Solving Quadratic Equations | 解一元二次方程

📚 Solving Quadratic Equations | 解一元二次方程

A quadratic equation is an equation of the form ax² + bx + c = 0, where a, b and c are constants and a ≠ 0. Quadratics appear in nearly every IGCSE Mathematics paper — either as a direct question or as a hidden step in geometry, sequences and problem-solving contexts. This guide will take you through expansion and factorisation, the three standard solving methods, the discriminant and exam-style applications, with bilingual explanations to make every step clear.

一元二次方程是指形如 ax² + bx + c = 0(其中 a、b、c 为常数且 a ≠ 0)的方程。二次函数几乎出现在每份 IGCSE 数学试卷中——无论是直接考查,还是作为几何、数列和实际问题中的隐含步骤。本指南将带你复习展开与因式分解,掌握三种标准解法、判别式以及考试风格的应用题,并配以中英双语讲解,确保每一步都清晰易懂。


1. Expanding Double Brackets | 展开二项式括号

Before solving quadratics, you must be comfortable expanding and factorising. To expand (x + p)(x + q), multiply each term in the first bracket by each term in the second. The acronym FOIL (First, Outer, Inner, Last) helps you remember the order. For example:

在解一元二次方程之前,你必须熟练掌握展开与因式分解。要展开 (x + p)(x + q),需要用第一个括号中的每一项去乘第二个括号中的每一项。首外内尾(FOIL)口诀可以帮助你记住顺序。例如:

(x + 3)(x + 5) = x² + 5x + 3x + 15 = x² + 8x + 15

Notice that the coefficient of x is the sum of 3 and 5, and the constant term is their product. This pattern leads directly to factorisation: to factorise x² + bx + c, find two numbers that multiply to c and add to b.

注意:x 的系数是 3 和 5 的和,常数项是 3 和 5 的积。这一规律直接引出因式分解:要把 x² + bx + c 分解因式,只需找到两个数,使它们的乘积为 c、和为 b。


2. Factorising Quadratic Expressions | 二次多项式的因式分解

When the coefficient of x² is 1, factorising is straightforward. For x² − 7x + 12, we need two numbers with product 12 and sum −7. These are −3 and −4, so:

当 x² 的系数为 1 时,因式分解非常简单。对于 x² − 7x + 12,我们需要找到乘积为 12、和为 −7 的两个数。这两个数是 −3 和 −4,因此:

x² − 7x + 12 = (x − 3)(x − 4)

When the coefficient of x² is not 1, for example 2x² + 7x + 3, you can use the ‘grouping’ method. Multiply a and c (2 × 3 = 6), then find two numbers whose product is 6 and whose sum is 7 — that is 1 and 6. Split the middle term and factor by grouping:

当 x² 的系数不为 1 时,例如 2x² + 7x + 3,可以使用“分组分解”法。先求出 a 与 c

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