Electron Domains and Molecular Geometry | 电子域与分子几何构型

📚 Electron Domains and Molecular Geometry | 电子域与分子几何构型

Understanding molecular geometry is essential in IB Chemistry HL, as it explains how atoms arrange themselves in three-dimensional space. The Valence Shell Electron Pair Repulsion (VSEPR) theory provides a simple yet powerful model for predicting the shapes of molecules based on the repulsion between electron domains around a central atom.

理解分子几何构型是IB化学HL的核心内容,它解释了原子如何在三维空间中排列。价层电子对互斥理论(VSEPR)提供了一个简单而强大的模型,通过中心原子周围电子域之间的排斥作用来预测分子的形状。


1. What Are Electron Domains? | 什么是电子域?

An electron domain is any region around a central atom where electrons are likely to be found. This includes bonding pairs of electrons (single, double, or triple bonds) and lone pairs of electrons. Each bond, regardless of bond order, counts as one electron domain.

电子域是中心原子周围电子可能出现的区域,包括成键电子对(单键、双键或三键)和孤对电子。每个键,无论键级如何,都算作一个电子域。

  • Bonding domain: a pair of electrons shared between two atoms (e.g., C–H, C=O, C≡N).
  • Lone pair domain: a pair of electrons not involved in bonding (e.g., the lone pair on N in NH₃).
  • 成键域:两个原子之间共享的一对电子(如C–H、C=O、C≡N)。
  • 孤对电子域:不参与成键的一对电子(如NH₃中N上的孤对电子)。

For example, in CO₂, the central carbon has two double bonds, so it has two electron domains. In H₂O, oxygen has two single bonds and two lone pairs, giving four electron domains.

例如,在CO₂中,中心碳原子有两个双键,因此有2个电子域。在H₂O中,氧原子有2个单键和2个孤对电子,总计4个电子域。


2. VSEPR Theory Core Principle | VSEPR理论核心原理

The VSEPR theory states that electron domains around a central atom repel each other and will arrange themselves as far apart as possible to minimize this repulsion. The resulting arrangement determines the bond angles and overall shape of the molecule.

VSEPR理论指出,中心原子周围的电子域相互排斥,并会尽可能远离以减小这种排斥作用。由此产生的排列决定了键角和分子的整体形状。

Repulsion strength follows this order:

排斥强度遵循以下顺序:

lone pair–lone pair > lone pair–bonding pair > bonding pair–bonding pair

孤对电子–孤对电子 > 孤对电子–成键电子 > 成键电子–成键电子

This means lone pairs occupy more space and compress bond angles, making them crucial for predicting deviations from ideal geometries.

这意味着孤对电子占据更多空间并压缩键角,因此它们对预测偏离理想几何构型至关重要。


3. Electron Domain Geometry vs Molecular Geometry | 电子域几何与分子几何的区别

It is vital to distinguish between electron domain geometry (the arrangement of all electron domains) and molecular geometry (the arrangement of only atoms). Lone pairs are included in the former but not in the latter.

区分电子域几何(所有电子域的排列)和分子几何(仅原子的排列)至关重要。孤对电子包含在前者中,但不包含在后者中。

For a molecule with four electron domains and no lone pairs, both geometries are tetrahedral. But if one domain is a lone pair, the molecular shape becomes trigonal pyramidal, even though the electron domain geometry remains tetrahedral.

对于一个有4个电子域且无孤对电子的分子,两种几何都是四面体形。但如果一个域是孤对电子,分子形状变为三角锥形,尽管电子域几何仍是四面体形。

Electron domains Lone pairs Electron domain geometry Molecular geometry
4 1 Tetrahedral Trigonal pyramidal
4 2 Tetrahedral Bent (V-shaped)
电子域数 孤对电子数 电子域几何 分子几何
4 1 四面体形 三角锥形
4 2 四面体形 角形(V形)

4. Two and Three Electron Domains | 两个和三个电子域

With two electron domains, the optimal arrangement is linear. The bond angle is 180°, as seen in BeCl₂ and CO₂. With three electron domains, the geometry is trigonal planar, with bond angles of 120°, as in BF₃.

当有2个电子域时,最佳排列是直线形,键角为180°,如BeCl₂和CO₂。当有3个电子域时,几何为平面三角形,键角为120°,如BF₃。

If one of the three domains is a lone pair, the molecular shape becomes bent, with bond angles slightly less than 120° due to lone pair repulsion. An example is SO₂ (with one lone pair on sulfur) or O₃.

如果三个域中有一个是孤对电子,分子形状变为角形,键角略小于120°,这是因为孤对电子的排斥作用。例如SO₂(硫上有一个孤对电子)或O₃。


5. Four Electron Domains: Tetrahedral Family | 四个电子域:四面体家族

Four electron domains arrange tetrahedrally with ideal bond angles of 109.5°. This is the most common arrangement in organic and inorganic chemistry. Key examples include CH₄ (no lone pairs), NH₃ (one lone pair), and H₂O (two lone pairs).

