Solving Quadratic Equations | 解二次方程

📚 Solving Quadratic Equations | 解二次方程

Quadratic equations appear throughout the Edexcel IGCSE Mathematics syllabus, from factorising to graphing. Mastering them is essential for higher-level algebra and problem solving.

二次方程贯穿爱德思IGCSE数学大纲,从因式分解到图像问题都非常重要。掌握二次方程对高阶代数和实际问题求解至关重要。


1. The Standard Form | 标准形式

A quadratic equation is any expression that can be written in the form ax² + bx + c = 0, where a, b and c are constants and a ≠ 0.

二次方程是指可以写成 ax² + bx + c = 0 形式的方程,其中 a、b、c 为常数,且 a ≠ 0。

  • The highest power of x is 2, so the graph is a parabola.

    x 的最高次数为 2,因此图像是一条抛物线。

  • If a > 0, the parabola opens upwards; if a < 0, it opens downwards.

    若 a > 0,抛物线开口向上;若 a < 0,抛物线开口向下。


2. Solving by Factorisation | 因式分解法

Factorisation is the quickest method when the quadratic can be written as a product of two linear factors.

当二次式可以写成两个一次因式的乘积时,因式分解是最快速的方法。

For example, solve x² − 5x + 6 = 0. Look for two numbers that multiply to 6 and add to −5. These are −2 and −3.

例如,解 x² − 5x + 6 = 0。寻找两个数,它们相乘得 6,相加得 −5。这两个数是 −2 和 −3。

(x − 2)(x − 3) = 0

Then set each bracket equal to zero: x = 2 or x = 3.

然后令每个括号等于零:x = 2 或 x = 3。


3. Special Factorisation Patterns | 特殊因式分解模式

Remember these common patterns:

记住这些常见模式:

  • Difference of two squares: x² − a² = (x − a)(x + a).

    平方差:x² − a² = (x − a)(x + a)。

  • Perfect square: x² ± 2ax + a² = (x ± a)².

    完全平方:x² ± 2ax + a² = (x ± a)²。

For instance, x² − 9 = 0 gives (x − 3)(x + 3) = 0, so x = ±3.

例如,x² − 9 = 0 可得 (x − 3)(x + 3) = 0,所以 x = ±3。


4. Completing the Square | 配方法

Completing the square rewrites ax² + bx + c in the form a(x + p)² + q. This is useful for finding turning points and solving equations.

配方法将 ax² + bx + c 改写为 a(x + p)² + q 的形式。这在求顶点坐标和解方程时非常有用。

For x² + 6x − 7 = 0, take half of 6, square it to get 9, then write:

对于 x² + 6x − 7 = 0,取 6 的一半,平方得 9,然后写成:

x² + 6x + 9 − 9 − 7 = (x + 3)² − 16 = 0

So (x + 3)² = 16, giving x + 3 = ±4, hence x = 1 or x = −7.

于是 (x + 3)² = 16,得到 x + 3 = ±4,故 x = 1 或 x = −7。


5. The Quadratic Formula | 二次公式

For any quadratic ax² + bx + c = 0, the solutions are given by the quadratic formula:

对于任意二次方程 ax² + bx + c = 0,解由二次公式给出:

x = (−b ± √(b² − 4ac)) / (2a)

This formula works for all quadratics, including those that do not factorise easily.

这个公式适用于所有二次方程,包括那些不易因式分解的方程。

For 2x² + 3x − 2 = 0, a = 2, b = 3, c = −2. Substitute:

对于 2x² + 3x − 2 = 0,a = 2,b = 3,c = −2。代入:

x = (−3 ± √(9 + 16)) / 4 = (−3 ± 5) / 4

Therefore x = ½ or x = −2.

因此 x = ½ 或 x = −2。


6. The Discriminant | 判别式

The expression b² − 4ac is called the discriminant. It tells us the number of real roots.

表达式 b² − 4ac 称为判别式。它告诉我们实数根的个数。

Discriminant Δ = b² − 4ac Number of real roots 实数根个数
Δ > 0 Two distinct roots 两个不等的实数根
Δ = 0 One repeated root 一个重根
Δ < 0 No real roots 没有实数根

If Δ is a perfect square, the quadratic factors over integers.

