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AS AQA Pure Mathematics PSM1 | AS AQA 纯数学 PSM1

📚 AS AQA Pure Mathematics PSM1 | AS AQA 纯数学 PSM1

This article provides a structured review of the core pure mathematics topics tested in the OxfordAQA International AS Mathematics (9660) Pure Mathematics PSM1 paper. It focuses on key techniques, common pitfalls, and exam-style reasoning.

本文系统梳理了牛津AQA国际AS数学(9660)纯数学PSM1试卷的核心考点,重点讲解关键技巧、常见错误以及考试型思维。


1. Algebraic Expressions | 代数表达式

You must be confident in manipulating algebraic expressions, including expanding brackets, factorising, and simplifying surds. Recognise the difference between exact values and decimal approximations.

你需要熟练掌握代数表达式的运算,包括去括号、因式分解以及化简根式。要区分精确值与十进制近似值。

  • Surd rules: √(ab) = √a × √b, and √(a/b) = √a ÷ √b. Always simplify surds by removing square factors.
  • 根式规则:√(ab)=√a×√b,√(a/b)=√a÷√b。化简根式时始终提取平方因数。
  • Rationalising the denominator: multiply numerator and denominator by the conjugate when the denominator contains a surd.
  • 分母有理化:当分母含有根式时,分子分母同乘共轭式。
  • Index laws: aᵐ × aⁿ = aᵐ⁺ⁿ, aᵐ ÷ aⁿ = aᵐ⁻ⁿ, (aᵐ)ⁿ = aᵐⁿ.
  • 指数法则:aᵐ×aⁿ=aᵐ⁺ⁿ,aᵐ÷aⁿ=aᵐ⁻ⁿ,(aᵐ)ⁿ=aᵐⁿ。

Example: Express (√12 + √27) / √3 in the form a√b.

例:将 (√12+√27)/√3 化为 a√b 的形式。

Simplify each surd: √12 = 2√3, √27 = 3√3. Then (2√3 + 3√3)/√3 = 5√3/√3 = 5.

化简每个根式:√12=2√3,√27=3√3。于是 (2√3+3√3)/√3 = 5√3/√3 = 5。


2. Quadratics and Inequalities | 二次函数与不等式

Solving quadratic equations by factorising, completing the square, and the quadratic formula is essential. You also need to solve quadratic inequalities and understand the discriminant.

通过因式分解、配方法和求根公式解二次方程是基础。你还需要解二次不等式并理解判别式。

  • Completing the square: x² + bx + c = (x + b/2)² − (b/2)² + c.
  • 配方法:x²+bx+c = (x+b/2)² − (b/2)²+c。
  • Discriminant: Δ = b² − 4ac. If Δ > 0, two distinct real roots; Δ = 0, one repeated root; Δ < 0, no real roots.
  • 判别式:Δ=b²−4ac。若Δ>0,有两个不等实根;Δ=0,有一个重根;Δ<0,无实根。
  • Inequality sign: For (x − p)(x − q) > 0, the solution is x < p or x > q (assuming p < q). For < 0, the solution is p < x < q.
  • 不等式符号:对于(x−p)(x−q)>0,解为x<p或x>q(假设p<q)。对于<0,解为p<x<q。

The quadratic formula: x = (−b ± √(b² − 4ac)) / (2a)

求根公式:x = (−b ± √(b²−4ac)) / (2a)

When solving an inequality, always sketch the graph of the quadratic to avoid sign mistakes.

解不等式时,务必画出二次函数草图,避免符号错误。


3. Functions and Graphs | 函数与图像

Understand the domain and range of a function, composite functions, and inverse functions. Recognise transformations of graphs: translations and reflections.

理解函数的定义域与值域、复合函数和反函数。识别图像变换:平移和反射。

  • Composite function: fg(x) = f(g(x)). Apply g first, then f.
  • 复合函数:fg(x) = f(g(x))。先做g,再做f。
  • Inverse function: Only one-to-one functions have inverses. To find f⁻¹(x), swap x and y in y = f(x) and solve for y.
  • 反函数:只有一一对应的函数才有反函数。求f⁻¹(x)时,在y=f(x)中将x与y互换,然后解出y。
  • Translations: y = f(x) + a shifts vertically; y = f(x − a) shifts horizontally.
  • 平移:y=f(x)+a垂直平移;y=f(x−a)水平平移。
  • Reflections: y = −f(x) reflects in the x-axis; y = f(−x) reflects in the y-axis.
  • 反射:y=−f(x)关于x轴反射;y=f(−x)关于y轴反射。

Always state the domain of an inverse function, which equals the range of the original function.