四个电子域按四面体排列,理想键角为109.5°。这是有机和无机化学中最常见的排列方式。典型例子包括CH₄(无孤对电子)、NH₃(一个孤对电子)和H₂O(两个孤对电子)。

CH₄: 109.5° → NH₃: 107° → H₂O: 104.5°

CH₄:109.5° → NH₃:107° → H₂O:104.5°

The decreasing bond angle is explained by increasing lone pair repulsion. Each lone pair compresses the bonding pairs more strongly, reducing the H–X–H angle.

键角递减可通过孤对电子排斥增大来解释。每个孤对电子更强烈地压缩成键电子对,从而减小H–X–H键角。


6. Five and Six Electron Domains | 五个和六个电子域

Five electron domains give a trigonal bipyramidal electron domain geometry, with axial (90° from central axis) and equatorial (120° in the plane) positions. For molecular geometry with no lone pairs, the shape is trigonal bipyramidal, e.g., PCl₅.

五个电子域产生三角双锥形电子域几何,包含轴向位置(与中心轴成90°)和赤道位置(平面内120°)。如果没有孤对电子,分子几何为三角双锥形,如PCl₅。

Six electron domains give an octahedral electron domain geometry, with all bond angles at 90°. SF₆ is a classic example. When lone pairs are present, they preferentially occupy equatorial positions (for 5 domains) to minimize repulsion.

六个电子域产生八面体形电子域几何,所有键角为90°。SF₆是典型例子。当存在孤对电子时,它们优先占据赤道位置(对于5个域),以减小排斥作用。

For example, BrF₃ has five domains (three bonding, two lone pairs), giving a T-shaped molecular geometry. XeF₄ has six domains (four bonding, two lone pairs), giving a square planar shape.

例如,BrF₃有5个域(3个成键、2个孤对电子),形成T形分子几何。XeF₄有6个域(4个成键、2个孤对电子),形成平面正方形。


7. Predicting Molecular Shape Step by Step | 逐步预测分子形状

To determine the molecular geometry of any species, follow this systematic approach:

要确定任何物种的分子几何,请遵循以下系统步骤:

  1. Draw the Lewis structure (including all valence electrons).
  2. Count the total number of electron domains around the central atom (each bond = 1 domain, each lone pair = 1 domain).
  3. Determine the electron domain geometry from the total domains.
  4. Count lone pairs on the central atom and subtract their positions from the geometry to obtain the molecular geometry.
  5. State the bond angles, adjusting for lone pair compression.
  1. 绘制路易斯结构(包括所有价电子)。
  2. 计算中心原子周围电子域总数(每个键=1个域,每对孤对电子=1个域)。
  3. 由总域数确定电子域几何。
  4. 计算中心原子上的孤对电子数,从几何中扣除它们的位置,得到分子几何。
  5. 写出键角,并根据孤对电子压缩进行调整。

Example: For SO₃, sulfur has 6 valence electrons, each oxygen contributes 6, total = 24. The Lewis structure shows S with three double bonds and no lone pairs. Thus, 3 electron domains → trigonal planar, 120°.

示例:对于SO₃,硫有6个价电子,每个氧贡献6个,总计24个。路易斯结构显示S有3个双键且无孤对电子。因此,3个电子域→平面三角形,120°。


8. Hybridization and Electron Domains | 杂化与电子域

In HL, hybridization theory links the number of electron domains to the mixing of atomic orbitals. The hybridization of the central atom corresponds exactly to its electron domain count:

在HL中,杂化理论将电子域数量与原子轨道的混合联系起来。中心原子的杂化方式与其电子域数完全对应:

Electron domains Hybridization Shape
2 sp Linear
3 sp² Trigonal planar
4 sp³ Tetrahedral
5 sp³d Trigonal bipyramidal
6 sp³d² Octahedral
电子域数 杂化方式 形状
2 sp 直线形
3 sp² 平面三角形
4 sp³ 四面体形
5 sp³d 三角双锥形
6 sp³d² 八面体形

For example, carbon in CH₄ uses four equivalent sp³ orbitals, while carbon in CO₂ uses two sp orbitals. This hybridization model explains the equal bond lengths and angles observed in symmetrical molecules.

例如,CH₄中的碳使用4个等价sp³轨道,而CO₂中的碳使用2个sp轨道。这种杂化模型解释了对称分子中观察到的等键长和等键角。


9. Polarity and Molecular Geometry | 极性与分子几何

The shape of a molecule directly determines whether it is polar or nonpolar. A molecule is polar if it has polar bonds and an asymmetric arrangement that prevents bond dipoles from cancelling.

分子的形状直接决定其是极性还是非极性。如果分子有极性键且排列不对称,导致键偶极无法抵消,则为极性分子。

For instance, CO₂ is linear with two identical C=O dipoles pointing in opposite directions, so it is nonpolar. H₂O is bent, and the two O–H dipoles do not cancel, making it polar.

