📚 A-Level AQA Maths: Last-Minute Revision Notes | AQA A-Level 数学考前冲刺笔记
This last-minute revision guide brings together the essential formulas, techniques, and exam tips for the AQA A-Level Mathematics course. It covers core pure topics, statistics, and mechanics in a concise, easy‑to‑review format. Use it to jog your memory, avoid common pitfalls, and approach the exam with confidence.
这份考前冲刺笔记整理了 AQA A-Level 数学的核心公式、解题技巧和考试提醒,涵盖纯数、统计与力学三大模块,内容精炼、便于快速回顾。考前翻阅能帮你唤醒记忆、避开常见陷阱,自信应考。
1. Algebraic Techniques and Key Theorems | 代数技巧与关键定理
Manipulating algebraic expressions fluently is the foundation of success across the whole paper. Always check for common factors first, then look for the difference of two squares or the quadratic pattern.
熟练运用代数变形是全卷得分的基础。先检查是否有公因式,再观察是否为平方差或二次三项式的形式。
- Factorising: a² − b² = (a − b)(a + b). For harder quadratics, use the ‘ac’ method or complete the square.
- 因式分解:a² − b² = (a − b)(a + b)。较难的二次式可用“ac”法或配方法。
- The Remainder Theorem: If a polynomial f(x) is divided by (x − a), the remainder is f(a). The Factor Theorem states (x − a) is a factor if and only if f(a) = 0.
- 余式定理:多项式 f(x) 除以 (x − a) 的余数为 f(a)。因式定理指出,(x − a) 为因式当且仅当 f(a) = 0。
- Binomial expansion: (1 + x)ⁿ = 1 + nx + [n(n‑1)/2!] x² + … valid for |x| < 1 when n is not a positive integer.
- 二项展开:(1 + x)ⁿ = 1 + nx + [n(n‑1)/2!] x² + … 当 n 非正整数时要求 |x| < 1。
a³ + b³ = (a + b)(a² − ab + b²)
a³ + b³ = (a + b)(a² − ab + b²)
2. Functions and Transformations | 函数与图像变换
Understanding function notation and transformations is crucial for graphing questions and modelling. Watch out for domain restrictions, especially with square roots and logarithms.
理解函数符号与图像变换是作图与建模题的基础。特别注意定义域限制,尤其是带根号和对数的情况。
| Transformation | Effect on y = f(x) | 变换 |
| f(x) + a | Translation by vector (0, a) | 沿 y 轴平移 a |
| f(x + a) | Translation by vector (−a, 0) | 沿 x 轴平移 −a |
| a f(x) | Vertical stretch, scale factor a | 竖直拉伸,倍数 a |
| f(ax) | Horizontal stretch, scale factor 1/a | 水平拉伸,倍数 1/a |
When a function is defined piecewise, sketch carefully and pay attention to whether endpoints are included. For composite functions fg(x), work ‘inside out’: first apply g, then f.
对于分段函数要仔细画图,注意端点是否包含。复合函数 fg(x) 遵循“从内向外”的原则:先算 g,再算 f。
3. Trigonometric Identities and Equations | 三角恒等式与方程
Trigonometry questions often combine exact values, identities, and equation solving. Memorise the two Pythagorean identities and learn to spot hidden quadratics.
三角题常常混合特殊值、恒等式和解方程。熟记两个毕达哥拉斯恒等式,并学会识别隐藏的二次型。
- cos²θ + sin²θ ≡ 1 ; 1 + tan²θ ≡ sec²θ (both given in the formula booklet)
- cos²θ + sin²θ ≡ 1 ; 1 + tan²θ ≡ sec²θ(公式表提供)
- Double angle: sin2θ = 2 sinθ cosθ;cos2θ = cos²θ − sin²θ = 2 cos²θ − 1 = 1 − 2 sin²θ.
- 倍角公式:sin2θ = 2 sinθ cosθ;cos2θ 有三种等价形式。
- Solving equations: first rearrange to get a single trig function, then find principal values, and finally add/subtract periods to find all solutions in the required interval.
