AS Maths Unit 2 Mark Scheme Jan21: Common Mistakes Summary | AS数学单元2 2021年1月评分标准易错点总结

📚 AS Maths Unit 2 Mark Scheme Jan21: Common Mistakes Summary | AS数学单元2 2021年1月评分标准易错点总结

The January 2021 AS Mathematics Unit 2 examination tested a range of core topics including algebra, functions, calculus, trigonometry, exponentials, and proof. Analysing the mark scheme reveals recurring mistakes that cost students valuable marks. This article summarises the most common pitfalls, with paired explanations in English and Chinese, to help you avoid them in future assessments.

2021年1月AS数学单元2考试涵盖了代数、函数、微积分、三角函数、指数与对数、证明等核心内容。分析评分标准可以发现学生经常出现的问题，这些错误往往导致不必要的失分。本文以中英对照的形式总结最常见的易错点，帮助你在今后的考试中避开这些陷阱。

1. Algebraic Simplification and Factorisation Errors | 代数化简与因式分解错误

Many students lost marks by incorrectly expanding brackets or failing to fully factorise expressions. A typical mistake was writing (x + 3)² as x² + 9, forgetting the 6x term. In the mark scheme, partial factorisation such as taking out a common factor but leaving a quadratic that could be factorised further was penalised if a question asked for complete factorisation.

许多学生因错误展开括号或未能彻底分解表达式而丢分。常见的错误是把 (x + 3)² 写成 x² + 9，漏掉了 6x 这一项。在评分标准中，如果题目要求完全分解因式，而学生只提取了公因子却留下仍可继续分解的二次式，这种部分分解会被扣分。

Incorrect: 2x² – 8 = 2(x² – 4) stopped here. Correct: 2(x – 2)(x + 2).
错误：2x² – 8 = 2(x² – 4) 就停住了。正确：2(x – 2)(x + 2)。
Incorrect: (2x – 1)(x + 4) expanded to 2x² + 7x – 4. Correct expansion gives 2x² + 7x – 4, but sign errors like writing –7x were common.
错误：(2x – 1)(x + 4) 展开时符号弄错，如误得 2x² – 7x – 4。正确展开为 2x² + 7x – 4。

2. Misunderstanding Function Notation and Domain/Range | 函数符号与定义域值域的理解偏差

A frequent error was treating f(x + 2) as f(x) + 2. The mark scheme required students to substitute (x + 2) into the function correctly. Another common mistake involved stating the range of a quadratic function without considering the vertex, or giving the domain of a composite function without checking the output of the inner function.

常见的错误是把 f(x + 2) 当成 f(x) + 2 来处理。评分标准要求将 (x + 2) 正确代入函数表达式。另一个高频错误是在求二次函数的值域时不考虑顶点，或者在求复合函数的定义域时不检查内层函数的输出是否落在下一层的有效输入范围内。

Given f(x) = x² – 3, f(x + 2) should be (x + 2)² – 3 = x² + 4x + 1, not x² – 3 + 2.
已知 f(x) = x² – 3，f(x + 2) 应为 (x + 2)² – 3 = x² + 4x + 1，而不是 x² – 3 + 2。

3. Differentiation: Chain, Product and Quotient Rule Mistakes | 微分易错：链式、乘积与商法则

The mark scheme showed that many candidates lost accuracy marks by misapplying the chain rule, especially when differentiating expressions like sin²x or e³ˣ. For product and quotient rules, errors often arose from incorrect signs or forgetting to square the denominator in the quotient rule. Some students also differentiated ln(kx) as 1/x only, ignoring the constant factor.

评分标准显示，许多考生在链式法则的应用上丢失了准确分，特别是在对 sin²x 或 e³ˣ 这类函数求导时。乘积法则和商法则的常见错误包括符号弄反，或者商法则中忘记对分母平方。也有学生在求 ln(kx) 的导数时只写作 1/x，忽略了常系数。

Mistake	Correct
d/dx (sin²x) = cos²x	2 sin x cos x
d/dx (x eˣ) = eˣ + x eˣ incorrectly got eˣ only	eˣ + x eˣ (product rule)
d/dx (x/(x+1)) = 1/(x+1)² (sign error)	1/(x+1)² using quotient rule

4. Integration: Forgetting the Constant and Incorrect Limits | 积分错误：遗漏常数与积分限处理不当

Indefinite integration without ‘+ c’ was a common reason for losing the final accuracy mark. In definite integration, errors included mis-substituting limits, especially when the lower limit was negative, or forgetting to apply the anti-derivative to both limits. When integrating fractions like 1/(ax+b), students sometimes omitted the factor 1/a.

