📚 GCSE OCR PE: Unit Test Mock Paper Walkthrough | GCSE OCR 体育：单元测试模拟卷解析
This walkthrough covers a typical OCR GCSE Physical Education unit test on Applied Anatomy and Physiology. Each question is broken down with answers, examiner tips, and links to the specification. Use this to identify gaps in your knowledge and refine exam technique.
本文逐题解析一份典型的OCR GCSE体育应用解剖学与生理学单元测试模拟卷。每题都给出了答案、考官建议和课程大纲链接。用它来发现知识漏洞并打磨应试技巧。
1. Question 1: Functions of the Skeleton | 第1题：骨骼的功能
Question: Which of the following is NOT a recognised function of the human skeleton?
A. Protection of vital organs
B. Heat production
C. Mineral storage
D. Blood cell production
问题：以下哪项不是人类骨骼公认的功能？
A. 保护重要器官
B. 产热
C. 矿物质储存
D. 血细胞生成
Correct answer: B. Heat production is not a function of the skeleton; it is a result of muscular contraction and metabolic processes.
正确答案：B。产热不是骨骼的功能，它是肌肉收缩和代谢过程的结果。
The five primary functions of the skeleton are support, protection, movement (acting as levers), mineral storage (calcium and phosphorus), and haematopoiesis (blood cell production in bone marrow). Heat generation is linked to shivering and muscle activity, not to bones.
骨骼的五个主要功能是支撑、保护、运动（充当杠杆）、矿物质储存（钙和磷）以及造血功能（骨髓中血细胞生成）。热量产生与颤抖和肌肉活动有关，与骨骼无关。
Many students lose marks by selecting ‘mineral storage’, assuming it is not a function. Remember bones store and release minerals like calcium on demand.
许多学生因误选‘矿物质储存’而丢分，认为那不是一项功能。请记住骨骼可按需储存和释放钙等矿物质。
2. Question 2: Types of Bones | 第2题：骨骼的分类
Question: State the bone type for each of the following examples: femur, carpals, and vertebrae.
问题：写出以下骨骼各自的类型：股骨、腕骨和椎骨。
The femur is a long bone, the carpals are short bones, and the vertebrae are irregular bones.
股骨是长骨，腕骨是短骨，椎骨是不规则骨。
Long bones act as levers for movement; short bones provide weight-bearing support and shock absorption; irregular bones protect the spinal cord and enable flexibility.
长骨作为运动杠杆；短骨提供承重支撑和减震；不规则骨保护脊髓并实现灵活性。
Examiners often ask for classifications along with a function or an example. Be prepared to give both.
考官经常要求同时给出分类和功能或例子，要做好准备。
3. Question 3: Synovial Joints and Movement | 第3题：滑膜关节与运动
Question: Identify the type of synovial joint found at the elbow and name the movement that occurs during the upward phase of a bicep curl.
问题：指出肘部的滑膜关节类型，并说出肱二头肌弯举上举阶段发生的动作名称。
The elbow is a hinge joint. The movement is flexion (bending the arm, decreasing the angle at the joint).
肘关节是铰链关节。该动作为屈曲（弯曲手臂，减小关节角度）。
Hinge joints allow movement in one plane only – flexion and extension. The elbow, knee, and ankle are typical examples. During a bicep curl, the biceps brachii contracts, pulling the radius and ulna to flex the joint.
铰链关节只允许在一个平面上运动——屈和伸。肘、膝和踝关节是典型例子。在肱二头肌弯举中，肱二头肌收缩，牵拉桡骨和尺骨使关节屈曲。
A common error is confusing the type of joint (ball-and-socket for shoulder) or stating extension instead of flexion for the upward phase.
常见错误是混淆关节类型（肩关节是球窝关节）或在上举阶段写成伸而不是屈。
4. Question 4: Antagonistic Muscle Pairs | 第4题：拮抗肌对
Question: During the downward phase of a push-up, which muscle acts as the agonist at the elbow joint? Explain the role of the antagonist.
问题：在做俯卧撑下降阶段时，肘关节处的主动肌是哪块？解释拮抗肌的作用。
The agonist is the biceps brachii. The antagonist is the triceps brachii, which relaxes to allow the movement controlled by the agonist.
