📚 Year 10 Eduqas Science: Case Study Practical Practice | 十年级 Eduqas 科学：案例分析实战演练
In Year 10 Eduqas Science, case studies connect classroom theory with real-world applications. You will encounter scenarios that require you to analyse data, draw conclusions, and evaluate methods — just like a working scientist. This article provides guided practice through four core case studies, covering biology, chemistry, and physics. By working through these examples, you will sharpen your data interpretation, calculation, and evaluation skills, all essential for both your practical assessments and written examinations.
在十年级 Eduqas 科学课程中，案例分析将课堂理论与实际应用紧密相连。你会遇到需要分析数据、得出结论并评估方法的场景——就像真正的科学家一样。本文通过四个核心案例（涵盖生物、化学和物理）为你提供引导式练习。通过演练这些实例，你将强化数据解读、计算和评估能力，这些都是实践考核和笔试所必需的关键技能。
1. Understanding Scientific Case Studies | 理解科学案例分析
Scientific case studies present a realistic situation together with collected data, often from an experiment or survey. Your job is to apply scientific knowledge to interpret findings, identify patterns, and critically assess the investigation. Unlike simple factual recall, case study questions test how you think like a scientist.
科学案例分析会呈现一个真实情境以及从实验或调查中收集的数据。你的任务是运用科学知识来解读发现、识别规律并批判性地评估研究过程。与简单的知识回忆不同，案例分析题考察的是你能否像科学家一样思考。
Eduqas exam papers regularly include case study questions worth 6–9 marks. Strong responses must describe trends, use data as evidence, link findings to scientific concepts, and suggest improvements. Common themes include ecosystems, pollution, energy resources, and human health.
Eduqas 试卷中常常包含分值为 6–9 分的案例分析题。高分答案需要描述变化趋势、用数据作为证据、把发现与科学概念联系起来，并提出改进建议。常见主题包括生态系统、污染、能源资源和人体健康。
2. Case Study 1: Investigating a Pond Ecosystem | 案例一：调查池塘生态系统
A biology field study was carried out to compare biodiversity in two zones of a pond: the sunlit littoral edge and the shaded central region. Students used a 0.5 m² quadrat to count organisms and recorded abiotic factors. The aim was to see whether light availability affects species distribution.
一项生物学实地研究比较了池塘两个区域的生物多样性：阳光充足的沿岸带和遮荫的中央区。学生使用 0.5 平方米样方计数生物，并记录非生物因子。目的是探究光照是否影响物种分布。
Abiotic data: littoral zone — light intensity 850 lux, temperature 18 °C, dissolved oxygen 8.2 mg/L; central zone — light intensity 120 lux, temperature 14 °C, dissolved oxygen 6.0 mg/L.
非生物数据：沿岸带——光照强度 850 lux，温度 18 °C，溶解氧 8.2 mg/L；中央区——光照强度 120 lux，温度 14 °C，溶解氧 6.0 mg/L。
| Species | Littoral zone count | Central zone count |
|---|---|---|
| Duckweed | 24 | 3 |
| Water flea (Daphnia) | 38 | 10 |
| Pond snail | 15 | 9 |
| Dragonfly nymph | 4 | 2 |
The data show higher organism counts in the littoral zone for all species, especially duckweed and water flea. Light availability fuels photosynthesis in plants like duckweed, which then provides food and oxygen for consumers. The lower dissolved oxygen in the shaded zone limits aerobic organisms.
数据显示，沿岸带所有物种的数量都更高，尤其是浮萍和水蚤。光照促进了浮萍等植物的光合作用，进而为消费者提供食物和氧气。遮荫区溶解氧较低，限制了需氧生物的生存。
3. Analysing Population Density | 分析种群密度
Population density can be calculated using the formula density = number of individuals ÷ area sampled. For the littoral zone duckweed: 24 ÷ 0.5 m² = 48 individuals per m². In the central zone the density is only 6 per m². This eightfold difference highlights how strongly light affects plant distribution.
种群密度可以用公式 密度 = 个体数量 ÷ 取样面积 计算。沿岸带浮萍：24 ÷ 0.5 m² = 48 个/㎡。中央区密度仅为 6 个/㎡。这八倍的差异突显了光照对植物分布的强烈影响。
When commenting on data, always refer to figures. For instance, ‘the mean number of water fleas per quadrat fell from 38 to 10, a 74% decrease, which correlates with a reduction in oxygen from 8.2 to 6.0 mg/L.’ Linking variables using quantitative evidence shows analysis skill.
