Year 12 Edexcel Further Mathematics: Key Concepts Review | Year 12 Edexcel 进阶数学：核心知识点梳理

📚 Year 12 Edexcel Further Mathematics: Key Concepts Review | Year 12 Edexcel 进阶数学：核心知识点梳理

This article summarises the essential topics for the AS-Level Further Mathematics course under Edexcel. Students studying Core Pure Mathematics 1 will find a concise review of key concepts, including complex numbers, series, matrices, vectors and more, with practical tips for exam success.

本文梳理了 Edexcel 考试局 AS 阶段进阶数学的核心知识点，涵盖复数、级数、矩阵、向量等内容，帮助 Year 12 学生系统巩固 Core Pure Mathematics 1 的重点与应试技巧。

1. Complex Numbers | 复数

Complex numbers are of the form z = a + bi, where a, b ∈ R and i² = −1. The real part is a, the imaginary part is b. Pure imaginary numbers have a = 0.

复数具有形式 z = a + bi，其中 a, b 为实数，i 是虚数单位且 i² = −1。a 称为实部，b 为虚部。当 a = 0 时为纯虚数。

Addition and multiplication follow normal algebra with i² replaced by −1. The complex conjugate z* = a − bi allows division: multiply numerator and denominator by the conjugate of the denominator.

加减乘法遵循代数规则，将 i² 换为 −1。共轭复数 z* = a − bi 用于除法：分子分母同乘分母的共轭。

The modulus |z| = √(a² + b²) gives the distance from the origin. The argument arg(z) = θ, where tanθ = b/a (care with quadrant). Modulus-argument form: z = r(cosθ + i sinθ) with r = |z|. Multiplication in this form: multiply moduli, add arguments.

模长 |z| = √(a² + b²) 表示到原点的距离；辐角 arg(z) = θ 满足 tanθ = b/a（注意象限）。模-辐角形式：z = r(cosθ + i sinθ)，其中 r = |z|。用此形式乘除：模长相乘、辐角相加。

2. Argand Diagrams and de Moivre | 阿尔冈图与棣莫弗定理

An Argand diagram plots the real part on the horizontal axis and the imaginary part on the vertical axis. Loci: |z − a| = r is a circle centre at complex number a, radius r. arg(z − a) = θ is a half‑line from a at angle θ. |z − a| = |z − b| is the perpendicular bisector of a and b.

阿尔冈图以横轴为实部、纵轴为虚部。轨迹：|z − a| = r 表示圆心在 a、半径为 r 的圆；arg(z − a) = θ 表示从 a 出发、与正实轴夹角为 θ 的射线；|z − a| = |z − b| 是 a 与 b 连线的垂直平分线。

de Moivre’s theorem: (cosθ + i sinθ)ⁿ = cos nθ + i sin nθ for integer n. It is used to derive multiple‑angle trig identities and to find powers and roots of complex numbers.

棣莫弗定理：对整数 n，有 (cosθ + i sinθ)ⁿ = cos nθ + i sin nθ。常用于推导倍角三角恒等式以及计算复数的幂与根。

Roots of unity: solutions of zⁿ = 1 are z = e^(2πik/n) = cos(2πk/n) + i sin(2πk/n) for k = 0,1,…,n−1. These points lie evenly on the unit circle. For example, the cube roots of unity are 1, ω = e^(2πi/3), ω² = e^(4πi/3), and 1 + ω + ω² = 0.

单位根：zⁿ = 1 的解为 z = cos(2πk/n) + i sin(2πk/n)，k = 0,1,…,n−1，均匀分布在单位圆上。例如三次单位根 1, ω, ω² 满足 1 + ω + ω² = 0。

3. Series | 级数

Standard sums are essential: Σₖ₌₁ⁿ k = ½ n(n+1), Σₖ₌₁ⁿ k² = ⅙ n(n+1)(2n+1), Σₖ₌₁ⁿ k³ = ¼ n²(n+1)². These underpin the method of differences and Maclaurin expansions.

标准求和公式必须熟记：Σₖ₌₁ⁿ k = ½ n(n+1)，Σₖ₌₁ⁿ k² = ⅙ n(n+1)(2n+1)，Σₖ₌₁ⁿ k³ = ¼ n²(n+1)²，是裂项相消法和麦克劳林展开的基础。

Method of differences: rewrite the general term as uᵣ = f(r) − f(r+1). Then Σᵣ₌₁ⁿ uᵣ telescopes to f(1) − f(n+1), simplifying evaluation.

裂项相消法：将通项写成 uᵣ = f(r) − f(r+1)，则求和结果为 f(1) − f(n+1)，大量项抵消。

Maclaurin series: f(x) = f(0) + f'(0)x + f”(0)x²/2! + f”'(0)x³/3! + … Key expansions: eˣ = 1 + x + x²/2! + x³/3! + …; sin x = x − x³/3! + x⁵/5! − …; cos x = 1 − x²/2! + x⁴/4! − …; ln(1+x) = x − x²/2 + x³/3 − … (valid for −1 < x ≤ 1).

麦克劳林展开：f(x) = f(0) + f'(0)x + f”(0)x²/2! + f”'(0)x³/3! + …。核心展开：eˣ = 1 + x + x²/2! + …；sin x = x − x³/3! + x⁵/5! − …；cos x = 1 − x²/2! + x⁴/4! − …；ln(1+x) = x − x²/2 + x³/3 − …（−1 < x ≤ 1）。

4. Roots of Polynomials | 多项式根的关系

For quadratic ax² + bx + c = 0 with roots α, β: α + β = −b/a, αβ = c/a. This yields identities like α² + β² = (α+β)² − 2αβ.

二次方程 ax² + bx + c = 0 的根 α, β 满足：α + β = −b/a，αβ = c/a。由此可得 α² + β² = (α+β)² − 2αβ 等恒等式。

For cubic ax³ + bx² + cx + d = 0: Σα = α+β+γ = −b/a, Σαβ = αβ+βγ+γα = c/a, αβγ = −d/a. Similar symmetric sums exist for quartics.

三次方程 ax³ + bx² + cx + d = 0：Σα = α+β+γ = −b/a，Σαβ = αβ+βγ+γα = c/a，αβγ = −d/a。四次方程也有类似对称和。

These relations help form new equations whose roots are, for example, 1/α, kα or α². Replace x appropriately and use symmetric sums

Published by TutorHao | Year 12 进阶数学 Revision Series | aleveler.com

更多咨询请联系16621398022（同微信）