📚 PDF资源导航

AS Mathematics Unit 1 June 2019 Mark Scheme Knowledge Points | AS 数学 Unit 1 2019年6月评分方案知识点精讲

📚 AS Mathematics Unit 1 June 2019 Mark Scheme Knowledge Points | AS 数学 Unit 1 2019年6月评分方案知识点精讲

The June 2019 AS Mathematics Unit 1 exam covers core pure mathematics topics such as algebra, coordinate geometry, differentiation, integration, and sequences. By examining the official mark scheme, students can understand precisely how method (M), accuracy (A), and independent (B) marks are awarded. This article unpacks the key knowledge points highlighted by the mark scheme, offering targeted revision insights and pointing out common errors that lead to mark loss.

2019年6月AS数学单元1考试涵盖代数、坐标几何、微分、积分和数列等核心纯数主题。通过研究官方评分方案,学生可以准确理解方法分(M)、准确分(A)和独立分(B)的授予方式。本文深入剖析评分方案中强调的关键知识点,提供有针对性的复习思路,并指出导致失分的常见错误。

1. Simplifying Rational Expressions | 分式化简

The mark scheme often awards an M1 mark for the correct attempt to factorise the numerator and denominator of an algebraic fraction. A subsequent A1 is given for the fully simplified expression after cancelling common factors. In the June 2019 paper, candidates were expected to recognise difference of two squares or common linear factors.

评分方案通常对正确尝试因式分解代数分式的分子和分母给予M1方法分。随后,对约去公因式后完全化简的表达式给予A1准确分。在2019年6月的试卷中,考生需识别平方差公式或常见的线性因式。

A typical error is to cancel terms before factorising, such as incorrectly cancelling an x from a binomial, which gains no method credit. You must always fully factorise first, then look for matching factors in the numerator and denominator. For example, (x²-4)/(x²-5x+6) simplifies to (x+2)(x-2)/(x-2)(x-3) = (x+2)/(x-3), with the mark scheme requiring the intermediate factorised step to award M1.

一个典型错误是在因式分解前先约分,比如错误地从二项式中约去x,这样得不到方法分。你必须首先完全因式分解,然后再寻找分子分母中的相同因式。例如,(x²-4)/(x²-5x+6) 化简为 (x+2)(x-2)/(x-2)(x-3) = (x+2)/(x-3),评分方案要求展示中间的因式分解步骤才授予M1分。


2. Factorising Quadratic Expressions | 二次式的因式分解

Many mark scheme points depend on factorising quadratic expressions of the form ax²+bx+c. The M1 mark is awarded for a valid attempt, such as finding two numbers that multiply to ac and add to b, or using the quadratic formula to find roots and then working backwards. The A1 is for the correct factorised form.

许多评分方案要点依赖于对形如ax²+bx+c的二次式进行因式分解。M1方法分授予有效的尝试,比如找出两个数乘积为ac且和为b,或者使用二次公式求出根然后反向写出因式。A1准确分授予正确的因式分解形式。

For simpler quadratics with a=1, look for two integers whose product is c and sum is b. For example, x²-5x+6 = (x-2)(x-3). When a≠1, a systematic grouping method is expected. Errors often occur when signs are mishandled or when the product-sum relationship is reversed. The June 2019 scheme penalised giving factors that expand to the wrong constant term.

对于a=1的简单二次式,寻找两个整数使其乘积为c且和为b。例如,x²-5x+6 = (x-2)(x-3)。当a≠1时,需要使用系统的分组法。常见错误包括符号处理失误或乘积和关系颠倒。2019年6月的评分方案对展开后常数项不正确的因式扣分。


3. Completing the Square and Vertex Form | 配方法与顶点式

Completing the square is tested frequently, and the mark scheme splits marks for method and final form. The M1 is given for correctly writing the quadratic as a(x+b/(2a))² + …, while the A1 requires the fully simplified form a(x+p)²+q. This skill is also used to identify the vertex of a parabola.

