Solving Quadratic Equations | 解二次方程

📚 Solving Quadratic Equations | 解二次方程

Quadratic equations appear in almost every Edexcel IGCSE Mathematics (4MA1) paper, whether as direct solving questions, graph-sketching tasks, or multi-step word problems. Mastering factorisation, completing the square, the quadratic formula and the graphical method is essential for top marks.

二次方程几乎出现在每一份 Edexcel IGCSE 数学(4MA1)试卷中,无论是直接求解、函数图像题,还是多步骤应用题。熟练掌握因式分解、配方法、二次公式法和图像法,是冲击高分的关键。


1. What Is a Quadratic Equation? | 什么是二次方程

A quadratic equation is an equation where the highest power of the unknown variable is 2. Its general form is ax² + bx + c = 0, where a, b and c are constants and a must not be zero.

二次方程是指未知数的最高次数为 2 的方程。它的一般形式是 ax² + bx + c = 0,其中 a、b、c 为常数,且 a 不能为零。

  • If a = 0, the equation becomes linear, not quadratic.
    如果 a = 0,方程就变成一次方程,而不是二次方程。
  • The solutions of a quadratic equation are called roots or solutions.
    二次方程的解称为根(roots)。
  • “Quadratic” comes from the Latin word “quadratus”, meaning square.
    “Quadratic” 一词源自拉丁文 “quadratus”,意为”平方”。

2. Rearranging into Standard Form | 化为标准形式

Before choosing a solving method, you must always rearrange the equation so that one side equals zero and the terms are in descending powers of x.

在选择解法之前,你必须先把方程整理成一边等于零,并且各项按 x 的降幂排列。

Example: Solve 3x(x − 1) = 2x + 5.

例:解方程 3x(x − 1) = 2x + 5。

Expand the left-hand side first:
先展开左边:

3x² − 3x = 2x + 5 → 3x² − 5x − 5 = 0

  • Expand brackets carefully, watching negative signs.
    展开括号时小心负号。
  • Collect all terms on one side; the x² term should be positive if possible.
    把所有项移到一边;x² 项的系数最好为正。
  • If the equation contains fractions, multiply through by the common denominator first.
    若方程含分数,先乘以公分母去分母。

3. Solving by Factorisation | 因式分解法

Factorisation works when the quadratic can be written as a product of two linear brackets. This is often the fastest method in the IGCSE exam.

当二次式能写成两个一次括号相乘时,就可以用因式分解法。这通常是 IGCSE 考试中最快的方法。

Worked example: Solve x² − 5x + 6 = 0.
例:解 x² − 5x + 6 = 0。

Find two numbers that multiply to +6 and add to −5. The numbers are −2 and −3, so:
找两个数,相乘等于 +6,相加等于 −5。这两个数是 −2 和 −3,所以:

(x − 2)(x − 3) = 0 → x = 2 or x = 3

  • Always set each bracket equal to zero separately.
    务必让每个括号分别等于零。
  • Check your roots by substituting them back into the original equation.
    把根代回原方程检验。
  • Special case: x² − 9 = 0 → (x − 3)(x + 3) = 0 → x = ±3 (difference of two squares).
    特殊情况:x² − 9 = 0 → (x − 3)(x + 3) = 0 → x = ±3(平方差公式)。
  • Special case: 2x² + 4x = 0 → 2x(x + 2) = 0 → x = 0 or x = −2 (common factor).
    特殊情况:2x² + 4x = 0 → 2x(x + 2) = 0 → x = 0 或 x = −2(提取公因式)。

4. Solving by Completing the Square | 配方法

Completing the square rewrites a quadratic in the form (x + p)² + q. It is useful when factorisation is not obvious and it also reveals the turning point of the graph.