始终写出反函数的定义域,它等于原函数的值域。


4. Coordinate Geometry | 坐标几何

Lines, circles, and the distance formula appear frequently. You must be able to find midpoints, gradients, parallel and perpendicular lines, and equations of circles.

直线、圆和距离公式经常出现。你必须能求中点、斜率、平行与垂直直线,以及圆的方程。

  • Gradient: m = (y₂ − y₁) / (x₂ − x₁).
  • 斜率:m = (y₂−y₁)/(x₂−x₁)。
  • Parallel lines: m₁ = m₂. Perpendicular lines: m₁m₂ = −1.
  • 平行线:m₁=m₂。垂直线:m₁m₂=−1。
  • Equation of a circle: (x − a)² + (y − b)² = r², where (a, b) is the centre and r is the radius.
  • 圆的方程:(x−a)²+(y−b)²=r²,其中(a,b)为圆心,r为半径。
  • Distance between two points: √((x₂ − x₁)² + (y₂ − y₁)²).
  • 两点间距离:√((x₂−x₁)²+(y₂−y₁)²)。

Midpoint: ((x₁ + x₂)/2, (y₁ + y₂)/2)

中点:((x₁+x₂)/2, (y₁+y₂)/2)

When finding the equation of the tangent to a circle, use the fact that the radius is perpendicular to the tangent.

求圆的切线方程时,利用半径垂直于切线的性质。


5. Sequences and Series | 数列与级数

Arithmetic and geometric sequences are tested in AS. You need to use the nth term formulas and sums of finite series.

等差数列和等比数列在AS中会考到。你需要使用通项公式和有限项求和公式。

  • Arithmetic nth term: uₙ = a + (n − 1)d.
  • 等差数列通项:uₙ=a+(n−1)d。
  • Arithmetic sum: Sₙ = n/2 [2a + (n − 1)d] = n/2 (a + l), where l is the last term.
  • 等差数列求和:Sₙ=n/2[2a+(n−1)d] = n/2(a+l),其中l为末项。
  • Geometric nth term: uₙ = arⁿ⁻¹.
  • 等比数列通项:uₙ=arⁿ⁻¹。
  • Geometric sum: Sₙ = a(1 − rⁿ) / (1 − r), r ≠ 1.
  • 等比数列求和:Sₙ=a(1−rⁿ)/(1−r),r≠1。

For the sum to infinity of a geometric series, you must have |r| < 1. Then S∞ = a / (1 − r).

等比级数求和存在需满足|r|<1。此时S∞=a/(1−r)。


6. Trigonometry | 三角函数

AS trigonometry focuses on exact values, solving equations, and the sine and cosine rules for triangles. Radians may be introduced, so be comfortable converting.

AS三角学重点为精确值、解三角方程以及三角形的正弦定理和余弦定理。弧度制可能引入,所以应熟练转换。

  • Exact values: sin 30° = ½, cos 30° = √3/2, tan 30° = 1/√3; sin 45° = √2/2, cos 45° = √2/2, tan 45° = 1; sin 60° = √3/2, cos 60° = ½, tan 60° = √3.
  • 精确值:sin30°=½,cos30°=√3/2,tan30°=1/√3;sin45°=√2/2,cos45°=√2/2,tan45°=1;sin60°=√3/2,cos60°=½,tan60°=√3。
  • Sine rule: a/sin A = b/sin B = c/sin C.
  • 正弦定理:a/sin A = b/sin B = c/sin C。
  • Cosine rule: a² = b² + c² − 2bc cos A.
  • 余弦定理:a²=b²+c²−2bc cos A。
  • Identities: tan θ = sin θ / cos θ; sin²θ + cos²θ = 1.
  • 恒等式:tanθ=sinθ/cosθ;sin²θ+cos²θ=1。

When solving equations like sin θ = 0.5 in degrees, remember the symmetry of the sine graph: additional solutions may lie in the second quadrant.

