Quadratic Equations and Functions | 二次方程与函数

📚 Quadratic Equations and Functions | 二次方程与函数

Quadratic equations and functions are a central topic in IGCSE Mathematics. They connect algebra, graphs, and problem-solving, appearing in both Paper 2 and Paper 4. Mastering this topic builds confidence for higher-level studies and helps you secure crucial marks.

二次方程与函数是IGCSE数学的核心内容。它们将代数、图像和问题解决联系起来,出现在Paper 2和Paper 4中。掌握这一主题能增强你继续深入学习的信心,并帮助你在考试中拿下关键分数。


1. Standard Form of a Quadratic Equation | 二次方程的标准形式

A quadratic equation in one variable can be written in the form ax² + bx + c = 0, where a, b, and c are real numbers, and a ≠ 0. The coefficient a determines the shape of the parabola, while b and c affect its position.

含一个未知数的二次方程可以写成 ax² + bx + c = 0 的形式,其中 a、b、c 是实数,且 a ≠ 0。系数 a 决定抛物线的形状,而 b 和 c 影响其位置。

For example, in the equation 3x² − 5x + 2 = 0, we have a = 3, b = −5, and c = 2.

例如,在方程 3x² − 5x + 2 = 0 中,a = 3,b = −5,c = 2。

If a = 0, the equation becomes linear, which is a different type of problem. Therefore, a quadratic equation must always include an x² term.

如果 a = 0,方程就变成线性方程,那是另一类问题。因此,二次方程必须始终包含 x² 项。


2. Solving by Factorisation | 用因式分解法求解

Factorisation is often the quickest method when the quadratic expression can be written as a product of two linear factors. For example, x² + 7x + 12 = 0 can be factored as (x + 3)(x + 4) = 0.

当二次表达式可以写成两个一次因式的乘积时,因式分解法通常是最快的方法。例如,x² + 7x + 12 = 0 可以分解为 (x + 3)(x + 4) = 0。

Using the zero product property, if (x + 3)(x + 4) = 0, then x + 3 = 0 or x + 4 = 0. Thus x = −3 or x = −4.

利用零积性质,如果 (x + 3)(x + 4) = 0,那么 x + 3 = 0 或 x + 4 = 0。因此 x = −3 或 x = −4。

To factorise ax² + bx + c, look for two numbers that multiply to give ac and add to give b. For x² + 7x + 12, the numbers 3 and 4 multiply to 12 and add to 7.

要分解 ax² + bx + c,需要找到两个数,它们相乘等于 ac,相加等于 b。对于 x² + 7x + 12,3 和 4 相乘为 12,相加为 7。

  • Check if the expression can be factored before trying other methods.
  • Be careful with signs when b or c is negative.
  • Always expand your factors to verify correctness.
  • 在尝试其他方法之前,先检查表达式是否可分解。
  • 当 b 或 c 为负数时,要特别注意符号。
  • 始终展开因式验证正确性。

3. Solving by Completing the Square | 用配方法求解

Completing the square rewrites x² + bx as (x + b/2)² − (b/2)². This is useful when factorisation is not obvious or when the quadratic has irrational roots.

配方法将 x² + bx 改写为 (x + b/2)² − (b/2)²。当因式分解不明显或二次方程有无理根时,这种方法很有用。

For example, solve x² + 6x + 1 = 0. First, write x² + 6x as (x + 3)² − 9. Then the equation becomes (x + 3)² − 9 + 1 = 0, so (x + 3)² = 8.

例如,解 x² + 6x + 1 = 0。首先,将 x² + 6x 写成 (x + 3)² − 9。然后方程变为 (x + 3)² − 9 + 1 = 0,所以 (x + 3)² = 8。

Taking square roots gives x + 3 = ±√8, so x = −3 ± 2√2.

两边开平方得 x + 3 = ±√8,所以 x = −3 ± 2√2。

(x + b/2)² = x² + bx + (b/2)²

The general form for completing the square is x² + bx + c = (x + p)² + q, where p = b/2 and q = c − p².

配方法的一般形式为 x² + bx + c = (x + p)² + q,其中 p = b/2,q = c − p²。


4. The Quadratic Formula | 二次公式

The quadratic formula solves any quadratic equation ax² + bx + c = 0 directly. It is especially useful when factorisation fails or when the coefficients are difficult to handle.

二次公式可以直接求解任意二次方程 ax² + bx + c = 0。当因式分解失败或系数难以处理时,它尤其有用。

x = (−b ± √(b² − 4ac)) / (2a)

To use the formula, substitute the values of a, b, and c into the equation. Simplify carefully, especially the square root and the sign of b.

使用公式时,将 a、b、c 的值代入方程即可。要小心化简,特别是根号和 b 的符号。

For example, solve 2x² − 4x − 3 = 0. Here a = 2, b = −4, c = −3. Therefore, x = (4 ± √(16 + 24)) / 4 = (4 ± √40) / 4 = (2 ± √10) / 2.

例如,解 2x² − 4x − 3 = 0。这里 a = 2,b = −4,c = −3。因此,x = (4 ± √(16 + 24)) / 4 = (4 ± √40) / 4 = (2 ± √10) / 2。

Always check the discriminant first, because a negative value means no real roots.

先检查判别式,因为如果判别式为负,则没有实数根。


5. The Discriminant and the Nature of Roots | 判别式与根的性质

The discriminant, Δ = b² − 4ac, tells us how many real roots a quadratic equation has. It appears inside the square root of the quadratic formula.