配方法把二次式改写成 (x + p)² + q 的形式。当因式分解不明显时非常有用,同时还能直接看出图像的顶点。

Worked example: Solve x² + 6x + 2 = 0.
例:解 x² + 6x + 2 = 0。

Take half of 6, which is 3, and write:
取 6 的一半,即 3,写出:

(x + 3)² − 9 + 2 = 0 → (x + 3)² = 7

x + 3 = ±√7 → x = −3 ± √7

  • Remember to subtract the square of half the coefficient: (b/2)².
    不要忘记减去”一次项系数一半的平方”:(b/2)²。
  • The vertex of y = (x + 3)² − 7 is at (−3, −7).
    函数 y = (x + 3)² − 7 的顶点坐标为 (−3, −7)。
  • Leave answers in surd form unless the question asks for decimals.
    除非题目要求小数,否则答案保留根号形式。

5. The Quadratic Formula | 二次公式

The quadratic formula solves any quadratic equation, even when it cannot be factorised easily. You must memorise it for the exam.

二次公式可以求解任何二次方程,即使无法轻松因式分解。考试中你必须熟记这个公式。

x = (−b ± √(b² − 4ac)) / (2a)

Here a, b and c are taken from the standard form ax² + bx + c = 0. Substitute carefully, paying attention to signs.

这里的 a、b、c 取自标准形式 ax² + bx + c = 0。代入时要格外小心符号。

  • Write down a =, b =, c = before substituting.
    代入前先写出 a =、b =、c =。
  • Use a scientific calculator to check your final decimals.
    用科学计算器检验最终小数答案。
  • Do not round until the last step.
    最后一步之前不要四舍五入。

6. Worked Example Using the Formula | 公式法例题

Solve 2x² − 4x − 3 = 0 using the quadratic formula.
用二次公式解 2x² − 4x − 3 = 0。

Here a = 2, b = −4 and c = −3. Substitute these values:
这里 a = 2,b = −4,c = −3。代入公式:

x = (4 ± √((−4)² − 4 × 2 × (−3))) / (2 × 2)

x = (4 ± √(16 + 24)) / 4 = (4 ± √40) / 4

Simplify √40 = 2√10, so x = (2 ± √10) / 2. As decimals, x ≈ 2.58 or x ≈ −0.58.

化简 √40 = 2√10,所以 x = (2 ± √10) / 2。化为小数得 x ≈ 2.58 或 x ≈ −0.58。

  • A negative sign inside the square root means you have made a sign error.
    根号内若出现负数,说明你符号代错了。
  • Check that b² − 4ac is simplified before taking the square root.
    开根号之前,先化简 b² − 4ac。
  • Give both roots; the ± symbol represents two distinct answers.
    两个根都要写出;± 代表两个不同的答案。

7. The Discriminant | 判别式

The expression b² − 4ac is called the discriminant. It tells you how many real roots a quadratic equation has without solving it.

式子 b² − 4ac 称为判别式。不解方程,它就能告诉你二次方程有几个实数根。

Discriminant 判别式 Number of real roots 实数根个数 Graph meaning 图像含义
b² − 4ac > 0 Two distinct real roots 两个不同实数根 Graph crosses the x-axis twice 图像与 x 轴有两个交点
b² − 4ac = 0 One repeated real root 两个相等实数根 Graph touches the x-axis at one point 图像与 x 轴相切于一点
b² − 4ac < 0 No real roots 无实数根 Graph does not meet the x-axis 图像与 x 轴无交点

If b² − 4ac is a perfect square, the roots are rational and factorisation should work. If not, the roots are irrational surds.

若 b² − 4ac 是完全平方数,则根为有理数,通常可以因式分解;若不是,则根为无理数(根式形式)。


8. Solving Quadratic Equations Using Graphs | 用图像法解二次方程

The roots of ax² + bx + c = 0 are exactly the x-intercepts of the graph y = ax² + bx + c. Reading where the curve crosses the x-axis gives approximate solutions.

方程 ax² + bx + c = 0 的根,正是图像 y = ax² + bx + c 与 x 轴交点的横坐标。读出曲线与 x 轴的交点即可得到近似解。

Example: The graph of y = x² − 3x + 2 crosses the x-axis at x = 1 and x = 2, so the equation x² − 3x + 2 = 0 has roots x = 1 and x = 2.

