IGCSE WJEC Engineering: Interdisciplinary Integrated Question Training | IGCSE WJEC 工程：跨学科综合题型训练

📚 IGCSE WJEC Engineering: Interdisciplinary Integrated Question Training | IGCSE WJEC 工程：跨学科综合题型训练

WJEC IGCSE Engineering papers often combine mechanics, materials, electronics, manufacturing and energy into one scenario. A single question may ask you to select a material, calculate stress, choose a gear ratio, estimate power use and justify a production method. This article gives you a structured way to train these integrated questions.

WJEC IGCSE 工程试卷经常把机械、材料、电子、制造和能源组合到一个情境中。一道题可能要求你选择材料、计算应力、选择齿轮比、估算功耗并说明生产工艺。本文将为你提供一套训练这类综合题的结构化方法。

1. What Makes a WJEC Integrated Question Different? | 什么是 WJEC 综合题？

Integrated questions usually begin with a design brief such as ‘A charity needs a low-cost lifting device for wheelchair users.’ You must extract numbers, identify the relevant systems, and show clear working rather than only giving a final answer.

综合题通常从一个设计任务书开始，例如‘某慈善机构需要一种面向轮椅使用者的低成本举升装置’。你必须提取数据、识别相关系统，并展示清晰的步骤，而不能只写最终答案。

WJEC examiners reward method marks, so a correct substitution with a unit conversion often gains more marks than a rushed final number. The most common integrated contexts are lifting, sorting, safety interlocks, automated gates and small production machines.

WJEC 考官会奖励步骤分，因此正确代入公式并完成单位换算往往比匆忙写出最终答案得分更高。最常见的综合情境包括举升、分拣、安全联锁、自动门和小型生产机器。

• Interpreting a product specification from the brief
• Selecting materials and manufacturing processes
• Performing mechanical, electrical or energy calculations
• Considering safety, cost and environmental impact

• 从任务书中解读产品规格
• 选择材料和制造工艺
• 进行机械、电气或能量计算
• 考虑安全、成本和环境影响

2. Materials, Stress and Factor of Safety | 材料、应力与安全系数

In a lifting hook question, you are usually given load F and a rod diameter d. The first step is to calculate the cross-sectional area A. For a circular rod:

在吊钩类题目中，通常会给出载荷 F 和圆杆直径 d。第一步是计算横截面积 A。对于圆杆：

A = πd² ÷ 4

Then calculate direct stress σ = F ÷ A. Finally compare the working stress with the ultimate tensile strength, UTS, using the factor of safety.

然后计算正应力 σ = F ÷ A。最后利用安全系数将工作应力与极限抗拉强度 UTS 进行比较。

σ = F ÷ A   |   FoS = UTS ÷ σ_working

Worked example: A steel rod of diameter 10 mm carries 15 kN. UTS is 400 MPa. Find stress and factor of safety. A = π × 10² ÷ 4 = 78.5 mm². Convert to m

Published by TutorHao | IGCSE 工程 Revision Series | aleveler.com

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