Quadratic Functions and Equations | 二次函数与方程

📚 Quadratic Functions and Equations | 二次函数与方程

Quadratic functions and equations form the backbone of IGCSE algebra. Understanding their graphs, transformations, and solution methods is essential for achieving top marks in Paper 2 and Paper 4.

二次函数与方程是 IGCSE 代数部分的核心内容。掌握它们的图像、变换及求解方法,是在 Paper 2 和 Paper 4 中获得高分的必要基础。


1. Standard Form and Vertex Form | 标准形式与顶点形式

A quadratic function is usually written in standard form:

二次函数通常写成标准形式:

f(x) = ax² + bx + c , a ≠ 0

Every quadratic function can also be expressed in vertex form: f(x) = a(x − h)² + k, where (h, k) is the vertex of the parabola. The value of a determines the direction and width of the curve.

每一个二次函数也可以写成顶点形式:f(x) = a(x − h)² + k,其中 (h, k) 是抛物线的顶点。系数 a 决定曲线的开口方向与宽窄。


2. The Graph of a Quadratic | 二次函数的图像

The graph of a quadratic function is always a parabola. If a > 0, the parabola opens upwards and has a minimum point; if a < 0, it opens downwards and has a maximum point.

二次函数的图像始终是一条抛物线。若 a > 0,抛物线开口向上,存在最小值点;若 a < 0,抛物线开口向下,存在最大值点。

  • The axis of symmetry is the vertical line x = −b/(2a).

    对称轴是竖直线 x = −b/(2a)。

  • The y-intercept is the point (0, c).

    y 截距是点 (0, c)。

  • The x-intercepts, if they exist, are the real roots of the equation f(x) = 0.

    x 截距(若存在)是方程 f(x) = 0 的实数根。


3. Completing the Square | 配方法

Completing the square converts standard form into vertex form. This technique is frequently tested in IGCSE, especially for finding turning points and solving equations.

配方法将标准形式转化为顶点形式。这是 IGCSE 的高频考点,常用于求极值点和解方程。

ax² + bx + c = a(x + b/(2a))² + c − b²/(4a)

For example, f(x) = 2x² + 8x + 5 becomes f(x) = 2(x + 2)² − 3, so the vertex is at (−2, −3).

例如,f(x) = 2x² + 8x + 5 可化为 f(x) = 2(x + 2)² − 3,因此顶点为 (−2, −3)。


4. Solving by Factorisation | 因式分解法

When the quadratic expression can be factorised into two linear factors, the equation is solved by setting each factor equal to zero.

当二次式可以分解为两个一次因式时,将每个因式等于零即可解出方程。

x² − 5x + 6 = 0 → (x − 2)(x − 3) = 0 → x = 2 or 3

Always check whether the coefficient a is not 1, and factor out any common factor first.

注意,当 a ≠ 1 时需格外小心,并应首先提取公因子。


5. The Quadratic Formula | 求根公式

For any quadratic equation ax² + bx + c = 0, the roots are given by the quadratic formula:

对于任意一元二次方程 ax² + bx + c = 0,其根由求根公式给出:

x = (−b ± √(b² − 4ac)) / (2a)

This formula works for all cases, including irrational and complex roots. In IGCSE, you must be able to substitute values correctly and simplify surds.

该公式适用于一切情形,包括无理根与复数根。在 IGCSE 中,你须能正确代入数值并化简根式。


6. The Discriminant | 判别式

The discriminant, denoted by Δ, is the expression under the square root in the quadratic formula:

判别式用 Δ 表示,即求根公式中根号内的表达式:

Δ = b² − 4ac

Δ > 0 Two distinct real roots 两个不等实根
Δ = 0 One repeated real root 一个重根
Δ < 0 No real roots 无实根

The discriminant also tells us whether the parabola intersects the x-axis at two points, touches it, or never crosses it.

判别式还决定抛物线与 x 轴有两个交点、相切还是无交点。


7. Sum and Product of Roots | 根与系数的关系

If α and β are the roots of ax² + bx + c = 0, then:

若 α 和 β 是方程 ax² + bx + c = 0 的两个根,则:

α + β = −b/a and αβ = c/a

This relationship is frequently used in questions that ask you to find symmetric expressions such as α² + β², without solving the equation.

这一关系常用于求出对称式(如 α² + β²)的值,而不需要具体解方程。


8. Solving Simultaneous Equations with Quadratics | 二次方程组求解

IGCSE often tests linear-quadratic simultaneous equations. The standard method is substitution: replace y in the linear equation, forming a single quadratic equation in one variable.

IGCSE 经常考查一次-二次联立方程组。标准方法是代入法:将一次式中的 y 代入二次式,得到关于单一变量的一元二次方程。

For example, solve y = 2x + 1 and y = x² − 1. Substituting gives:

例如,解方程组 y = 2x + 1 和 y = x² − 1。代入得:

2x + 1 = x² − 1 → x² − 2x − 2 = 0

This quadratic can then be solved using the formula, giving two possible x-values, each with a corresponding y-value.

随后用求根公式解该二次方程,得到两个 x 值,并分别求出对应的 y 值。


9. Applications in Word Problems | 实际应用题

Quadratic equations are used to model projectile motion, area problems, and number puzzles. For example, the product of two consecutive positive integers is 132. The equation is:

二次方程常用于建模抛体运动、面积问题和数字谜题。例如,两个连续正整数的乘积为 132。方程为:

n(n + 1) = 132 → n² + n − 132 = 0

(n + 12)(n − 11) = 0 → n = 11

Always discard negative or physically impossible roots in context.

在具体情境中要注意剔除负数或无实际意义的根。


10. Connecting Graphs and Equations | 图像与方程的呼应

Every question about quadratic equations corresponds to a graphical interpretation. Roots are x-intercepts, the discriminant controls the number of intersections, and the vertex corresponds to the maximum or minimum value.

每一个关于二次方程的问题都对应着图像解释。根是 x 截距,判别式决定交点个数,顶点则对应最大值或最小值。

In the exam, when given a graph, you should be able to read off approximate roots, the y-intercept, and the turning point.

考试中,面对图像题时,你应能读出近似根、y 截距及极值点。


Summary | 总结: Master standard form, completing the square, the quadratic formula, and the discriminant. These four tools unlock every quadratic question in IGCSE Mathematics.

总结:熟练掌握标准形式、配方法、求根公式与判别式,这四大工具能帮你解锁 IGCSE 数学中所有的二次函数与方程问题。


Published by TutorHao | Mathematics Revision Series | aleveler.com

更多咨询请联系16621398022(同微信)

Comments

屏轩国际教育cambridge primary/secondary checkpoint, cat4, ukiset,ukcat,igcse,alevel,PAT,STEP,MAT, ibdp,ap,ssat,sat,sat2课程辅导,国外大学本科硕士研究生博士课程论文辅导

This site uses Akismet to reduce spam. Learn how your comment data is processed.

Discover more from aleveler.com

Subscribe now to keep reading and get access to the full archive.

Continue reading