- 解三角方程:先将方程化为单一三角函数,求出主值,再根据周期给出所求区间内的所有解。
sin(π/6) = ½, cos(π/3) = ½, tan(π/4) = 1
sin(π/6) = ½, cos(π/3) = ½, tan(π/4) = 1
A common mistake is forgetting that when you take square roots you need both positive and negative cases: e.g., sinθ = ±√0.25 gives four solutions in 0 ≤ θ < 2π.
常见错误是开平方后忘记正负两种情况:例如 sinθ = ±√0.25 在 0 ≤ θ < 2π 内会有四个解。
4. Differentiation: Rules and Applications | 微分:法则与应用
Master the chain, product, and quotient rules. Always simplify before differentiating when possible, and check the domain of the derivative.
掌握链式法则、乘积法则和商法则。微分前尽量先化简,并注意导数的定义域。
d/dx [xⁿ] = n xⁿ⁻¹
d/dx [xⁿ] = n xⁿ⁻¹
- Chain rule: dy/dx = dy/du × du/dx. Used for composite functions like e^{3x} or ln(5x − 1).
- 链式法则:dy/dx = dy/du · du/dx,用于复合函数如 e^{3x} 和 ln(5x − 1)。
- Product rule: d/dx (uv) = u’v + uv’. Quotient rule: d/dx (u/v) = (u’v − uv’)/v².
- 乘积法则:d/dx (uv) = u’v + uv’;商法则:d/dx (u/v) = (u’v − uv’)/v²。
- Second derivative d²y/dx² tells you about concavity and helps classify stationary points. Positive → minimum, negative → maximum.
- 二阶导数 d²y/dx² 用于判断凹凸性并分类驻点。二阶导数为正 → 极小值点,为负 → 极大值点。
At a stationary point, dy/dx = 0. For a point of inflection, the second derivative changes sign (or first derivative does not change sign). Check both sides of the point.
驻点处 dy/dx = 0。拐点处二阶导数变号(或一阶导数不变号)。务必检查该点左右两侧的符号。
5. Integration: Techniques and Definite Integrals | 积分:技巧与定积分
Integration is the reverse of differentiation, but requires pattern recognition. Look for standard forms and consider substitution when you see a function and its derivative.
积分是微分的逆运算,需要识别模式。看到函数与其导数同时出现时,优先考虑换元法。
∫ xⁿ dx = xⁿ⁺¹/(n+1) + C (n ≠ −1)
∫ xⁿ dx = xⁿ⁺¹/(n+1) + C (n ≠ −1)
- ∫ e^{ax} dx = (1/a) e^{ax} + C;∫ 1/x dx = ln|x| + C;∫ cos(ax) dx = (1/a) sin(ax) + C
- ∫ e^{ax} dx = (1/a) e^{ax} + C;∫ 1/x dx = ln|x| + C;∫ cos(ax) dx = (1/a) sin(ax) + C
- Integration by substitution: choose u = inner function, replace dx with du / (du/dx). Don’t forget to change the limits in a definite integral.
- 换元积分:令 u = 内层函数,将 dx 替换为 du/(du/dx)。定积分换元时务必同时改变积分上下限。
- Definite integral ∫ₐᵇ f(x) dx gives the signed area between the curve and the x-axis. If the curve goes below the axis, compute the area in parts.
- 定积分 ∫ₐᵇ f(x) dx 表示曲线与 x 轴间的带符号面积。若曲线在 x 轴下方,应分段计算面积。
When using the trapezium rule, remember: h = (b−a)/n, and the formula is h/2 [y₀ + yₙ + 2(y₁ + y₂ + … + yₙ₋₁)]. This overestimates when the curve is convex.
使用梯形法则时,牢记 h = (b−a)/n,公式为 (h/2)[ y₀ + yₙ + 2(y₁+ …+yₙ₋₁)]。曲线为上凸时该法会高估面积。
6. Vectors in 2D and 3D | 二维与三维向量
Vector questions test your ability to move between notation forms and apply geometric concepts. Always draw a simple sketch to visualise directions.
向量题考查在不同表示形式间转换的能力以及应用几何概念的能力。画简图有助于理清方向。
- Magnitude: |a i + b j| = √(a² + b²); in 3D |a i + b j + c k| = √(a² + b² + c²).