配方法经常被考查,评分方案将方法分和最终形式分分开。M1分授予正确将二次式写成a(x+b/(2a))² + …的过程,而A1分要求写成完全化简的形式a(x+p)²+q。这一技巧也用于确定抛物线的顶点。

For x²+6x+2, completing the square gives (x+3)² -7. Candidates who forget to adjust the constant term correctly lose the accuracy mark. The June 2019 mark scheme shows that even a sign error in the constant, such as writing +7 instead of -7, forfeits the A1, though the M1 may still be awarded if the previous step was visible.

对于x²+6x+2,配方得到(x+3)² -7。忘记正确调整常数项的考生会失去准确分。2019年6月的评分方案显示,即使常数符号错误(如写成+7而非-7),也会失去A1分,但如果之前的步骤可见,M1分仍可能获得。


4. The Discriminant and Nature of Roots | 判别式与根的性质

The discriminant Δ = b²-4ac determines the nature of the roots of a quadratic equation. The mark scheme often awards B1 or M1 for writing the discriminant equation and A1 for solving it correctly to find an unknown coefficient or parameter.

判别式Δ = b²-4ac决定二次方程根的性质。评分方案常对写出判别式方程授予B1或M1分,并对正确求解以找到未知系数或参数授予A1分。

Key conditions are: Δ > 0 for two distinct real roots, Δ = 0 for one repeated real root, and Δ < 0 for no real roots. In inequalities involving a parameter, setting Δ = 0 and solving yields critical values. A common mistake in June 2019 was misidentifying coefficients when substituting into b²-4ac, especially when terms are rearranged.

关键条件:Δ>0有两个不等实根,Δ=0有一个重实根,Δ<0没有实根。在含有参数的不等式中,令Δ=0并求解得到临界值。2019年6月的一个常见错误是在代入b²-4ac时误判系数,尤其是项经过移项后。


5. Solving Quadratic Equations | 解二次方程

The three standard methods – factorisation, quadratic formula, and completing the square – all appear in mark schemes. A method mark is given for substituting values into the correct formula or for an appropriate factorisation attempt. Accuracy marks are for the correct roots, often requiring both explicit values.

三种标准方法——因式分解、二次公式和配方法——都出现在评分方案中。方法分授予将数值代入正确公式或进行适当因式分解的尝试。准确分授予正确的根,通常需要写出两个明确的值。

The quadratic formula is especially helpful when factorisation is not straightforward. The formula, x = (-b ± √(b²-4ac)) / (2a), must be used with care, especially regarding the sign of b and the entire numerator over 2a. The June 2019 scheme awarded M1 for correct substitution even if a simplification error occurred later.

当不易因式分解时,二次公式特别有用。公式为:

x = (-b ± √(b² – 4ac)) / (2a)

使用此公式需格外小心,尤其是b的符号以及整个分子除以2a。2019年6月的方案即便在后续化简错误时,也对正确的代入给予M1分。


6. Quadratic Inequalities | 二次不等式

Solving quadratic inequalities builds on solving equations and understanding the shape of the parabola. The mark scheme typically requires finding critical values, drawing a sketch or using a sign table, and then writing the solution set. M1 is for the critical values, and A1 for the correct interval notation.

求解二次不等式建立在解方程和理解抛物线形状的基础上。评分方案通常要求找出临界值、画草图或使用符号表,然后写出解集。M1分授予临界值的求解,A1分授予正确的区间表示。

For example, to solve x²-3x-4>0, first solve x²-3x-4=0 to get x=4 or x=-1. The curve y=x²-3x-4 is a ∪-shaped parabola, so y>0 when x<-1 or x>4. Many candidates in June 2019 lost the final A1 by writing -1

例如,解x²-3x-4>0,先解x²-3x-4=0得x=4或x=-1。曲线y=x²-3x-4是开口向上的抛物线,因此当x<-1或x>4时y>0。2019年6月许多考生因写成-1


7. Coordinate Geometry: Straight Lines | 坐标几何:直线

Straight-line problems involve finding gradients, distances, midpoints, and equations. The mark scheme awards method marks for using the correct formulas: gradient m = (y₂-y₁)/(x₂-x₁), distance d = √[(x₂-x₁)²+(y₂-y₁)²], and midpoint M = ((x₁+x₂)/2, (y₁+y₂)/2). An equation of a line often comes via y-y₁ = m(x-x₁).