主动肌是肱二头肌。拮抗肌是肱三头肌，它放松以使主动肌控制的运动得以进行。
In the downward phase, the elbow flexes. The biceps acts as the agonist (prime mover), contracting eccentrically to control the descent. The triceps lengthens and relaxes as the antagonist. Eccentric contraction is when the muscle lengthens under tension.
在下降阶段，肘关节屈曲。肱二头肌作为主动肌（原动肌），进行离心收缩以控制下降。肱三头肌作为拮抗肌拉长并放松。离心收缩是指肌肉在张力下拉长。
Students often assume the triceps is always the agonist in a push-up, but this is only during the upward pushing phase (extension).
学生常以为俯卧撑中肱三头肌总是主动肌，但那只是在向上推起阶段（伸肘）。
5. Question 5: Cardiac Output Calculation | 第5题：心输出量计算
Question: Write the equation for cardiac output (Q). Then calculate Q for a performer with a stroke volume of 75 ml/beat and a heart rate of 70 beats per minute. Give your answer in litres per minute.
问题：写出心输出量（Q）的公式。然后为一名每搏输出量为75毫升/次、心率为70次/分钟的运动员计算Q值，以升/分钟为单位作答。
Cardiac Output (Q) = Stroke Volume (SV) × Heart Rate (HR)
心输出量（Q）= 每搏输出量（SV）× 心率（HR）
Q = 75 ml × 70 bpm = 5250 ml/min = 5.25 litres per minute.
Q = 75毫升 × 70次/分 = 5250毫升/分 = 5.25升/分钟。
Remember to convert millilitres to litres by dividing by 1000. Cardiac output is the volume of blood pumped by the heart per minute. The equation is a classic calculation in OCR GCSE PE.
记住将毫升换算为升需除以1000。心输出量是心脏每分钟泵出的血量。该公式是OCR GCSE体育中的经典计算题。
6. Question 6: Mechanics of Breathing (Inspiration) | 第6题：呼吸机制（吸气）
Question: Describe the changes that occur in the thorax during inspiration at rest.
问题：描述平静吸气时胸腔内发生的变化。
During inspiration, the diaphragm contracts and flattens, while the external intercostal muscles contract, pulling the rib cage up and out. This increases the volume of the thoracic cavity, causing the pressure inside to decrease below atmospheric pressure. Air rushes into the lungs to equalise the pressure.
吸气时，膈肌收缩变平，同时肋间外肌收缩，将胸廓向上向外提拉。这增大了胸腔容积，使内部压力降至大气压以下。空气涌入肺部使压力平衡。
Key terms to include: diaphragm, external intercostals, volume increase, pressure decrease. Do not confuse with expiration, where the diaphragm relaxes and the internal intercostals may be used.
关键词要包括：膈肌、肋间外肌、容积增加、压力降低。不要与呼气混淆，呼气时膈肌放松，可能用到肋间内肌。
7. Question 7: Aerobic vs Anaerobic Exercise | 第7题：有氧运动与无氧运动
Question: Complete the table to compare aerobic and anaerobic respiration.
问题：完成下表，比较有氧呼吸与无氧呼吸。
| Feature / 特征 | Aerobic / 有氧 | Anaerobic / 无氧 |
|---|---|---|
| Oxygen used / 是否用氧 | Yes / 是 | No / 否 |
| Fuel source / 燃料 | Carbohydrates and fats / 碳水化合物和脂肪 | Carbohydrates only / 仅碳水化合物 |
| By-products / 副产物 | CO₂ and H₂O / 二氧化碳和水 | Lactic acid / 乳酸 |
| Intensity / 强度 | Low to moderate / 低至中等 | High / 高 |
| Duration / 持续时间 | Long / 长 | Short (seconds to a few minutes) / 短（数秒至几分钟） |
| Energy yield / 能量产出 | High (36-38 ATP per glucose) / 高（每分子葡萄糖36-38 ATP） | Low (2 ATP per glucose) / 低（每分子葡萄糖2 ATP） |
Examiners frequently test this comparison. Remember that anaerobic respiration produces lactic acid, which causes fatigue. EPOC (Excess Post-exercise Oxygen Consumption) is the oxygen required to remove lactic acid and restore the body to its resting state.
