📚 Polar Coordinates Revision for GCSE Edexcel Maths | GCSE Edexcel 数学:极坐标 考点精讲
Polar coordinates provide an elegant way to represent points and curves based on a distance from the origin and an angle from the positive x-axis. In the Edexcel GCSE Further Pure Mathematics course, you are expected to master conversions, sketch polar graphs, find intersections, and calculate areas using integration.
极坐标提供了一种优雅的方式,用点到原点的距离和与正 x 轴的夹角来表示点和曲线。在 Edexcel GCSE Further Pure Mathematics 课程中,你需要掌握坐标转换、绘制极坐标图形、求交点,并运用积分计算面积。
1. What are Polar Coordinates? | 什么是极坐标?
Instead of (x, y), a point P is given by (r, θ), where r is the radial distance from the origin O, and θ is the anticlockwise angle from the positive x-axis (polar axis). Negative r means the point lies on the opposite ray.
代替 (x, y),点 P 用 (r, θ) 表示,其中 r 是到原点 O 的径向距离,θ 是从正 x 轴(极轴)逆时针旋转的角度。负的 r 表示点位于相反方向的射线上。
The polar axis is the horizontal line to the right of O; angles are usually measured in radians for calculus work.
极轴是位于原点右侧的水平线;在微积分作业中,角通常以弧度为单位。
2. Converting Between Polar and Cartesian Forms | 极坐标与直角坐标的转换
The key relationships linking polar and Cartesian coordinates are: x = r cos θ, y = r sin θ, and r² = x² + y², tan θ = y/x (for x ≠ 0). These formulas allow you to switch between representations seamlessly.
连接极坐标和直角坐标的关键关系是:x = r cos θ, y = r sin θ,以及 r² = x² + y², tan θ = y/x(当 x ≠ 0)。这些公式让你能够在两种表示之间无缝切换。
Example: Convert (3, π/4) to Cartesian. Here r=3, θ=π/4, so x=3 cos(π/4)=3√2/2, y=3 sin(π/4)=3√2/2, giving (3√2/2, 3√2/2).
示例:将 (3, π/4) 转换为直角坐标。这里 r=3, θ=π/4,所以 x=3 cos(π/4)=3√2/2, y=3 sin(π/4)=3√2/2,得到 (3√2/2, 3√2/2)。
To convert (x,y) to polar, compute r = √(x²+y²) and determine θ using arctan(y/x), considering the quadrant.
将 (x,y) 转换为极坐标时,计算 r = √(x²+y²),并使用 arctan(y/x) 确定 θ,同时需考虑象限。
3. Basic Polar Equations and Graphs | 基本极坐标方程与图形
Common simple polar equations include r = constant (a circle radius a centred at origin), θ = constant (a line through the origin at angle α). These are building blocks for more complex curves.
常见的简单极坐标方程包括 r = 常数(以原点为中心、半径为 a 的圆),θ = 常数(过原点且角度为 α 的直线)。它们是更复杂曲线的构建基础。
Graphing by hand typically involves compiling a table of θ values and computing corresponding r, then plotting the points.
手工绘图通常需要列出 θ 值表并计算相应的 r,然后描点连线。
4. Circles in Polar Form | 极坐标形式的圆
A circle passing through the pole O with diameter a on the polar axis has equation r = a cos θ. Similarly, r = a sin θ is a circle whose diameter a lies on the line θ = π/2.
过极点 O 且直径 a 位于极轴上的圆方程为 r = a cos θ。同理,r = a sin θ 则是对直径 a 在 θ = π/2 直线上的圆。
If the centre is at the pole, the equation is simply r = a, a circle radius a. For a circle offset from the pole, use r = 2a cos(θ – α) to control the centre’s position.
如果圆心在极点,方程就是 r = a,半径为 a 的圆。对于偏离极点的圆,用 r = 2a cos(θ – α) 来控制圆心的位置。
5. Cardioids and Limaçons | 心形线与蜗牛线
Equations of the form r = a + b cos θ or r = a + b sin θ produce limaçon curves. When a = b, the shape is a cardioid, for example r = a(1 + cos θ) or r = a(1 + sin θ).
形如 r = a + b cos θ 或 r = a + b sin θ 的方程产生蜗牛线。当 a = b 时,形状为心形线,例如 r = a(1 + cos θ) 或 r = a(1 + sin θ)。
If |a| > |b|, the limaçon has no inner loop; if |a| < |b|, there is an inner loop. These curves are symmetric and often appear in exam questions requiring area calculations.
如果 |a| > |b|,蜗牛线没有内环;如果 |a| < |b|,则有一个内环。这些曲线具有对称性,常见于要求面积计算的考题中。
6. The Spiral of Archimedes | 阿基米德螺线
The Archimedean spiral is given by r = aθ, where a is a constant. As θ increases, the radius grows linearly, so the curve winds around the pole with constant separation between successive turns.
阿基米德螺线由 r = aθ 给出,其中 a 为常数。随着 θ 增大,半径线性增长,因此曲线绕极点旋转,相邻圈之间的间隔恒定。
You may be asked to sketch it for θ ≥ 0, noting that negative θ values produce a reflection across the pole.
你可能会被要求绘制 θ ≥ 0 时的图形,注意负的 θ 值会产生关于极点的反射图形。
7. Finding Intersections of Polar Curves | 求极坐标曲线的交点
To find where two polar curves r = f(θ) and r = g(θ) intersect, solve f(θ) = g(θ) for θ in the relevant domain. However, always check if the pole (r=0) is an intersection point, as f(θ)=0 and g(θ)=0 might occur at different θ values.
为求两条极坐标曲线 r = f(θ) 和 r = g(θ) 的交点,在相关定义域内求解 f(θ) = g(θ)。然而,一定要检查极点 (r=0) 是否
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