- 模长:|a i + b j| = √(a² + b²);三维下 |a i + b j + c k| = √(a² + b² + c²)。
- Unit vector: â = a / |a|. Parallel vectors are scalar multiples of each other.
- 单位向量:â = a / |a|。平行向量彼此成标量倍数。
- Dot product: a·b = |a||b| cosθ = a₁b₁ + a₂b₂ (+ a₃b₃). If a·b = 0, vectors are perpendicular.
- 点乘:a·b = |a||b| cosθ = a₁b₁ + a₂b₂(+ a₃b₃)。若 a·b = 0,则两向量垂直。
To find the angle between two vectors, use cosθ = (a·b) / (|a||b|). Make sure you use the acute angle when asked for the angle between lines.
求两向量夹角时用 cosθ = (a·b) / (|a||b|)。注意题目要求的是锐角还是钝角。
7. Probability and Statistical Distributions | 概率与统计分布
AQA thoroughly tests binomial and normal distributions, often in context. Be methodical: identify the variable, parameters, and the event you need to calculate.
AQA 会充分考查二项分布与正态分布的实际应用。解题要有条理:确定随机变量、参数及所求事件。
- Binomial: X ~ B(n, p). P(X = r) = ⁿCᵣ pʳ (1−p)ⁿ⁻ʳ. Mean = np, variance = np(1−p).
- 二项分布:X ~ B(n, p),P(X = r) = ⁿCᵣ pʳ (1−p)ⁿ⁻ʳ,均值 np,方差 np(1−p)。
- Normal: X ~ N(μ, σ²). Use z = (x − μ)/σ. The total area under the curve is 1; tables give P(Z < z).
- 正态分布:X ~ N(μ, σ²),标准化 z = (x − μ)/σ。曲线下总面积为 1;标准正态表给出 P(Z < z)。
- For “greater than” probabilities, use complement: P(X > a) = 1 − P(X < a). Draw a bell curve and shade the required area.
- 求“大于”型概率用补集:P(X > a) = 1 − P(X < a)。画出钟形曲线并涂色待求区域有助于避免错误。
When approximating a binomial with a normal, check that np > 5 and n(1−p) > 5. Apply the continuity correction (e.g., P(X ≤ 10) becomes P(X < 10.5)).
用正态分布近似二项分布时,需满足 np > 5 且 n(1−p) > 5,并进行连续性校正(如 P(X ≤ 10) 变为 P(X < 10.5))。
8. Hypothesis Testing and Correlation | 假设检验与相关性
Hypothesis testing is a structured procedure. Write the null and alternative hypotheses clearly, state the significance level, and always interpret your result in context.
假设检验有固定步骤。明确写出原假设与备择假设,标明显著性水平,最后在原文情境中给出结论。
- Null hypothesis H₀: population parameter equals a claimed value. Alternative H₁: parameter is greater, smaller, or different (one‑tailed or two‑tailed).
- 原假设 H₀:总体参数等于某假设值;备择假设 H₁:参数大于、小于或不等于该值(单尾或双尾)。
- For a binomial test, find P(X ≥ observed) or P(X ≤ observed) depending on the tail. Compare the p‑value with the significance level.
- 对二项分布检验,根据尾部方向计算 P(X ≥ 观测值) 或 P(X ≤ 观测值),将 p 值与显著性水平比较。
- Product Moment Correlation Coefficient (PMCC): given by formula booklet. Test for zero correlation using the critical value table.
- 积矩相关系数 (PMCC):公式表提供。检验相关系数是否为零,需查临界值表。
A significant result means there is sufficient evidence to reject H₀ at the given significance level. If not significant, you do not accept H₀; you simply fail to reject it.
显著的结果表明在给定显著性水平下有足够证据拒绝 H₀。若不显著,不能接受 H₀,而只能说没有足够证据拒绝它。
9. Mechanics: Kinematics (SUVAT) | 力学:运动学 (SUVAT)
The SUVAT equations link displacement, initial velocity, final velocity, acceleration, and time. Only apply them when acceleration is constant.