例:y = x² − 3x + 2 的图像与 x 轴交于 x = 1 和 x = 2,因此方程 x² − 3x + 2 = 0 的根为 x = 1 和 x = 2。

  • If the parabola does not touch the x-axis, the equation has no real roots.
    若抛物线与 x 轴没有交点,则方程无实数根。
  • The completed-square form y = (x − h)² + k gives the turning point (h, k).
    配方形式 y = (x − h)² + k 可直接给出顶点坐标 (h, k)。
  • To solve ax² + bx + c = k graphically, draw the line y = k and read the intersection x-values.
    要在图像上解 ax² + bx + c = k,可画水平线 y = k,读取交点横坐标。

9. Word Problems Involving Quadratics | 二次方程应用题

Exam word problems often lead to a quadratic equation after forming and simplifying an area or product expression.

考试中的应用题往往在列出并化简面积或乘积表达式后,得到二次方程。

Worked example: A rectangle has length (x + 4) m and width (x + 1) m. Its area is 40 m². Find x.

例:一个长方形的长为 (x + 4) 米,宽为 (x + 1) 米,面积为 40 平方米。求 x。

(x + 4)(x + 1) = 40 → x² + 5x + 4 = 40

x² + 5x − 36 = 0 → (x + 9)(x − 4) = 0

So x = −9 or x = 4. Since lengths cannot be negative, reject x = −9. The valid answer is x = 4.

所以 x = −9 或 x = 4。由于长度不能为负,舍去 x = −9,有效答案为 x = 4。

  • Always state why you reject a negative root in a context question.
    在应用题中,务必说明为什么舍去负根。
  • Use the original units of measurement in your final answer.
    最终答案使用题目原有的单位。
  • Read the question again: sometimes x is only part of what is asked.
    再读一遍题目:有时 x 只是所求量的一部分。

10. Common Exam Mistakes | 常见考试误区

Here are the most frequent errors students make in quadratic questions, with advice on how to avoid them.

下面是学生在二次方程题中最常犯的错误,以及避免方法。

  • Forgetting to rearrange: solving 2x² + 5 = 3x without moving all terms to one side.
    忘记整理:解 2x² + 5 = 3x 时没有把所有项移到一边。
  • Dividing by x: this loses the root x = 0. Factor instead of dividing.
    两边除以 x:这会丢失根 x = 0。应该提取公因式,而不是约去 x。
  • Misreading signs in the formula: when b is negative, −b becomes positive.
    公式中符号看错:当 b 为负数时,−b 要变为正数。
  • Using the quadratic formula without writing a, b and c first.
    不先写出 a、b、c 就直接套用二次公式。
  • Rounding intermediate values, which destroys accuracy.
    过早四舍五入中间值,导致精度损失。

11. Exam Checklist | 考场检查清单

Use this quick checklist before you move on to the next question.

进入下一题之前,快速对照这份检查清单。

Check 检查项 Question to ask yourself 自问
Standard form 标准形式 Is the equation written as ax² + bx + c = 0? 方程是否写成 ax² + bx + c = 0?
Method 解法 Is factorisation possible, or should I use the formula? 可否因式分解?否则用公式法?
Discriminant 判别式 Is b² − 4ac positive, zero or negative? b² − 4ac 是正、零还是负?
Substitution 代入检验 Do both roots satisfy the original equation? 两个根是否都满足原方程?
Context 情境 Are both roots sensible in the problem context? 在题目情境中两个根是否都合理?

12. Summary | 总结

Quadratic equations are a guaranteed topic on the Edexcel IGCSE Mathematics exam. Practise rearranging into standard form, choose the fastest method, check the discriminant and verify every root by substitution.

二次方程是 Edexcel IGCSE

Published by TutorHao | IGCSE Mathematics Revision Series | aleveler.com

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