在不定积分中漏写「+ c」是导致最终准确分丢失的常见原因。定积分方面，典型错误包括代入积分限时出错，特别是下限为负数时，或者忘记将反导数分别代入上下限求差。在积分形如 1/(ax+b) 的分式时，学生有时会遗漏系数 1/a。

∫ 2/(3x+1) dx ≠ 2 ln|3x+1| + c; correct is (2/3) ln|3x+1| + c.
∫ 2/(3x+1) dx 不等于 2 ln|3x+1| + c，正确结果为 (2/3) ln|3x+1| + c。

5. Trigonometric Equations: Missing Solutions and Principal Values | 三角方程：漏解与主值问题

When solving sin θ = 0.5, many candidates only gave θ = 30° in the range 0° to 360°, ignoring the second solution 150°. The mark scheme consistently awards marks for all solutions within the given interval. Another pitfall was not adjusting the interval when solving equations like sin(2θ) = 0.5, leading to missed solutions.

在解 sin θ = 0.5 时，许多考生仅在 0° 到 360° 范围内给出 θ = 30°，而遗漏了第二个解 150°。评分标准始终要求给出指定区间内的所有解。另一个陷阱是，在解形如 sin(2θ) = 0.5 的方程时没有相应调整区间，导致漏解。

For sin(2θ) = 0.5, 0° ≤ θ ≤ 360°, first find 2θ in 0°–720°: 2θ = 30°, 150°, 390°, 510°, so θ = 15°, 75°, 195°, 255°.
对于 sin(2θ) = 0.5，0° ≤ θ ≤ 360°，先求 2θ 在 0°–720° 中的解：2θ = 30°, 150°, 390°, 510°，于是 θ = 15°, 75°, 195°, 255°。

6. Exponentials and Logarithms: Mixed Up Laws | 指数与对数法则的混淆

Incorrect manipulation of log and exponential equations was widespread. A typical error was solving e²ˣ = 5 by writing 2x = ln 5 incorrectly as x = ln(5/2). The mark scheme demands correct use of inverse operations: if e²ˣ = 5 then 2x = ln 5, so x = (ln 5)/2. Log law mistakes like log(a + b) = log a + log b also surfaced in simplification questions.

对数和指数方程的变形错误非常普遍。典型错误是解 e²ˣ = 5 时，将 2x = ln 5 错误地写成 x = ln(5/2)。评分标准要求正确运用逆运算：若 e²ˣ = 5，则 2x = ln 5，从而 x = (ln 5)/2。在化简题中也出现了像 log(a + b) = log a + log b 这样的对数运算法则错误。

log₂ 8 + log₂ 2 = 3 + 1 = 4, but writing log₂ 10 is incorrect.
log₂ 8 + log₂ 2 = 3 + 1 = 4，写成 log₂ 10 就不对了。

7. Inequalities: Multiplying by Negative and Quadratic Handling | 不等式：负数乘除与二次不等式

When multiplying or dividing an inequality by a negative number, many students forgot to reverse the inequality sign. In quadratic inequalities such as x² – 5x + 6 > 0, common mistakes included sketching the wrong region or giving the solution as 2 < x < 3 instead of x < 2 or x > 3. The mark scheme penalised such incorrect interval notation.

对不等式两边乘或除以负数时，许多学生忘记翻转不等号。对于二次不等式如 x² – 5x + 6 > 0，常见错误包括画错函数图像的区域，或者将解集错误地表示为 2 < x < 3，而正确解应为 x < 2 或 x > 3。评分标准对这种错误的区间表示会扣分。

Solve –2x < 6: dividing by –2 gives x > –3 (not x < –3).
解 –2x < 6：除以 –2 得 x > –3（而不是 x < –3）。

8. Sequences and Series: Misapplying Arithmetic and Geometric Formulas | 数列与级数：等差与等比公式的误用

In questions on arithmetic sequences, a typical error was using the formula a + (n – 1)d incorrectly when finding the nth term, particularly confusing n with the number of terms. For geometric series, students often misapplied the sum formula a(1 – rⁿ)/(1 – r) when |r| > 1, failing to check convergence. Another mistake was treating sigma notation limits as the number of terms without careful counting.