SUVAT 方程联系位移、初速度、末速度、加速度和时间。仅当加速度恒定时方可使用。
s = ut + ½at², v = u + at, v² = u² + 2as, s = ½(u + v)t
s = ut + ½at², v = u + at, v² = u² + 2as, s = ½(u + v)t
- Choose the equation that includes the three known quantities and the unknown you need. Write a list of ‘suvat’ values first.
- 先列出五个量的值(未知用?),然后选择包含三个已知量与所求量的方程。
- If a particle is projected vertically, a = ±g (usually −9.8 m s⁻² if upward is positive). Speed is a scalar, velocity is a vector.
- 物体竖直上抛时,a = ±g(通常取向上为正,则 a = −9.8 m s⁻²)。速率是标量,速度是矢量。
- For problems involving two connected particles, consider each separately or treat the whole system, and use F = ma.
- 涉及两个相连物体的问题,可分别分析或整体考虑,均需使用 F = ma。
Always state the positive direction clearly at the start of a mechanics question. This prevents sign errors throughout.
力学题一开始就明确指定正方向,可有效避免过程中的符号错误。
10. Mechanics: Forces, Moments, and Newton’s Laws | 力学:力、力矩与牛顿定律
Draw a clear, labelled force diagram before writing any equations. Resolve forces parallel and perpendicular to the plane if there is an incline.
列方程前先画清晰的受力示意图。有斜面时,将力分解为沿斜面和垂直于斜面方向。
- Newton’s Second Law: F = ma (net force = mass × acceleration). When an object is in equilibrium, net force = 0.
- 牛顿第二定律:F = ma(合力 = 质量 × 加速度)。物体处于平衡状态时,合力为零。
- Friction: F ≤ μR, where μ is the coefficient of friction and R is the normal reaction. At limiting equilibrium, F = μR.
- 摩擦力:F ≤ μR,μ 为摩擦系数,R 为法向反作用力。在极限平衡时 F = μR。
- Moment of a force = force × perpendicular distance from pivot. Clockwise moments are usually taken as negative, anticlockwise positive.
- 力矩 = 力 × 到支点的垂直距离。通常取顺时针力矩为负,逆时针为正。
For a rigid body in equilibrium, the resultant force is zero in all directions AND the total moment about any point is zero. Taking moments about an unknown force can simplify calculations.
刚体平衡要求所有方向合力为零,且对任一点的总力矩为零。对某未知力所在点取矩可以简化计算。
11. Common Exam Pitfalls and Time Management | 常见考试陷阱与时间管理
Even well‑prepared students lose marks through avoidable mistakes. Be systematic, check your work, and allocate your time according to the mark weight of each question.
即便准备充分的学生也会因可以避免的错误而失分。保持解题条理、认真检查,并按题目分值分配时间。
- Algebraic slips: expanding (x ± a)² wrongly as x² ± a². Always write (x ± a)² = x² ± 2ax + a².
- 代数错误:将 (x ± a)² 误写成 x² ± a²。牢记 (x ± a)² = x² ± 2ax + a²。
- Trigonometric ranges: forgetting the period or missing solutions. Sketch the trig graph quickly to see how many solutions exist in the given interval.
- 三角区间错误:漏解或忘掉周期。快速画出三角函数的图像,确定在给定区间内解的数量。
- Units: they matter in mechanics (change all values to SI: m, s, kg). In statistics, ensure probabilities add to 1 and are between 0 and 1.
- 单位:力学中务必转换为国际单位制(m, s, kg)。统计中概率必须介于 0 和 1 之间且总和为 1。
- Calculator mode: check it is in degrees for trig equations unless the question specifies radians. Look for the degree symbol or the word “radians”.
- 计算器模式:除非题目明确要求弧度,否则三角方程使用角度模式。注意看是否有 ° 符号或 “radians” 字样。
In the final 15 minutes, stop working on difficult questions and review your answers. Focus on the quality of your working — clear method marks can compensate for a small slip.
最后 15 分钟不要再纠缠难题,应回顾已完成的答案。清晰的解题过程能帮你拿到方法分,弥补少许计算失误。
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