AS AQA Physics Unit 1 (June 2022) – Exam Paper Walkthrough | AS AQA 物理 Unit 1（2022年6月）考卷解析

📚 AS AQA Physics Unit 1 (June 2022) – Exam Paper Walkthrough | AS AQA 物理 Unit 1（2022年6月）考卷解析

The June 2022 AQA AS Physics Unit 1 examination assessed the core topics of mechanics, materials, waves, and electricity. Candidates were required to recall key definitions, apply equations to unfamiliar situations, and analyse experimental data with precision.

2022年6月AQA AS物理Unit 1试卷考查了力学、材料、波动与电学等核心内容。考生需要准确回忆关键定义、将公式灵活应用于新情境，并对实验数据进行精确分析。

1. Exam Structure and Assessment Objectives | 试卷结构与测评目标

The paper is divided into two sections: Section A consists of multiple-choice questions, while Section B contains structured and extended-response questions. The total time is 1 hour 30 minutes, and the mark total is typically 70.

试卷分为两部分：A部分为选择题，B部分为结构化及扩展作答题目。考试时长为1小时30分钟，满分通常为70分。

Assessment Objective	Description	Approximate Weighting
AO1	Knowledge and understanding of scientific ideas	35%
AO2	Application of knowledge and understanding to familiar and unfamiliar contexts	45%
AO3	Analysis, interpretation, and evaluation of scientific information and experimental methods	20%

Time management is critical. A useful strategy is to spend no more than 20 minutes on Section A, then divide the remaining time between Section B questions. Always leave 5 minutes to check units and significant figures.

时间管理至关重要。建议策略是：A部分用时不超过20分钟，其余时间分配给B部分各题。务必留出5分钟检查单位与有效数字。

2. Section A: Multiple-Choice Questions | 第二部分：选择题

Section A typically contains about 10 multiple-choice questions. These test straightforward recall and simple application. One common question asks for the SI base unit of electric current; the correct answer is the ampere (A).

A部分通常包含约10道选择题，考查基础记忆和简单应用。常见问题之一是“电流的SI基本单位是什么”，正确答案为安培（A）。

Another typical question involves projectile motion. For a ball thrown horizontally at 8.0 m s⁻¹ from a height of 1.25 m, the time of flight is found from the vertical displacement using s = ½gt².

另一个典型问题涉及抛体运动。若球以8.0 m s⁻¹的水平速度从1.25 m高处抛出，其飞行时间可由竖直位移s = ½gt²求得。

1.25 = ½ × 9.81 × t² → t = 0.505 s

The horizontal range is then 8.0 × 0.505 = 4.04 m. In multiple-choice questions, check whether the answer is required to one or two significant figures.

水平射程随后为8.0 × 0.505 = 4.04 m。在选择题中，注意答案是否需要保留一位或两位有效数字。

3. Section B: Structured Questions | 第三部分：结构化题目

Section B usually consists of part (a) to (e) questions that gradually increase in difficulty. A typical first part asks candidates to “Define the moment of a force”, worth one mark. The expected response is the product of force and perpendicular distance from the pivot.

B部分通常为(a)至(e)小题，难度逐步递增。典型的第一问是“定义力的力矩”，分值为1分。标准答案为力与转轴到力的垂直距离的乘积。

Later parts often contain a calculation followed by an explanation. For example, a question may give a beam in equilibrium and ask for the reaction force at a support. This requires applying the principle of moments: sum of clockwise moments equals sum of anticlockwise moments.

后面的部分通常包含一道计算题和一道解释题。例如，题目可能给出处于平衡状态下的横梁，要求计算支点的反作用力。这需要应用力矩原理：顺时针力矩之和等于逆时针力矩之和。

ΣM_clockwise = ΣM_anticlockwise

Always draw a clear diagram if one is not provided, and label distances from the pivot before substituting values.

若题目未提供图示，务必自行绘制清晰示意图，并在代入数值前标出各力到支点的距离。

4. Mechanics: Motion and Forces | 第四部分：力学：运动与力

The laws of constant acceleration are essential. Candidates should be able to rearrange the SUVAT equations and apply them to vertical motion, including sign conventions for upward and downward directions.