在等差序列题目中，典型错误是在求第 n 项时错用公式 a + (n – 1)d，特别是混淆了 n 与项数。对于等比级数，学生在 |r| > 1 时仍套用求和公式 a(1 – rⁿ)/(1 – r)，而未检查收敛性。另一个错误是在处理连加符号时，不做认真计数就直接把上限当作项数。

Sum of first 10 terms: ∑ₖ₌₁¹⁰ (2k+1). Some used n=10 incorrectly as 2(10)+1=21 only; correct sum = n/2 [first + last] = 10/2 (3+21) = 120.
前10项和：∑ₖ₌₁¹⁰ (2k+1)。有人直接把 n=10 当作 2(10)+1=21 来处理；正确的和应为 n/2 [首项+末项] = 10/2 (3+21) = 120。

9. Proof: Insufficient Reasoning and Logical Gaps | 证明：推理不足与逻辑漏洞

Proof questions in the January 2021 Unit 2 paper required a clear logical structure. Many candidates lost marks by only providing examples or by making an assertion without justification. For instance, to prove that the sum of three consecutive integers is divisible by 3, you must write 3n + 3 = 3(n + 1), not just test with numbers. The mark scheme rewards full algebraic reasoning.

2021年1月单元2试卷中的证明题要求清晰的逻辑结构。许多考生仅通过举例或给出断言而没有提供理由，从而丢分。例如，证明三个连续整数的和能被3整除，必须写出 3n + 3 = 3(n + 1) 的代数过程，而不仅仅是数字验证。评分标准会奖励完整的代数推理。

Weak proof: ‘3,4,5 sum to 12 which is divisible by 3.’ Strong proof: ‘n + (n+1) + (n+2) = 3n+3 = 3(n+1), hence a multiple of 3.’
薄弱的证明：「3、4、5 之和为12，能被3整除。」有力的证明：「n + (n+1) + (n+2) = 3n+3 = 3(n+1)，因此是3的倍数。」

10. Modelling with Calculus: Interpreting Derivatives in Context | 微积分建模：情境中导数的含义

When a function modelled temperature over time, students were asked to find the rate of change at a specific instant. A common mistake was computing the derivative correctly but then failing to interpret its sign or units. The mark scheme required stating the rate with appropriate units (e.g., °C per minute) and indicating whether the quantity was increasing or decreasing.

当函数模拟温度随时间变化时，题目要求学生求特定时刻的变化率。常见错误是正确求得导数后，却未能解释其正负号和单位。评分标准要求用适当的单位（如°C/分钟）说明变化率，并指出该量是增大还是减小。

Given T(t) = 20 + 15e⁻⁰·²ᵗ, T'(5) ≈ –0.55. Answer: ‘Decreasing at 0.55°C/min.’ Forgetting the minus sign lost meaning.
已知 T(t) = 20 + 15e⁻⁰·²ᵗ，T'(5) ≈ –0.55。答：「以0.55°C/分钟的速度下降。」遗漏负号会导致含义不清。

11. Graphs and Transformations: Confusing Shifts and Stretches | 图像与变换：平移与伸缩的混淆

Transformation questions often asked for the effect of y = f(ax) or y = f(x) + a. Recurring errors included describing a horizontal stretch as a compression or mixing up the direction of a translation. The mark scheme required precise language like ‘translation by vector (3,0)’ or ‘horizontal stretch scale factor 2’.

图像变换题经常要求描述 y = f(ax) 或 y = f(x) + a 的影响。反复出现的错误包括把横向拉伸说成压缩，或者把平移方向弄混。评分标准要求使用精确的表述，如「按向量 (3,0) 平移」或「水平方向拉伸倍数为2」。

y = f(x + 2) is a translation 2 units left, not right. y = 3f(x) is a vertical stretch factor 3.
y = f(x + 2) 是向左平移2个单位，而不是向右。y = 3f(x) 是垂直方向拉伸至原来的3倍。

12. Coordinate Geometry: Circle and Line Intersection | 解析几何：圆与直线的交点问题

In finding the intersection of a line and a circle, candidates often made algebraic slips when substituting the linear equation into the circle equation, especially with signs when expanding (y – k)². Another typical error was solving the resulting quadratic but only giving one intersection point, or failing to state the coordinates as required. The mark scheme awards marks for both x and y coordinates.

在求直线与圆的交点时，考生常在将直线方程代入圆方程时出现代数失误，特别是在展开 (y – k)² 时符号弄错。另一个典型错误是解出二次方程后只给出一个交点，或者未能按要求写出坐标。评分标准会分别对 x 坐标和 y 坐标计分。

Line y = 2x + 1, circle (x – 1)² + (y – 3)² = 16. Substitute to get quadratic in x; solving gives two x values, then find corresponding y. Never leave as just x = …
直线 y = 2x + 1，圆 (x – 1)² + (y – 3)² = 16。代入后得到关于 x 的二次方程；解得两个 x 值后应求出对应的 y。不能只给出 x = … 就结束。

Published by TutorHao | AS Maths Revision Series | aleveler.com

更多咨询请联系16621398022（同微信）

AS Maths Unit 2 Mark Scheme Jan21: Common Mistakes Summary | AS数学单元2 2021年1月评分标准 易错点总结