Calculating the Enthalpy Change of Hydration of an Anhydrous Salt | 计算无水盐的水合焓变

📚 Calculating the Enthalpy Change of Hydration of an Anhydrous Salt | 计算无水盐的水合焓变

The hydration of an anhydrous salt is one of those wonderfully instructive topics in A-Level energetics. It draws together Hess’s law, simple calorimetry, and the concept of enthalpy cycles. Understanding how to determine the enthalpy change when a dry salt takes up water of crystallisation is not only a key practical skill but also a doorway into the broader energetics of ionic substances.

无水盐的水合是A-Level热力学中一个极具启发性的主题。它综合了赫斯定律、简易量热法和焓循环的概念。理解如何测定干燥盐吸收结晶水时的焓变,不仅是一项关键的实验技能,也是通往离子物质更广泛能量学的大门。


1. What Is the Enthalpy of Hydration of an Anhydrous Salt? | 什么是无水盐的水合焓?

When an anhydrous salt combines directly with water molecules to form a solid hydrated crystal, the enthalpy change for that transformation is known as the enthalpy change of hydration of the anhydrous salt. A classic example is the reaction of white anhydrous copper(II) sulfate with water to give blue copper(II) sulfate pentahydrate: CuSO₄(s) + 5H₂O(l) → CuSO₄·5H₂O(s). This process is energetically favourable (exothermic) because strong ion–dipole interactions are established as water molecules coordinate to the cation and anion.

当无水盐直接与水分子结合生成固态水合晶体时,该转变的焓变就称为无水盐的水合焓变。一个经典例子是白色无水硫酸铜与水反应生成蓝色五水合硫酸铜:CuSO₄(s) + 5H₂O(l) → CuSO₄·5H₂O(s)。这一过程在能量上是有利的(放热),因为水分子与阳离子和阴离子配位时建立了强烈的离子-偶极相互作用。

Unfortunately, this direct reaction is rarely clean enough for a one‑step calorimetric determination. The solid often clumps, the reaction is slow, and it is difficult to ensure complete conversion. Instead, we turn to an indirect method based on Hess’s law.

遗憾的是,该直接反应很少能干净到可用一步量热法测定。固体常常结块,反应缓慢,且难以确保转化完全。因此,我们转向基于赫斯定律的间接方法。


2. Anhydrous versus Hydrated Salts | 无水盐与水合盐的对比

An anhydrous salt contains no water of crystallisation. It is often obtained by gently heating its hydrated form until the water is driven off. The hydrated salt, by contrast, contains a fixed number of water molecules per formula unit that are incorporated into the crystal lattice. The two forms have markedly different properties – most obviously their colour, as seen with CuSO₄ (white) and CuSO₄·5H₂O (blue), or CoCl₂ (blue) and CoCl₂·6H₂O (pink).

无水盐不含结晶水,通常可通过温和加热其水合形式驱除水分而得到。相反,水合盐每个化学式含有固定数目的水分子,这些水分子被结合在晶格中。两种形式具有明显不同的性质,最显著的是颜色:如CuSO₄(白色)和CuSO₄·5H₂O(蓝色),或CoCl₂(蓝色)与CoCl₂·6H₂O(粉红色)。

In thermochemical equations, it is vital to include the dot notation and the correct number of water molecules, e.g. Na₂CO₃·10H₂O, MgSO₄·7H₂O. The water molecules are written as part of the solid formula, not as free water.

在热化学方程式中,必须包括点符号和正确的水分子数目,如Na₂CO₃·10H₂O、MgSO₄·7H₂O。水分子被写作固体化学式的一部分,而不是自由水。


3. Hess’s Law – The Theoretical Foundation | 赫斯定律——理论基础

Hess’s law states that the total enthalpy change for a chemical reaction is independent of the route taken, provided the initial and final conditions are the same. This allows us to construct an energy cycle in which the unknown hydration enthalpy is linked to two measurable enthalpy changes – the enthalpies of solution of the anhydrous and the hydrated salts.

赫斯定律指出,只要始态和终态相同,化学反应的总焓变与所采取的路径无关。这使得我们可以构建一个能量循环,将未知的水合焓与两个可测量的焓变——无水盐和水合盐的溶解焓——联系起来。

Because both the anhydrous salt and its hydrated form dissolve to give the same aqueous ions, the difference between their solution enthalpies must equal the enthalpy of hydration of the anhydrous salt.