在评论数据时，务必引用具体数字。例如，“每个样方的水蚤平均数从 38 降至 10，下降 74%，这与溶解氧从 8.2 降至 6.0 mg/L 相关。”用定量证据把变量联系起来，能体现分析能力。
4. Case Study 2: River Pollution and Eutrophication | 案例二：河流污染与富营养化
A chemical case study focused on a stream downstream from farmland. Scientists measured nitrate and phosphate concentrations at four sites, along with the percentage cover of algae. Their concern was whether fertiliser runoff was triggering eutrophication.
一个化学案例聚焦于农田下游的一条溪流。科学家在四个地点测量了硝酸盐和磷酸盐浓度，以及藻类覆盖百分比。他们关心的是肥料径流是否正在引发富营养化。
| Site | Nitrate (mg/L) | Phosphate (mg/L) | Algal cover (%) |
|---|---|---|---|
| 1 — upstream | 2.1 | 0.05 | 5 |
| 2 — adjacent to field | 15.4 | 0.48 | 62 |
| 3 — 500 m downstream | 9.8 | 0.31 | 41 |
| 4 — 2 km downstream | 4.3 | 0.12 | 18 |
The dramatic rise in nitrate and phosphate at Site 2 strongly suggests fertiliser runoff. Algal cover peaks at 62% here because the nutrients act as fertilisers for algae. As distance increases, nutrient levels fall due to dilution and uptake by plants.
二号地点的硝酸盐和磷酸盐大幅上升，强烈表明存在肥料径流。藻类覆盖率在此达到 62% 的峰值，因为这些营养物充当了藻类的肥料。随着距离增加，营养物水平因稀释和植物吸收而下降。
5. Interpreting Chemical Evidence | 解读化学证据
Eutrophication follows a predictable sequence: nutrient input → algal bloom → light blockage → death of submerged plants → decomposition by bacteria → oxygen depletion → death of aquatic animals. This case study provides direct evidence for the first three stages. Students should be able to predict that dissolved oxygen would be lowest soon after the algal bloom decays.
富营养化遵循可预测的顺序：营养物输入 → 藻华 → 光照阻挡 → 沉水植物死亡 → 细菌分解 → 氧气耗尽 → 水生动物死亡。本案例为前三阶段提供了直接证据。学生应能预测，在藻华分解后不久，溶解氧会降至最低。
A well-structured answer might state: ‘Nitrate concentration at Site 2 is over seven times the upstream baseline, strongly implying agricultural runoff. The corresponding 62% algal cover confirms a classic eutrophication response. To prove the link, further measurements of dissolved oxygen and BOD (biochemical oxygen demand) would be needed at night.’
一个结构清晰的回答可以这样写：“二号地点的硝酸盐浓度是上游基线的七倍多，强烈暗示农业径流。相应的 62% 藻类覆盖率证实了典型的富营养化反应。要证明这种联系，需要在夜间进一步测量溶解氧和生化需氧量 (BOD)。”
6. Case Study 3: Optimising Solar Panel Performance | 案例三：优化太阳能电池板性能
A physics investigation examined how the angle of incidence of light affects the power output of a small photovoltaic cell. Students kept a lamp at a fixed distance and tilted the cell from 0° (facing the lamp directly) to 75°. Voltage and current were recorded to calculate power: P = V × I.
一项物理探究考察了光的入射角如何影响小型光伏电池的功率输出。学生将灯保持在固定距离，并将电池从 0°（正对灯）倾斜到 75°。记录电压和电流以计算功率：P = V × I。
| Angle (°) | Voltage (V) | Current (A) | Power (W) |
|---|---|---|---|
| 0 | 2.40 | 0.18 | 0.432 |
| 15 | 2.38 | 0.18 | 0.428 |
| 30 | 2.29 | 0.17 | 0.389 |
| 45 | 2.10 | 0.16 | 0.336 |
| 60 | 1.76 | 0.14 | 0.246 |
| 75 | 1.10 | 0.10 | 0.110 |
The data reveal that power output is maximised when the cell faces the light source directly (0°). As the angle increases, less light energy strikes the cell surface per unit area, so both current and voltage decrease. This is a direct consequence of the reduced effective area capturing photons.