匀加速直线运动定律至关重要。考生应能灵活变形SUVAT方程，并将其应用于竖直运动，同时注意上、下方向的正负号约定。

v = u + at, s = ut + ½at², v² = u² + 2as

A common June 2022 style question: a car accelerates uniformly from 12 m s⁻¹ to 24 m s⁻¹ in 6.0 s. Calculate the acceleration and the distance travelled.

类似2022年6月卷的常见问题：一辆汽车在6.0 s内从12 m s⁻¹匀加速到24 m s⁻¹。求加速度和行驶距离。

a = (24 − 12) / 6.0 = 2.0 m s⁻²

s = ½ × (12 + 24) × 6.0 = 108 m

Newton’s second law is often tested with a free-body diagram. If a resultant force of 450 N acts on a trolley of mass 90 kg, the acceleration is 5.0 m s⁻².

牛顿第二定律常配合受力分析图进行考查。若450 N的合力作用在90 kg的小车上，加速度为5.0 m s⁻²。

5. Materials: Density, Hooke’s Law, and Young Modulus | 第五部分：材料：密度、胡克定律与杨氏模量

Materials questions require the distinction between elastic and plastic deformation. Hooke’s law states that force is proportional to extension for a spring within its elastic limit.

材料类题目要求区分弹性形变与塑性形变。胡克定律指出，在弹性限度内，弹簧的力与伸长量成正比。

F = kΔL

Young modulus questions are also common. The defining equation is stress divided by strain:

杨氏模量问题同样常见。其定义方程为应力除以应变：

E = σ / ε = (F / A) / (ΔL / L)

Consider a wire of length 2.0 m and cross-sectional area 2.0 × 10⁻⁷ m², which extends by 2.0 mm when a 50 N load is applied. The stress is 2.5 × 10⁸ Pa and the strain is 1.0 × 10⁻³.

考虑一根长为2.0 m、横截面积为2.0 × 10⁻⁷ m²的金属丝，当施加50 N载荷时伸长了2.0 mm。则应力为2.5 × 10⁸ Pa，应变为1.0 × 10⁻³。

E = 2.5 × 10⁸ / 1.0 × 10⁻³ = 2.5 × 10¹¹ Pa

In the exam, always convert millimetres to metres before substitution, and state the unit as Pa or N m⁻².

考试中，代入前务必把毫米换算成米，并写明单位为Pa或N m⁻²。

6. Waves: Superposition and Stationary Waves | 第六部分：波动：叠加与驻波

The wave equation v = fλ is always worth remembering. For a stationary wave on a string fixed at both ends, the fundamental wavelength is twice the string length.

波动方程v = fλ需要牢记。对于两端固定的弦上的驻波，基波波长为弦长的两倍。

f = v / λ, v = √(T / μ)

Here T is the tension and μ is the mass per unit length. If a string has tension 80 N, mass per unit length 5.0 × 10⁻³ kg m⁻¹, and length 0.50 m, then v = √(80 / 0.005) = 126 m s⁻¹. The fundamental frequency is f = 126 / 1.0 = 126 Hz.

其中T为张力，μ为单位长度质量。若弦的张力为80 N，单位长度质量为5.0 × 10⁻³ kg m⁻¹，长度为0.50 m，则v = √(80 / 0.005) = 126 m s⁻¹。基频为f = 126 / 1.0 = 126 Hz。

For interference questions, describe the conditions for constructive and destructive superposition. Path difference equal to nλ gives constructive interference; (n + ½)λ gives destructive interference.

在干涉问题中，要描述相长叠加与相消叠加的条件。光程差等于nλ时产生相长干涉；(n + ½)λ时产生相消干涉。

7. Electricity: Circuits and Resistivity | 第七部分：电学：电路与电阻率

Electricity questions in Unit 1 focus on current, potential difference, resistance, and series–parallel circuits. In a series circuit, resistance adds: R_total = R₁ + R₂.