判别式 Δ = b² − 4ac 告诉我们二次方程有多少个实数根。它出现在二次公式的根号内。

Δ > 0 Two distinct real roots
Δ = 0 One repeated real root
Δ < 0 No real roots
Δ > 0 两个不同实数根
Δ = 0 一个重复实数根
Δ < 0 没有实数根

If Δ is a perfect square, the roots are rational; otherwise, they are irrational. This information helps you decide which solving method to use.

如果 Δ 是完全平方数,根是有理数;否则是无理数。这个信息能帮助你决定使用哪种求解方法。


6. Sum and Product of Roots | 根的和与积

For a quadratic equation ax² + bx + c = 0 with roots α and β, the sum of roots is α + β = −b/a, and the product is αβ = c/a.

对于根为 α 和 β 的二次方程 ax² + bx + c = 0,根之和为 α + β = −b/a,根之积为 αβ = c/a。

α + β = −b/a, αβ = c/a

This relationship is useful for forming quadratic equations from given roots without solving the original equation.

这个关系在已知根的情况下构造二次方程时非常有用,无需解原方程。

For instance, if a quadratic equation has roots 2 and 5, then the sum is 7 and the product is 10. Therefore, the equation is x² − 7x + 10 = 0.

例如,如果某二次方程的根是 2 和 5,那么和为 7,积为 10。因此,方程为 x² − 7x + 10 = 0。


7. Quadratic Functions and Their Graphs | 二次函数与图像

The graph of a quadratic function y = ax² + bx + c is a parabola. If a > 0, it opens upwards and has a minimum point; if a < 0, it opens downwards and has a maximum point.

二次函数 y = ax² + bx + c 的图像是一条抛物线。如果 a > 0,抛物线开口向上,有最小值点;如果 a < 0,抛物线开口向下,有最大值点。

The vertex of the parabola is the turning point. Its x-coordinate is given by x = −b/(2a). The y-coordinate is found by substituting this x-value into the function.

抛物线的顶点是转向点。其 x 坐标由 x = −b/(2a) 给出。y 坐标通过将该 x 值代入函数求得。

The axis of symmetry is the vertical line through the vertex, with equation x = −b/(2a).

对称轴是通过顶点的竖直线,方程为 x = −b/(2a)。


8. Sketching Quadratic Graphs | 绘制二次函数图像

To sketch a quadratic graph accurately, you need to find three key features: the roots, the vertex, and the y-intercept. These points define the overall shape.

要准确绘制二次函数图像,需要找到三个关键特征:根、顶点和 y 截距。这些点决定整体形状。

  • Find the roots by solving y = 0, which gives the x-intercepts.
  • Find the y-intercept by setting x = 0.
  • Find the vertex using x = −b/(2a).
  • 通过解 y = 0 求根,即可得到 x 截距。
  • 通过令 x = 0 求 y 截距。
  • 使用 x = −b/(2a) 求顶点。

Plot these points on a coordinate grid, then draw a smooth curve through them. Make sure the curve shows the correct minimum or maximum point.

在坐标网格上标出这些点,然后画一条平滑曲线穿过它们。确保曲线显示出正确的最小值点或最大值点。


9. Solving Quadratic Inequalities | 二次不等式的求解

Quadratic inequalities involve expressions such as x² − x − 6 > 0. To solve them, first find the roots of the corresponding equation, then test intervals on a number line.

二次不等式涉及如 x² − x − 6 > 0 的表达式。要解这类不等式,首先求对应方程的根,然后在数轴上测试区间。

For x² − x − 6 > 0, the roots are x = 3 and x = −2. The quadratic is positive when x < −2 or x > 3, because the graph opens upwards.

对于 x² − x − 6 > 0,根为 x = 3 和 x = −2。由于图像开口向上,该二次式在 x < −2 或 x > 3 时为正。

Therefore, the solution set is x ≤ −2 or x ≥ 3, depending on whether the inequality is strict.

因此,解集为 x ≤ −2 或 x ≥ 3,具体取决于不等式是否为严格不等式。


10. Applications of Quadratics | 二次方程的应用

Quadratic equations model many real-life situations, such as projectile motion, area optimisation, and profit calculations. In these problems, we often need to interpret the meaningful root.

二次方程可以模拟许多现实情境,如抛体运动、面积优化和利润计算。在这些问题中,我们通常需要解释有意义的根。

For example, a rectangle has area 24 m² and its length is 2 m longer than its width. If the width is x, then x(x + 2) = 24, which gives x² + 2x − 24 = 0.

例如,一个矩形面积为 24 m²,其长比宽长 2 m。如果宽为 x,则 x(x + 2) = 24,即 x² + 2x − 24 = 0。

Solving this gives x = 4 or x = −6. Since width cannot be negative, the width is 4 m and the length is 6 m.

求解得 x = 4 或 x = −6。由于宽不能为负,所以宽为 4 m,长为 6 m。


11. Common Mistakes and Exam Tips | 常见错误与考试技巧

Many students lose marks by making simple errors. Always rewrite the equation in the form ax² + bx + c = 0 before solving.

许多学生因为简单错误而失分。求解前,一定要将方程改写为 ax² + bx + c = 0 的形式。

  • Do not forget that a negative discriminant means no real roots.
  • Check your factoring by expanding.
  • When using the quadratic formula, be careful with negative signs.
  • In word problems, reject negative or impossible answers.
  • 不要忘记判别式为负意味着没有实数根。
  • 通过展开来检查你的因式分解。
  • 使用二次公式时,注意负号的处理。
  • 在应用题中,舍弃负数或不可能的解。

Practice drawing parabolas and solving equations until the methods become automatic. This will save you time in the exam.

多练习绘制抛物线和求解方程,直到这些方法变得熟练。这将帮助你在考试中节省时间。


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