数据揭示，当电池直接面对光源 (0°) 时，功率输出最大。随着角度增大，单位面积上照射到电池表面的光能减少，因此电流和电压都下降。这是捕获光子的有效面积减小所带来的直接后果。
7. Efficiency Calculations in Context | 实际情境中的效率计算
Efficiency is a key concept. For the cell at 0°, the input light power was measured as 2.0 W. Using the equation:
效率是一个关键概念。对于 0° 的电池，测得的输入光功率为 2.0 W。使用方程式：
Efficiency = (useful power output / total power input) × 100%
效率 = (有用功率输出 / 总功率输入) × 100%
The calculation gives (0.432 / 2.0) × 100% = 21.6%. At 75° the efficiency falls to only 5.5%. This dramatic drop demonstrates why solar panels are often mounted on adjustable racks to track the Sun’s movement.
计算结果为 (0.432 / 2.0) × 100% = 21.6%。在 75° 时效率降至仅 5.5%。这种急剧下降说明了为什么太阳能电池板通常安装在可调节的支架上以追踪太阳的运动。
Case study questions may ask you to suggest improvements. Using a tracking system, cleaning the panel surface, or installing a lens to concentrate light would all raise efficiency.
案例分析题可能会要求你提出改进建议。使用追踪系统、清洁面板表面或安装透镜聚光都可以提高效率。
8. Case Study 4: Measuring Energy Content in Food | 案例四：测量食物中的能量含量
A classic calorimetry experiment compared the energy content of a crisp, a piece of bread, and a marshmallow. Each food sample was burned under a boiling tube containing 20 cm³ of water. The temperature rise was recorded to estimate energy released, using the specific heat capacity of water: 4.2 J/g°C.
一个经典的量热实验比较了薯片、一片面包和棉花糖的能量含量。每种食物样本在装有 20 cm³ 水的沸腾管下方燃烧。记录水温升高值，利用水的比热容 4.2 J/g°C 来估算释放的能量。
Energy transferred (J) = mass of water (g) × 4.2 × temperature rise (°C)
转移的能量 (J) = 水的质量 (g) × 4.2 × 温度升高值 (°C)
| Food | Mass burned (g) | Temp rise (°C) | Energy (J) | Energy per gram (J/g) |
|---|---|---|---|---|
| Crisp | 0.38 | 32.5 | 2730 | 7184 |
| Bread | 0.41 | 18.0 | 1512 | 3688 |
| Marshmallow | 0.33 | 14.2 | 1193 | 3615 |
The crisp gives the highest energy per gram, mainly due to its fat content. Fats store more energy per gram than carbohydrates. However, the experiment is known for large heat losses to the surroundings, so values are far below those on food labels. This is a critical evaluation point.
薯片每克提供的能量最高，这主要来自其脂肪含量。脂肪每克储存的能量比碳水化合物多。但众所周知，该实验向周围环境散失了大量的热，因此数值远低于食品标签上的数据。这是一个关键的评估要点。
9. Data Skills: Graphs, Trends and Anomalies | 数据技能：图表、变化趋势与异常值
Plotting graphs correctly is essential. The independent variable (e.g. angle, site) goes on the x-axis, the dependent variable (e.g. power, algal cover) on the y-axis. Always label axes with quantities and units, and use sensible scales. For the solar data, a line graph with a smooth curve is appropriate; for algal cover, a bar chart would work well.
正确绘制图表至关重要。自变量（如角度、地点）放在 x 轴，因变量（如功率、藻类覆盖率）放在 y 轴。务必用物理量和单位标注坐标轴，并使用合理的刻度。对于太阳能数据，带有平滑曲线的折线图是合适的；对于藻类覆盖率，柱状图效果很好。
Anomalies are data points that do not fit the overall pattern. Suppose the voltage reading at 30° was recorded as 1.60 V instead of 2.29 V. This should be circled on the graph and repeated if possible. Anomalies can arise from misreading meters, poor connections, or environmental fluctuations.
