Year 8 SQA Statistics: Unit Test Mock Paper Walkthrough | 八年级 SQA 统计：单元测试模拟卷解析

📚 Year 8 SQA Statistics: Unit Test Mock Paper Walkthrough | 八年级 SQA 统计：单元测试模拟卷解析

Welcome to this detailed walkthrough of a Year 8 SQA Statistics unit test mock paper. This resource covers key topics such as averages, charts, probability, and data interpretation. Each question is broken down step by step to help you understand the reasoning and techniques required for success in your assessment.

欢迎阅读这份八年级 SQA 统计单元测试模拟卷的详细解析。本资源涵盖了平均值、图表、概率和数据解读等关键主题。每个问题都逐步分解，帮助你掌握评估成功所需的推理方式和解题技巧。

1. Question 1: Survey Data Analysis | 第1题：调查数据分析

A class survey asked 10 students how many pets they have at home. The responses were: 2, 0, 1, 2, 3, 1, 0, 2, 4, 1.

一项班级调查询问了10名学生他们家里有多少只宠物。回答如下：2, 0, 1, 2, 3, 1, 0, 2, 4, 1。

(a) Calculate the mean, median, mode, and range. (b) Which measure best describes the typical number of pets?

(a) 计算平均值、中位数、众数和范围。(b) 哪一项度量最能描述宠物的典型数量？

Step 1: Mean. Add all the values: 2+0+1+2+3+1+0+2+4+1 = 16. There are 10 data points. Mean = 16 ÷ 10 = 1.6.

步骤1：平均值。 将所有数值相加：2+0+1+2+3+1+0+2+4+1 = 16。共有10个数据点。平均值 = 16 ÷ 10 = 1.6。

Step 2: Median. Sort the numbers from smallest to largest: 0, 0, 1, 1, 1, 2, 2, 2, 3, 4. The median lies between the 5th and 6th values: (1 + 2) ÷ 2 = 1.5.

步骤2：中位数。 将数字从小到大排序：0, 0, 1, 1, 1, 2, 2, 2, 3, 4。中位数位于第5和第6个值之间：(1 + 2) ÷ 2 = 1.5。

Step 3: Mode. The numbers 1 and 2 both appear three times, more than any other value. The data set is bimodal, with modes 1 and 2.

步骤3：众数。 数字1和2各出现了三次，比其他任何值都多。该数据集是双峰的，众数为1和2。

Step 4: Range. Range = Maximum − Minimum = 4 − 0 = 4.

步骤4：范围。 范围 = 最大值 − 最小值 = 4 − 0 = 4。

Part (b): The median (1.5) and mean (1.6) are close, giving a typical value around 1–2 pets. However, the presence of a relatively high value (4) slightly pulls the mean upwards; the median is not affected by this outlier. The mode highlights the most common responses. In this context, the median is a robust choice for ‘typical’ pets.

第(b)部分： 中位数（1.5）和平均值（1.6）很接近，给出的典型值大约是1–2只宠物。不过，存在一个相对较高的数值（4）略微拉高了平均值；中位数不受这个异常值影响。众数突出了最常见的回答。在这个情境下，中位数是“典型”宠物数量的稳健选择。

2. Question 2: Bar Chart Interpretation | 第2题：条形图解读

A bar chart displays the favourite sports of 20 students. The frequencies are: Football 8, Basketball 5, Tennis 3, Cricket 4.

一幅条形图展示了20名学生最喜爱的运动。频数分别为：足球 8，篮球 5，网球 3，板球 4。

(a) What is the mode? (b) How many students chose Football or Basketball? (c) What fraction of students chose Tennis?

(a) 众数是什么？(b) 有多少名学生选择了足球或篮球？(c) 选择网球的学生占多大比例？

Solution:

解答：

(a) The mode is the category with the highest bar: Football, with a frequency of 8.

(a) 众数是条形最高的类别：足球，频数为8。

(b) Students choosing Football or Basketball = 8 + 5 = 13.

(b) 选择足球或篮球的学生数 = 8 + 5 = 13。

(c) Fraction for Tennis = 3 out of 20 students = 3/20.

(c) 网球所占比例 = 20名学生中的3名 = 3/20。Published by TutorHao | Year 8 统计 Revision Series | aleveler.com

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