Year 8 AQA Statistics: Interdisciplinary Mixed Question Practice | 跨学科综合题型训练

📚 Year 8 AQA Statistics: Interdisciplinary Mixed Question Practice | 跨学科综合题型训练

In Year 8, statistics is not just a standalone topic in mathematics – it appears across many subjects. You might need to analyse data from a science experiment, interpret graphs in geography, or work out probabilities in games. This article provides mixed question practice that combines statistical skills with real-world contexts from different disciplines. By working through these examples, you will strengthen your ability to apply averages, charts, probability and data comparison techniques wherever they are needed.

在八年级,统计学不仅仅是数学中的一个独立主题——它出现在许多学科中。你可能需要分析科学实验的数据,解释地理中的图表,或者计算游戏中的概率。本文提供结合统计技能与不同学科真实情境的综合题型训练。通过练习这些示例,你将加强应用平均数、图表、概率和数据比较技术的能力,无论在哪里需要这些技能。


1. Science: Comparing Reaction Times Before and After Practice | 科学:比较练习前后的反应时间

A student conducted an experiment to see if practice improves reaction time. She dropped a ruler and caught it, measuring the distance and converting to time in seconds. Here are her results before any practice: 0.22 s, 0.25 s, 0.19 s, 0.30 s, 0.28 s. After a week of daily practice, she repeated the test and recorded: 0.18 s, 0.20 s, 0.17 s, 0.22 s, 0.24 s.

一位学生进行实验,看练习是否能提高反应时间。她让一把尺子落下并抓住它,测量距离并转换为秒。以下是练习前的结果:0.22 秒, 0.25 秒, 0.19 秒, 0.30 秒, 0.28 秒。经过一周每天练习后,她重复测试并记录:0.18 秒, 0.20 秒, 0.17 秒, 0.22 秒, 0.24 秒。

To find the median for the ‘before’ data, first order the values from smallest to largest: 0.19, 0.22, 0.25, 0.28, 0.30. The median is the middle value, which is 0.25 s. The range is the difference between the largest and smallest: 0.30 – 0.19 = 0.11 s.

要找“练习前”数据的中位数,先将数值从小到大排序:0.19, 0.22, 0.25, 0.28, 0.30。中位数是中间值,即 0.25 秒。极差是最大值与最小值之差:0.30 – 0.19 = 0.11 秒。

Now for the ‘after’ data: order 0.17, 0.18, 0.20, 0.22, 0.24. The median is 0.20 s, and the range is 0.24 – 0.17 = 0.07 s.

现在看“练习后”数据:排序 0.17, 0.18, 0.20, 0.22, 0.24。中位数是 0.20 秒,极差是 0.24 – 0.17 = 0.07 秒。

Comparing the two sets: the median reaction time decreased from 0.25 s to 0.20 s, showing improvement. The range also became smaller, suggesting more consistent performance after practice. These results support the idea that practice reduces reaction time.

比较两组数据:中位反应时间从 0.25 秒降至 0.20 秒,表明有所提高。极差也变小了,说明练习后的表现更一致。这些结果支持练习能缩短反应时间的观点。


2. Geography: Interpreting Climate Graphs | 地理:解读气候图表

A geography student recorded the average monthly rainfall (in millimetres) for a city over a year. The data is shown below.

一位地理学生记录了一座城市一年内的月平均降雨量(毫米)。数据如下所示。

Month Jan Feb Mar Apr May Jun Jul Aug Sep Oct Nov Dec
Rainfall (mm) 50 45 55 60 70 80 85 90 75 65 55 50

下表为同一数据的中文版:

月份 1月 2月 3月 4月 5月 6月 7月 8月 9月 10月 11月 12月
降雨量 (mm) 50 45 55 60 70 80 85 90 75 65 55 50

To draw a climate graph, you would plot months on the horizontal axis and rainfall on the vertical axis as bars. Then calculate the mean monthly rainfall by adding all values and dividing by 12.

要绘制气候图表,你会将月份放在横轴,降雨量作为纵轴上的条形。然后通过将所有值相加再除以 12 来计算月平均降雨量。

Mean = (50+45+55+60+70+80+85+90+75+65+55+50) ÷ 12 = 780 ÷ 12 = 65 mm

平均数 = (50+45+55+60+70+80+85+90+75+65+55+50) ÷ 12 = 780 ÷ 12 = 65 毫米

The wettest month is August with 90 mm, and the driest is February with 45 mm. This graph helps geographers understand seasonal patterns in rainfall.

最湿润的月份是八月,降雨量 90 毫米;最干燥的是二月,45 毫米。此图表帮助地理学家理解降雨的季节性规律。


3. Physical Education: Analysing Long Jump Results | 体育:分析跳远成绩

A PE teacher recorded the best long jump distances (in metres) for two groups of students. Group A: 3.2, 3.5, 2.9, 3.8, 3.1, 3.4, 3.0. Group B: 3.6, 3.3, 3.7, 3.2, 3.5, 3.8, 3.9.

一位体育老师记录了两组学生的最好跳远距离(米)。A 组:3.2, 3.5, 2.9, 3.8, 3.1, 3.4, 3.0。B 组:3.6, 3.3, 3.7, 3.2, 3.5, 3.8, 3.9。

To find which group performed better on average, calculate the mean for each group.

要找出哪组平均表现更好,计算每组的平均数。

Mean of Group A = (3.2 + 3.5 + 2.9 + 3.8 + 3.1 + 3.4 + 3.0) ÷ 7 = 22.9 ÷ 7 ≈ 3.27 m

A 组平均数 = (3.2 + 3.5 + 2.9 + 3.8 + 3.1 + 3.4 + 3.0) ÷ 7 = 22.9 ÷ 7 ≈ 3.27 米

Mean of Group B = (3.6 + 3.3 + 3.7 + 3.2 + 3.5 + 3.8 + 3.9) ÷ 7 = 25.0 ÷ 7 ≈ 3.57 m

B 组平均数 = (3.6 + 3.3 + 3.7 + 3.2 + 3.5 + 3.8 + 3.9) ÷ 7 = 25.0 ÷ 7 ≈ 3.57 米

Group B has a higher mean, so on average they jumped further. The median for Group A (ordered 2.9, 3.0, 3.1, 3.2, 3.4, 3.5, 3.8) is 3.2 m, and for Group B (3.2, 3.3, 3.5, 3.6, 3.7, 3.8, 3.9) the median is 3.6 m. Both averages confirm Group B’s advantage. The range for Group A is 3.8 – 2.9 = 0.9 m, while Group B’s range is 3.9 – 3.2 = 0.7 m, indicating Group B is also more consistent.

B 组的平均数更高,所以平均而言她们跳得更远。A 组的中位数(排序 2.9, 3.0, 3.1, 3.2, 3.4, 3.5, 3.8)是 3.2 米,B 组(3.2, 3.3, 3.5, 3.6, 3.7, 3.8

Published by TutorHao | Year 8 统计 Revision Series | aleveler.com

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