异常值是指与整体规律不符的数据点。假设 30° 的电压读数被记录为 1.60 V 而非 2.29 V。这应该在图上圈出，并在可能的情况下重做。异常值可能源于读数错误、连接不良或环境波动。
| Common graphing mistake | How to avoid it |
|---|---|
| Uneven scale | Use multiples of 1, 2, 5 or 10 evenly across the axis |
| Forgetting units | Write ‘Temperature/°C’ or ‘Power/W’ after the label |
| Dot-to-dot for curved data | Draw a smooth curve or line of best fit |
中文对应：常见的绘图错误有刻度不均匀、忘记标单位、弯曲数据仍用点对点连线。避免方法：轴刻度均匀使用 1, 2, 5 或 10 的倍数；标签后写单位如 ‘温度/°C’；绘制平滑曲线或最佳拟合线。
10. Evaluation: Limitations and Improvements | 评估：局限性与改进
Every investigation has limitations. In the pond study, quadrat throws may not have been truly random, and some organisms might have been missed due to their small size or mobility. To improve, students could use a random number generator for coordinates and take more replicates.
每项调查都有局限性。在池塘研究中，样方抛掷可能并非真正随机，而且一些生物因体型小或移动性强可能被遗漏。改进方法是可以使用随机数生成器确定坐标，并增加重复次数。
In the calorimetry case, major heat loss to the air and the apparatus is the chief limitation. Using a draught shield, insulating the boiling tube, and stirring the water would improve results. Additionally, burning the food in pure oxygen, as in a bomb calorimeter, gives near-perfect capture, but such equipment is not available in most schools.
在量热案例中，向空气和装置的大量热损失是主要局限。使用挡风屏、给沸腾管隔热并搅拌水可以改善结果。此外，在纯氧中燃烧食物（如弹式量热计）几乎可以完全捕获热量，但大多数学校不具备此类设备。
When evaluating, state the limitation, explain its impact on the result (e.g. ’causes the calculated energy to be an underestimate’), and propose a specific, practical improvement.
评估时，要先说明局限性，解释它对结果的影响（例如“导致计算出的能量偏低”），然后提出具体、可行的改进方案。
11. Communicating Scientific Findings | 传达科学发现
In the exam, you may be asked to write a short conclusion or a plan for a peer. Use clear, concise language and back every claim with data. For instance, ‘The investigation supports the hypothesis because the crisp demonstrated the highest energy per gram (7184 J/g), which is consistent with its high fat content.’
在考试中，可能会要求你写出简短结论或给同伴的计划。要使用清晰、简洁的语言，并用数据支持每一个主张。例如，“该研究支持假设，因为薯片表现出最高的每克能量 (7184 J/g)，这与其高脂肪含量一致。”
Risk assessments are also part of communication. For calorimetry, hazards include burning food, hot equipment, and sharp objects. Precautionary steps — tie back hair, wear goggles, use heatproof mats — should be explicitly stated.
风险评估也是沟通的一部分。对量热实验而言，危险包括燃烧的食物、热设备和尖锐物体。预防措施——束好头发、佩戴护目镜、使用隔热垫——应明确说明。
12. Exam Tips for Case Study Questions | 考试中案例题的应对技巧
Start by scanning the data table or graph: note the highest and lowest values and any outlier. Then read the question carefully; often it will guide you with command words like ‘describe’, ‘explain’, ‘calculate’, or ‘evaluate’. ‘Describe’ requires you to say what the data shows; ‘explain’ demands scientific reasoning; ‘evaluate’ asks for both strengths and weaknesses.
首先快速浏览数据表格或图表：记下最高值和最低值以及任何异常点。然后仔细读题；题目通常会通过指令词提示你，如“描述”、“解释”、“计算”或“评估”。“描述”要求说出数据呈现的状况；“解释”需要科学推理；“评估”则要求分析优缺点。
When a 6-mark evaluation question appears, use the following structure: one mark for a clear conclusion linked to the data, two marks for outlining the trend with quoted figures, two marks for identifying limitations and their effects, and one mark for realistic improvements. Practice this framework with the case studies above.
当出现 6 分评估题时，可采用以下结构：1 分用于给出与数据相关的清晰结论，2 分用于引用数字概述趋势，2 分用于指出局限性及其影响，1 分用于提出实际的改进方案。用上述案例反复练习这一框架。
Finally, manage your time: a 6-mark question deserves about 8–10 minutes.
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