Unit 1中的电学问题集中于电流、电势差、电阻以及串并联电路。串联电路中电阻相加：R_total = R₁ + R₂。

R = ρL / A

The resistivity equation is a frequent source of calculation questions. For a copper wire of resistivity 1.7 × 10⁻⁸ Ω m, length 4.0 m, and cross-sectional area 2.0 × 10⁻⁷ m², the resistance is:

电阻率公式是计算题的常见来源。对于一根铜导线，电阻率为1.7 × 10⁻⁸ Ω m，长度为4.0 m，横截面积为2.0 × 10⁻⁷ m²，其电阻为：

R = (1.7 × 10⁻⁸ × 4.0) / (2.0 × 10⁻⁷) = 0.34 Ω

Internal resistance problems require the equation E = I(R + r). If the emf is 6.0 V, the external resistance is 2.8 Ω, and the current is 2.0 A, then r = 0.2 Ω.

内阻问题需要使用方程E = I(R + r)。若电动势为6.0 V，外电阻为2.8 Ω，电流为2.0 A，则r = 0.2 Ω。

8. Data Analysis and Graph Skills | 第八部分：数据分析与图表技能

Approximately 20% of the paper involves data analysis. Candidates must plot graphs with suitable scales, draw the line of best fit, and calculate gradients using a large right-angled triangle.

试卷约20%涉及数据分析。考生必须用适当比例绘制图像、绘制最佳拟合线，并利用大直角三角形计算斜率。

When calculating percentage uncertainty, use the formula:

计算百分不确定度时，使用公式：

percentage uncertainty = (absolute uncertainty / measured value) × 100%

For example, if a current is measured as (2.00 ± 0.05) A, its percentage uncertainty is 0.05 / 2.00 × 100% = 2.5%. If a subsequent calculation involves multiplication or division, percentage uncertainties are added.

例如，若电流测量值为(2.00 ± 0.05) A，其百分不确定度为0.05 / 2.00 × 100% = 2.5%。若后续计算涉及乘法或除法，百分不确定度需要相加。

9. Common Mistakes and Mark Scheme Insight | 第九部分：常见错误与评分标准解读

Mark schemes favour precise language. The command word “Define” requires an exact mathematical statement; “State” asks for no explanation; “Explain” demands a reason; “Calculate” requires working to be shown.

评分标准偏爱精确措辞。指令词“Define（定义）”要求精确的数学表述；“State（说明）”无需解释；“Explain（解释）”需要给出理由；“Calculate（计算）”必须展示演算过程。

Forgetting to convert mm to m or cm² to m².

忘记把mm换算为m或把cm²换算为m²。
Omitting units in the final answer, especially Pa, N, and Hz.

最终答案漏写单位，尤其是Pa、N和Hz。
Using a tangent instead of a chord when calculating gradient from a curve.

在曲线中求斜率时，误用弦而不是切线。
Confusing “distance” with “displacement” in motion questions.

在运动学问题中混淆“路程”与“位移”。

10. Final Revision Checklist | 第十部分：考前复习清单

Before the exam, ensure you can recall every key equation without looking at a formula sheet. Make a list of definitions: moment, density, Young modulus, wavelength, emf, and resistivity.

考试前，确保能够不看公式表独立写出所有关键方程。整理一份定义清单：力矩、密度、杨氏模量、波长、电动势和电阻率。

Review standard experimental methods for measuring g, calculating Young modulus, and determining resistivity.

复习测量g、测定杨氏模量和电阻率的标准实验方法。
Practise past exam questions from previous June series to become familiar with command words.

练习往年6月卷真题，熟悉指令词的要求。
Memorise SI prefixes: milli (m = 10⁻³), micro (μ = 10⁻⁶), nano (n = 10⁻⁹).

记忆SI词头：毫(m = 10⁻³)、微(μ = 10⁻⁶)、纳(n = 10⁻⁹)。
Always quote final answers to an appropriate number of significant figures, usually 2 or 3.

最终答案应使用适当有效数字，通常为2或3位。

By focusing on definitions, equation application, and graph analysis, you will be well prepared for the AQA AS Physics Unit 1 paper. Good luck.

通过聚焦定义、公式应用与图表分析，你将能够从容应对AQA AS物理Unit 1试卷。祝好运。

Published by TutorHao | Physics Revision Series | aleveler.com

更多咨询请联系16621398022（同微信）

AS AQA Physics Unit 1 (June 2022) – Exam Paper Walkthrough | AS AQA 物理 Unit 1（2022年6月）考卷解析