: Build Your Own Answer | 练习：自己搭建答案
Question: A bag contains 24 sweets. Emma eats 1/3 of them and Ben eats 5/12 of the original amount. How many sweets are left? Write your answer using the five-part framework.
题目：一袋糖有24颗。Emma吃了其中的1/3，Ben吃了原来数量的5/12。还剩多少颗糖？请用五步框架写出答案。
Try this yourself before reading the model below. | 在阅读下方范文前请自己先尝试。
Given: Total sweets = 24. Emma eats 1/3 of 24. Ben eats 5/12 of 24.
Given (中文): 总糖数 = 24。Emma吃24的1/3。Ben吃24的5/12。
Strategy: Calculate the number of sweets each person eats using “fraction of amount = fraction × total”. Then subtract the eaten sweets from 24.
策略：用“某数的几分之几 = 分数 × 总数” 算出每人吃的颗数。再从24中减去吃掉的数量。
Working:
Emma: 1/3 × 24 = 24 ÷ 3 = 8 sweets.
Ben: 5/12 × 24 = (24 ÷ 12) × 5 = 2 × 5 = 10 sweets.
Total eaten = 8 + 10 = 18 sweets.
Sweets left = 24 − 18 = 6.
计算过程：
Emma：1/3 × 24 = 24 ÷ 3 = 8颗。
Ben：5/12 × 24 = (24 ÷ 12) × 5 = 2 × 5 = 10颗。
共吃掉 = 8 + 10 = 18颗。
剩余 = 24 − 18 = 6颗。
Answer: There are 6 sweets left.
答案：还剩6颗糖。
Check: Add the fractions eaten: 1/3 = 4/12, plus 5/12 equals 9/12 = 3/4 of the bag. Remaining fraction = 1/4. 1/4 of 24 = 6. Correct. ✓
检验：计算吃掉的比例之和：1/3 = 4/12，加上5/12等于9/12 = 3/4袋。剩余比例为1/4。24的1/4 = 6。正确。✓
10. Transitioning to Investigation–Style Questions | 向探究性问题过渡
Some Year 7 tasks may ask you to “investigate” or “explain why”. Use the same framework but expand the Strategy and Check sections into short paragraphs. For example, “I noticed a pattern when multiplying by 9: the digits of the product sum to 9. I will test this with three more examples.” Then present a table of results and write a concluding statement.
有些Year 7题目会要求你“探究”或“解释为什么”。使用同一框架，但把策略和检验部分扩展成小段落。例如：“我注意到乘以9时，乘积的数字之和为9。我将用三个例子验证。” 然后呈现一个结果表格，并写出总结性陈述。
11. Using the Framework in Timed Exams | 如何在限时考试中使用框架
You don’t have to write full sentences for every single step if time is short. Use abbreviations and bullet points while keeping the logical order. For instance, list Given as “L=12, W=8”, then write the formula, show substitution and final answer. The framework is flexible—it helps you remember to include all parts, not waste time.
如果时间紧张，你不必每一步都写完整句子。可以使用缩写和要点符号，但要保持逻辑顺序。例如，已知条件写为“L=12, W=8”，然后写下公式、代入和最终答案。框架是灵活的——它帮助你记得涵盖所有部分，而不会浪费时间。
12. Next Level: Peer Marking with the Framework | 进阶：用框架互评答案
Once you are comfortable, try marking a partner’s work using the five headings. Does their solution list the Given? Did they state a strategy? Check if each working step is correct and properly linked. This peer assessment skill improves your own accuracy and deepens your understanding of Edexcel mark schemes.
当你熟练后，可以尝试用这五个标题批改同伴的解答。他们的解答列出已知条件了吗？说明策略了吗？检查每一步计算是否正确且相互关联。这种互评技能能提高你自己的准确性，并加深对Edexcel评分标准的理解。
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