如果 Δ 是完全平方数,则二次式可以在整数范围内因式分解。


7. Solving Quadratics by Graphical Method | 图像法解二次方程

The roots of ax² + bx + c = 0 are the x-coordinates where the curve y = ax² + bx + c crosses the x-axis.

ax² + bx + c = 0 的根就是曲线 y = ax² + bx + c 与 x 轴交点的横坐标。

To solve graphically, plot the parabola and read the x-intercepts. This method is useful when exact solutions are not required.

要通过图像求解,先绘制抛物线,然后读出 x 轴交点。当不需要精确解时,这种方法很有用。

Remember that the vertex lies on the axis of symmetry x = −b/(2a).

记住顶点位于对称轴 x = −b/(2a) 上。


8. Word Problems | 应用题

Many IGCSE problems involve forming a quadratic equation from a real-life situation. For example, the area of a rectangle is 40 cm², and its length is 3 cm longer than its width.

许多IGCSE题目需要根据实际情境建立二次方程。例如,一个矩形的面积是 40 cm²,长比宽多 3 cm。

Let width = x, then length = x + 3. The area is x(x + 3) = 40, so x² + 3x − 40 = 0.

设宽为 x,则长为 x + 3。面积为 x(x + 3) = 40,所以 x² + 3x − 40 = 0。

Factorise: (x + 8)(x − 5) = 0, so x = 5 (since width cannot be negative).

因式分解:(x + 8)(x − 5) = 0,所以 x = 5(因为宽不能为负)。


9. Solving Quadratic Inequalities | 解二次不等式

Once roots are found, quadratic inequalities can be solved by considering the sign of the parabola.

求出根之后,可以通过抛物线的符号来解二次不等式。

For x² − x − 6 < 0, factorise to (x − 3)(x + 2) < 0. The critical points are x = −2 and x = 3.

对于 x² − x − 6 < 0,因式分解为 (x − 3)(x + 2) < 0。临界点为 x = −2 和 x = 3。

Since the parabola opens upwards, the inequality is negative between the roots, so −2 < x < 3.

因为抛物线开口向上,不等式在两根之间取负值,所以 −2 < x < 3。


10. Sum and Product of Roots | 根的和与积

For a quadratic ax² + bx + c = 0, if the roots are α and β, then:

对于二次方程 ax² + bx + c = 0,若根为 α 和 β,则:

α + β = −b/a, αβ = c/a

This is useful when checking answers or constructing equations with given roots.

这在检查答案或根据已知根构造方程时非常有用。

For example, roots 2 and −5 give sum −3 and product −10, so the equation is x² + 3x − 10 = 0.

例如,根 2 和 −5 的和为 −3,积为 −10,所以方程为 x² + 3x − 10 = 0。


11. Common Mistakes to Avoid | 常见错误提醒

  • Do not forget to make the equation equal to zero before factorising or using the formula.

    在因式分解或使用公式前,不要忘记将方程化为等于零的形式。

  • When taking the square root of both sides, remember to include both positive and negative roots.

    两边开平方时,记得同时取正根和负根。

  • In the quadratic formula, be careful with signs when substituting negative coefficients.

    在二次公式中,代入负系数时要特别注意符号。

  • Always check your solutions by substituting them back into the original equation.

    始终将解代回原方程进行检查。


12. Exam Tips | 考试技巧

In the Edexcel IGCSE exam, show all working clearly. If a question says ‘give your answer correct to 2 decimal places’, use the quadratic formula or completing the square, not factorisation.

在爱德思IGCSE考试中,要清晰展示全部步骤。如果题目要求”将答案精确到小数点后两位”,应使用二次公式或配方法,而不是因式分解。

For calculator papers, you can check your factorised answer by expanding it mentally. Always present the roots in the required form, whether exact or as decimals.

在允许使用计算器的试卷中,可以用心算展开因式来检验答案。无论要求精确值还是小数,务必按要求形式写出根。

Practising all four methods—factorisation, completing the square, formula and graphing—will give you flexibility and speed.

练习四种方法——因式分解、配方法、公式法和图像法——会让你更加灵活和快速。


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