考官经常考这个对比。记住无氧呼吸产生乳酸，导致疲劳。EPOC（运动后过量氧耗）是清除乳酸并让身体恢复到安静状态所需的额外氧气。
A common mistake is stating that anaerobic respiration produces more energy; in fact it is far less efficient but re-synthesises ATP rapidly for short bursts.
常见错误是写无氧呼吸产能更多；实际上它效率低得多，但能快速再合成ATP以应对短时间爆发。
8. Question 8: Long-term Effects of Exercise on the Cardiovascular System | 第8题：长期运动对心血管系统的影响
Question: Explain how regular aerobic training affects the heart’s resting values.
问题：解释定期的有氧训练如何影响心脏的安静状态数值。
Regular aerobic training leads to cardiac hypertrophy (increased heart size and strength), which results in a higher stroke volume. Consequently, resting heart rate decreases because the heart pumps more blood per beat. Blood pressure may also lower at rest. This is often called an athlete’s heart.
定期的有氧训练导致心脏肥大（心脏体积和力量增加），从而提高了每搏输出量。因此，安静心率会下降，因为心脏每次搏动泵出更多血液。安静时血压也可能降低。这常被称为运动员心脏。
Link these adaptations to improved performance: a larger stroke volume means the heart works more efficiently, and the performer can sustain higher intensities for longer.
将这些适应与运动表现联系起来：更大的每搏输出量意味着心脏工作效率更高，运动员能更长时间维持较高强度的运动。
9. Question 9: Planes and Axes of Movement | 第9题：运动平面与轴
Question: A gymnast performs a forward somersault. Identify the plane of movement and the axis of rotation used.
问题：一名体操运动员做了一个前空翻。指出所用的运动平面和旋转轴。
The movement occurs in the sagittal plane around the transverse axis.
该运动发生在矢状面，绕额状轴（横轴）进行。
A forward somersault involves rotation about the transverse axis (left to right through the body) combined with movement in the sagittal plane (dividing the body into left and right). Common alternatives: a cartwheel moves in the frontal plane around the sagittal axis; a 360-degree spin uses the transverse plane and longitudinal axis.
前空翻涉及绕额状轴（从左至右穿过身体）旋转，结合在矢状面（将身体分为左右两部分）的运动。常见对比：侧手翻是额状面绕矢状轴旋转；360度转体是水平面绕垂直轴旋转。
Students often mix up the plane and axis. Use the rule: sagittal plane pairs with transverse axis for forwards/backwards motions; frontal plane pairs with sagittal axis for sideways movements; transverse plane pairs with longitudinal axis for twisting.
学生常混淆平面和轴。记住规则：矢状面对应额状轴用于前后运动；额状面对应矢状轴用于侧向运动；水平面对应垂直轴用于旋转。
10. Question 10: Short-term Responses to Exercise (Tidal Volume) | 第10题：运动时的短期反应（潮气量）
Question: Define tidal volume and explain how it changes during a bout of moderate exercise.
问题：定义潮气量，并解释在中等强度运动过程中它如何变化。
Tidal volume is the volume of air inhaled or exhaled in one normal breath. During moderate exercise, tidal volume increases significantly to supply more oxygen to the working muscles and remove excess carbon dioxide. The increase is achieved by breathing deeper and using more of the lungs’ capacity.
潮气量是一次正常呼吸中吸入或呼出的空气量。在中等强度运动期间，潮气量会显著增加，以向工作肌肉供应更多氧气并清除多余的二氧化碳。这种增加是通过加深呼吸、更多地利用肺活量来实现的。
At the onset of exercise, depth and rate of breathing increase. Tidal volume rises from a resting value of about 0.5 litres to perhaps 2–3 litres in trained individuals. Residual volume and vital capacity are related concepts often tested together.
运动开始时，呼吸深度和频率都会增加。潮气量从安静时的约0.5升上升至训练有素者可达2-3升。残气量和肺活量是相关概念，经常一起考查。
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