解形如sinθ=0.5的方程(角度制)时,记住正弦图像的对称性:另一个解可能在第二象限。


7. Exponentials and Logarithms | 指数与对数

Logarithms are the inverse of exponentials. You must know the laws of logs and how to solve exponential equations using logarithms.

对数是指数的逆运算。你必须知道对数法则以及如何使用对数求解指数方程。

  • Definition: logₐ x = b means aᵇ = x.
  • 定义:logₐ x=b 等价于 aᵇ=x。
  • Laws: logₐ x + logₐ y = logₐ(xy); logₐ x − logₐ y = logₐ(x/y); n logₐ x = logₐ(xⁿ).
  • 法则:logₐ x+logₐ y=logₐ(xy);logₐ x−logₐ y=logₐ(x/y);n logₐ x=logₐ(xⁿ)。
  • Special values: logₐ 1 = 0, logₐ a = 1.
  • 特殊值:logₐ 1=0,logₐ a=1。
  • Change of base: logₐ b = logₖ b / logₖ a.
  • 换底公式:logₐ b=logₖ b/logₖ a。

To solve 2ˣ = 5, take logs of both sides: x = log₁₀5 / log₁₀2.

解2ˣ=5时,两边取对数:x=log₁₀5/log₁₀2。


8. Differentiation | 微分

Differentiation is a major topic in PSM1. You need to differentiate polynomials and use derivatives to find gradients, tangents, and normals.

微分是PSM1的主要话题。你需要对多项式求导,并利用导数求斜率、切线和法线。

  • Power rule: d/dx (kxⁿ) = knxⁿ⁻¹.
  • 幂法则:d/dx(kxⁿ)=knxⁿ⁻¹。
  • Constant: d/dx (c) = 0.
  • 常数:d/dx(c)=0。
  • Gradient of tangent: substitute x into dy/dx.
  • 切线的斜率:将x代入dy/dx。
  • Normal gradient: m_normal = −1 / m_tangent.
  • 法线斜率:m法线 = −1/m切线。

If y = xⁿ, then dy/dx = nxⁿ⁻¹.

若 y=xⁿ,则 dy/dx = nxⁿ⁻¹。

Always expand brackets before differentiating unless you can use the chain rule, which is not required at AS.

在求导前先展开括号,除非你能使用链式法则(AS不要求)。


9. Integration | 积分

Integration is the reverse of differentiation. You must be able to integrate polynomials and evaluate definite integrals to find areas.

积分是微分的逆运算。你必须能对多项式积分,并计算定积分求面积。

  • Indefinite integral: ∫ xⁿ dx = xⁿ⁺¹/(n+1) + C, n ≠ −1.
  • 不定积分:∫ xⁿ dx = xⁿ⁺¹/(n+1)+C,n≠−1。
  • Definite integral: ∫ₐᵇ f'(x) dx = [f(x)]ₐᵇ = f(b) − f(a).
  • 定积分:∫ₐᵇ f'(x) dx = [f(x)]ₐᵇ = f(b)−f(a)。
  • Area under curve: A = ∫ₐᵇ y dx.
  • 曲线下的面积:A=∫ₐᵇ y dx。

If the curve goes below the x-axis, the integral gives a negative value. Take the absolute value for the area, or split the interval at the roots.

若曲线在x轴下方,积分得负值。求面积时取绝对值,或在根处拆分区间。


10. Exam Tips and Common Mistakes | 考试技巧与常见错误

PSM1 rewards clear working and correct use of notation. Many students lose marks by skipping steps or misreading the question.

PSM1看重清晰的步骤和正确的符号书写。许多学生因跳步或读错题而丢分。

  • Show all working: Method marks are awarded even if the final answer is wrong.
  • 写出所有步骤:即使最终答案错误,方法分也会给。
  • Check domain/range: When giving inverse functions, always state the domain.
  • 检查定义域/值域:给出反函数时,必须写明定义域。
  • Use radians if specified: In trigonometry, set your calculator correctly.
  • 若指定弧度则用弧度:在三角题中,正确设置计算器模式。
  • Revise surds and indices: These often appear in the first few questions and can be simple marks.
  • 复习根式和指数:它们常出现在前几题,是容易拿到的分。

Manage your time: PSM1 usually has around 10–12 questions. Attempt every part; partial credit is available.

管理好时间:PSM1通常有10–12道题。尽量作答每一部分,部分分数是可以得到的。


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