直线问题涉及求斜率、距离、中点和方程。评分方案对使用正确公式授予方法分:斜率m = (y₂-y₁)/(x₂-x₁),距离d = √[(x₂-x₁)²+(y₂-y₁)²],中点M = ((x₁+x₂)/2, (y₁+y₂)/2)。直线方程通常通过y-y₁ = m(x-x₁)得出。

Examiners look for clear substitution and simplification. When finding a perpendicular line, remember that the product of gradients is -1, so the perpendicular gradient m_perp = -1/m. A common slip is to forget the negative sign. In June 2019, some candidates lost marks by using the perpendicular gradient for the tangent instead of the normal, or vice versa.

考官看重清晰的代入和化简。求垂线时,记住斜率乘积为-1,因此垂线斜率m_perp = -1/m。常见的疏忽是忘记负号。2019年6月,一些考生因混淆切线和法线、用错了垂直斜率而失分。


8. Differentiation: Power Rule and Tangents | 微分:幂法则与切线

Basic differentiation follows the rule: if y = xⁿ, then dy/dx = nxⁿ⁻¹. The mark scheme gives an M1 for reducing each power by one and multiplying by the original power. For polynomials, you differentiate term by term. The derivative gives the gradient of the tangent at a point.

基本微分遵循法则:若y = xⁿ,则dy/dx = nxⁿ⁻¹。评分方案对将每个幂指数减1并乘以原指数给予M1分。对于多项式,逐项微分。导数给出某点切线的斜率。

To find the equation of a tangent at x = a, first find y(a) to get the point, then compute m = dy/dx at x = a, and use y-y₁ = m(x-x₁). For a normal, use -1/m. The June 2019 mark scheme shows that full marks were only given when all steps were coherent, with the derivative correctly evaluated and the final equation simplified.

求x=a处的切线方程,先求y(a)得到切点,然后计算m = dy/dx在x=a的值,再用y-y₁ = m(x-x₁)。对于法线,使用-1/m。2019年6月的评分方案显示,只有在所有步骤连贯、导数计算正确且最终方程化简的情况下才给满分。


9. Integration: Indefinite Integrals and Finding Constants | 积分:不定积分与求常数

Integration reverses differentiation. The power rule for integration states: ∫ xⁿ dx = (xⁿ⁺¹)/(n+1) + C, where C is the constant of integration. The mark scheme awards M1 for increasing the power by one and dividing by the new power, and A1 for a correct expression including ‘+ C’.

积分是微分的逆运算。积分的幂法则为:∫ xⁿ dx = (xⁿ⁺¹)/(n+1) + C,其中C为积分常数。评分方案对将幂指数加1并除以新指数给予M1分,对包含“+ C”的正确表达式给予A1分。

If a curve passes through a given point, you substitute coordinates to find C. The June 2019 scheme frequently gave A1 only if C was found and the final equation of the curve was stated explicitly. Omitting the constant or forgetting to integrate all terms are common errors that result in the loss of both method and accuracy marks.

如果曲线经过给定点,代入坐标求C。2019年6月的方案经常只在求出C并明确写出最终曲线方程时才给A1分。漏掉常数或忘记对所有项积分是常见的导致方法和准确分双失的错误。


10. Arithmetic Sequences and Series | 等差数列与级数

The nth term of an arithmetic sequence is un = a + (n-1)d, and the sum of the

Published by TutorHao | AS Mathematics Revision Series | aleveler.com

更多咨询请联系16621398022(同微信)

Comments

屏轩国际教育cambridge primary/secondary checkpoint, cat4, ukiset,ukcat,igcse,alevel,PAT,STEP,MAT, ibdp,ap,ssat,sat,sat2课程辅导,国外大学本科硕士研究生博士课程论文辅导

This site uses Akismet to reduce spam. Learn how your comment data is processed.

Discover more from aleveler.com

Subscribe now to keep reading and get access to the full archive.

Continue reading