📚 Solving Linear Equations | 解一元一次方程
Solving linear equations is a core IGCSE algebra skill. It allows you to find the unknown value that makes an equation true, using inverse operations and the balance method.
解一元一次方程是 IGCSE 代数中的核心技能。它让你通过逆运算和天平法求出使等式成立的未知数值。
1. What Is a Linear Equation? | 什么是一元一次方程
A linear equation has variables raised only to the power of 1. Its graph is a straight line.
一元一次方程中,未知数的最高次数仅为 1。它的图像是一条直线。
General form of a linear equation in one variable:
一元一次方程的一般形式为:
ax + b = 0, a ≠ 0
Examples include 2x + 6 = 14, 5y − 3 = 2y + 9, and x/4 + 1 = 3.
例如:2x + 6 = 14、5y − 3 = 2y + 9、x/4 + 1 = 3。
2. The Balance Method | 天平法
Think of an equation as a balanced scale. Whatever you do to one side, you must also do to the other side.
把等式看作一架平衡的天平。你对一边做任何运算,另一边也必须做同样的运算。
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Add or subtract the same number from both sides.
两边同时加上或减去同一个数。
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Multiply or divide both sides by the same non-zero number.
两边同时乘以或除以同一个不为零的数。
This keeps the equation equivalent to the original equation, so the solution does not change.
这样方程仍与原方程同解,因此解不会改变。
3. One-Step Equations | 一步方程
Use one inverse operation to isolate the variable.
使用一个逆运算就可以把未知数单独留在一边。
Example: x + 7 = 15.
例子:x + 7 = 15。
x + 7 − 7 = 15 − 7 → x = 8
Example: 4x = 28.
例子:4x = 28。
4x ÷ 4 = 28 ÷ 4 → x = 7
| Operation in equation | Inverse operation to use |
| + a | − a |
| − a | + a |
| × a | ÷ a |
| ÷ a | × a |
The inverse operation reverses the one that is applied to the variable.
逆运算可以抵消作用在未知数上的运算。
4. Two-Step Equations | 两步方程
For equations like 3x + 5 = 20, undo the addition or subtraction first, then undo multiplication or division.
对于 3x + 5 = 20 这类方程,先消去加或减,再消去乘或除。
Worked solution:
解题过程:
3x + 5 − 5 = 20 − 5 → 3x = 15 → x = 5
Always reverse the order of operations: start with the outside operation.
一定要逆着运算顺序:先处理最外层的运算。
5. Expanding Brackets First | 先去括号
If an equation contains brackets, expand them before using the balance method.
如果方程中含有括号,先用乘法分配律去括号,再使用天平法。
Example: 2(x + 3) = 16.
例子:2(x + 3) = 16。
2x + 6 = 16 → 2x = 10 → x = 5
Be careful when a negative sign is in front of a bracket: −(x − 4) becomes −x + 4.
括号前有负号时要特别小心:−(x − 4) 应变为 −x + 4。
6. Variables on Both Sides | 未知数在两边
When variables appear on both sides, collect all variable terms on one side and constants on the other.
当未知数出现在两边时,把所有的未知数项移到一边,常数项移到另一边。
Example: 7x − 4 = 3x + 8.
例子:7x − 4 = 3x + 8。
7x − 3x = 8 + 4 → 4x = 12 → x = 3
Remember: when you move a term across the equals sign, its sign changes.
记住:把一项移到等号另一边时,符号要改变。
7. Equations with Fractions | 含分数的方程
Multiply every term by the lowest common denominator to clear fractions.
用最小公分母乘以每一项,以消去分母中的分数。
Example: x/3 + 2 = 7.
例子:x/3 + 2 = 7。
3 × (x/3 + 2) = 3 × 7 → x + 6 = 21 → x = 15
Example: (2x + 1)/5 = 3.
例子:(2x + 1)/5 = 3。
2x + 1 = 15 → 2x = 14 → x = 7
8. Checking Your Answer | 检验答案
Substitute your solution back into the original equation to confirm both sides are equal.
把解代入原方程,确认两边相等。
Example: check x = 5 in 3x + 5 = 20.
例子:在 3x + 5 = 20 中检验 x = 5。
3 × 5 + 5 = 15 + 5 = 20 ✓
Checking is especially important in exams to avoid sign or arithmetic errors.
考试中检验尤其重要,可以避免符号或计算错误。
9. Linear Equations in Word Problems | 应用题中的一次方程
Translate the words into an equation, solve it, and interpret the answer in context.
把文字转化为方程,求解,并结合题意解释答案。
Example: The sum of three consecutive numbers is 42. Find the numbers.
例子:三个连续数的和是 42。求这三个数。
Let the numbers be x, x + 1, and x + 2.
设三个数为 x、x + 1、x + 2。
x + (x + 1) + (x + 2) = 42 → 3x + 3 = 42 → x = 13
The numbers are 13, 14, and 15.
三个数是 13、14、15。
10. Common Mistakes to Avoid | 常见错误
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Forgetting to apply an operation to both sides.
忘记对两边同时进行同一运算。
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Changing the sign incorrectly when moving terms.
移项时符号改变错误。
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Expanding brackets with negative signs carelessly.
括号前为负号时去括号粗心。
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Multiplying only some terms by the common denominator.
乘以公分母时只乘了部分项。
Slow down, show working, and check your answer to avoid these errors.
减慢速度、写出步骤,并检验答案,以避免这些错误。
11. Summary and Exam Tips | 总结与考试提示
Use the balance method, clear brackets and fractions first, collect variable terms on one side, then check.
使用天平法,先去括号和分母,把未知数项移到一边,然后检验。
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Show every step to earn method marks.
写出每一步以取得过程分。
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Write the final answer clearly as x = …
最后答案清楚地写成 x = …
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Substitute back to check your solution.
把解代回原式进行检验。
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