例如,CO₂是直线形,两个相同的C=O偶极方向相反,因此是非极性的。H₂O是角形,两个O–H偶极不能抵消,因此是极性的。

Similarly, CCl₄ is tetrahedral with four C–Cl dipoles that cancel symmetrically, so it is nonpolar. CHCl₃, with one C–H bond, is polar because the dipoles are no longer symmetric.

类似地,CCl₄是四面体形,四个C–Cl偶极对称抵消,因此是非极性的。CHCl₃有一个C–H键,由于偶极不再对称,因此是极性的。


10. Bond Angles and Lone Pair Effects: Detailed Analysis | 键角与孤对电子效应:详细分析

Lone pairs exert stronger repulsion because they occupy larger orbitals and are closer to the central nucleus. This compresses the bonding pair angles more than a bonding pair alone would.

孤对电子产生更强排斥作用,因为它们占据更大的轨道且更靠近中心原子核。这比单独的成键电子对更能压缩成键电子对之间的角度。

Consider the series of hydrides:

考虑氢化物系列:

  • CH₄: 4 bonding pairs, no lone pairs → angle = 109.5°
  • NH₃: 3 bonding pairs, 1 lone pair → angle = 107° (reduced by ~2.5°)
  • H₂O: 2 bonding pairs, 2 lone pairs → angle = 104.5° (reduced by ~5°)
  • CH₄:4个成键对,无孤对电子 → 键角 = 109.5°
  • NH₃:3个成键对,1个孤对电子 → 键角 = 107°(减小约2.5°)
  • H₂O:2个成键对,2个孤对电子 → 键角 = 104.5°(减小约5°)

In addition, double bonds occupy more space than single bonds. For example, in phosgene (COCl₂), the Cl–C–Cl angle is slightly less than 120° because the C=O double bond repels the Cl atoms more strongly.

此外,双键比单键占据更多空间。例如,在光气(COCl₂)中,Cl–C–Cl键角略小于120°,因为C=O双键对Cl原子的排斥更强。


11. Worked Example: ICl₄⁻ and XeO₃ | 实例解析:ICl₄⁻ 和 XeO₃

Let us apply the steps to a real ion and a molecule.

让我们将步骤应用于一个真实离子和一个分子。

ICl₄⁻ (Iodine tetrachloride ion): Iodine has 7 valence electrons, each Cl contributes 7, plus 1 for the negative charge, total = 36. Central I has 4 bonding pairs and 2 lone pairs → 6 electron domains → octahedral electron domain geometry → square planar molecular geometry. Bond angles: 90°.

ICl₄⁻(四氯合碘离子):碘有7个价电子,每个Cl贡献7个,加上负电荷的1个,总计36个。中心I有4个成键对和2个孤对电子 → 6个电子域 → 八面体电子域几何 → 平面正方形分子几何。键角:90°。

XeO₃ (Xenon trioxide): Xenon has 8 valence electrons, each O contributes 6, total = 26. Central Xe forms three double bonds (6 electrons) and retains one lone pair → 4 electron domains → tetrahedral electron domain geometry → trigonal pyramidal molecular geometry. Bond angle: slightly less than 109.5°.

XeO₃(三氧化氙):氙有8个价电子,每个O贡献6个,总计26个。中心Xe形成三个双键(6个电子)并保留一个孤对电子 → 4个电子域 → 四面体电子域几何 → 三角锥形分子几何。键角:略小于109.5°。


12. Common Mistakes and Exam Tips | 常见错误与考试建议

Students often confuse electron domain geometry with molecular geometry. Remember that lone pairs are counted as domains, but they are not atoms, so they do not appear in the molecular shape name.

学生常将电子域几何与分子几何混淆。请记住,孤对电子算作电子域,但它们不是原子,因此不体现在分子形状名称中。

  • Mistake: Saying NH₃ is tetrahedral. Correct: electron domain geometry is tetrahedral; molecular geometry is trigonal pyramidal.
  • Mistake: Ignoring lone pairs when predicting bond angles. Always reduce angles by 2°–5° per lone pair.
  • Tip: For species with multiple resonance structures, use any resonance form to count domains – the geometry is identical.
  • Tip: In the exam, draw the Lewis structure first, then count domains systematically.
  • 错误:说NH₃是四面体形。正确:电子域几何是四面体形;分子几何是三角锥形。
  • 错误:预测键角时忽略孤对电子。每有一个孤对电子,键角应减小2°–5°。
  • 建议:对于有多种共振结构的物种,使用任意一种共振形式计算电子域——几何是相同的。
  • 建议:考试中先画路易斯结构,再系统地计算电子域。

Also, remember that transition metal complexes are typically described by crystal field theory rather than VSEPR, as VSEPR applies mainly to p-block compounds.

另外,过渡金属配合物通常用晶体场理论描述,而非VSEPR,因为VSEPR主要适用于p区元素化合物。


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