由于无水盐及其水合形式溶解后都生成相同的水合离子,二者溶解焓的差值必定等于无水盐的水合焓。


4. Defining Enthalpy of Solution | 溶解焓的定义

The standard enthalpy of solution, ΔHsol°, is the enthalpy change when one mole of a substance dissolves in a large excess of water to form an infinitely dilute solution. For an ionic salt, this involves breaking the ionic lattice and hydrating the separated ions.

标准溶解焓ΔHsol°是指一摩尔物质溶解在大量过量的水中形成无限稀释溶液时的焓变。对离子盐而言,这涉及破坏离子晶格并水合分离开的离子。

For the anhydrous salt: MX(s) + aq → M⁺(aq) + X⁻(aq) ΔHsol(anhydrous). For the hydrated salt: MX·nH₂O(s) + aq → M⁺(aq) + X⁻(aq) + nH₂O(l) ΔHsol(hydrated). Notice that in the second process, the n water molecules that were part of the solid simply become part of the solvent.

对无水盐:MX(s) + aq → M⁺(aq) + X⁻(aq) ΔHsol(无水)。对水合盐:MX·nH₂O(s) + aq → M⁺(aq) + X⁻(aq) + nH₂O(l) ΔHsol(水合)。注意在第二个过程中,原本属于固体的n个水分子变成了溶剂的一部分。

These two ΔHsol values can be determined experimentally by simple solution calorimetry, making them the key to unlocking the unknown hydration enthalpy.

这两个ΔHsol值可通过简单的溶液量热法实验测定,因而成为解开未知水合焓的关键。


5. Constructing the Hess Cycle for Hydration | 构建水合赫斯循环

We can represent the relationship with the following cycle:

我们可以用下面的循环来表示该关系:

  • Route A (direct hydration): Anhydrous salt + nH₂O(l) → Hydrated salt ΔHhyd
  • Route B (via solution): Anhydrous salt + nH₂O(l) → Ions in solution → Hydrated salt
  • 路径A(直接水合):无水盐 + nH₂O(l) → 水合盐 ΔHhyd
  • 路径B(经溶液):无水盐 + nH₂O(l) → 溶液中的离子 → 水合盐

The enthalpy change for Route B is the enthalpy of solution of the anhydrous salt, ΔHsol(anhydrous). The reverse of the solution process of the hydrated salt gives: Ions in solution → Hydrated salt + water, which has an enthalpy change of –ΔHsol(hydrated). Applying Hess’s law:

路径B的焓变是无水盐的溶解焓ΔHsol(无水)。水合盐溶解过程的逆过程为:溶液中的离子 → 水合盐 + 水,其焓变为–ΔHsol(水合)。应用赫斯定律:

ΔHhyd = ΔHsol(anhydrous) – ΔHsol(hydrated)

It is essential to keep track of the signs: if dissolving the anhydrous salt is exothermic (negative) and dissolving the hydrated salt is endothermic (positive), the hydration enthalpy becomes more negative (more exothermic), which is often the case.

必须注意符号:如果无水盐溶解是放热的(负值),而水合盐溶解是吸热的(正值),那么水合焓将变得更负(更放热),这正是常见的情况。


6. Calorimetric Measurement of Enthalpy of Solution | 溶解焓的量热法测量

The apparatus is simple: a polystyrene cup (as a calorimeter), a lid, a thermometer (0.1 °C resolution), a measuring cylinder, a balance, and a stirring rod. The procedure for each salt is:

装置很简单:一个聚苯乙烯杯(作为量热器)、盖子、温度计(精度0.1 °C)、量筒、天平和搅拌棒。每种盐的操作步骤如下:

  • Measure a known mass of distilled water (e.g. 50.0 g) into the polystyrene cup and record its initial temperature for several minutes to establish a steady baseline.
  • Weigh a sample of the salt (around 2–5 g) accurately, recording the mass.
  • Quickly add the salt to the water, replace the lid, and stir continuously.
  • Record the temperature every 30 seconds until a maximum (for exothermic dissolution) or minimum (for endothermic dissolution) is reached.
  • Extrapolate the cooling or warming curve to the time of mixing to compensate for heat exchange with the surroundings.

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