A-Level CCEA Physics: Calculation Skills Drill | A-Level CCEA 物理：计算题专项训练

📚 A-Level CCEA Physics: Calculation Skills Drill | A-Level CCEA 物理：计算题专项训练

Mastering numerical problems is crucial for success in CCEA A-Level Physics. This drill focuses on the most common calculation types across AS and A2 units, reinforcing equation recall, unit conversion, and systematic problem-solving approaches. Work through each worked example to build confidence and accuracy.

掌握数值计算题对于 CCEA A-Level 物理考试成功至关重要。本专项训练聚焦 AS 和 A2 单元中最常见的计算题型，强化公式记忆、单位转换和系统的解题方法。通过每个典型例题的练习，提升信心和准确性。

1. Kinematics: SUVAT Equations | 运动学：匀加速直线运动方程

A cyclist accelerates uniformly from 3 m/s to 9 m/s while covering a distance of 30 m. Determine the acceleration and the time taken.

题目：自行车手从 3 m/s 匀加速至 9 m/s，位移为 30 m。求加速度和所用时间。

Step 1 – Identify knowns: initial velocity u = 3 m/s, final velocity v = 9 m/s, displacement s = 30 m.

步骤1 – 确定已知量：初速度 u = 3 m/s，末速度 v = 9 m/s，位移 s = 30 m。

Step 2 – Choose the equation that does not contain time:

v² = u² + 2as

步骤2 – 选用不含时间的方程为：v² = u² + 2as。

Step 3 – Rearrange and substitute: a = (v² − u²) / (2s) = (9² − 3²) / (2 × 30) = (81 − 9) / 60 = 72/60 = 1.2 m/s². The positive sign confirms acceleration in the direction of motion.

步骤3 – 移项代入：a = (v² − u²) / (2s) = (9² − 3²) / (2 × 30) = (81 − 9) / 60 = 72/60 = 1.2 m/s²。正号表示加速度与运动方向相同。

Step 4 – Find time using v = u + at → t = (v − u) / a = (9 − 3) / 1.2 = 6 / 1.2 = 5.0 s.

步骤4 – 用 v = u + at 求时间 → t = (v − u) / a = (9 − 3) / 1.2 = 6 / 1.2 = 5.0 s。

A helpful summary of the five SUVAT variables is shown in the table below. Always check that all quantities are in SI units before substituting.

下表总结了五个 SUVAT 变量。代入前务必确认所有量均已转换为国际单位制。