KS3 WJEC Psychology: Unit Test Mock Exam Walkthrough | KS3 WJEC 心理学：单元测试模拟卷解析

📚 KS3 WJEC Psychology: Unit Test Mock Exam Walkthrough | KS3 WJEC 心理学：单元测试模拟卷解析

This walkthrough breaks down a typical KS3 WJEC Psychology unit test on Memory. Each question is presented with its correct answer, followed by a detailed explanation of the key concepts, research, and exam techniques you need to master. Use this guide to understand why certain answers are right, learn how to structure extended responses, and build confidence for your own assessments.

本解析详细拆解了一套典型的 KS3 WJEC 心理学“记忆”单元测试卷。每道题目都给出了正确答案，并针对关键概念、研究案例和应试技巧进行了深入讲解。通过这份指南，你可以明白为什么某些答案是正确的，学会如何组织扩展性回答，并为自己的评估建立信心。

1. Multiple Choice: The Capacity of Short-Term Memory | 单选题：短时记忆的容量

Question: According to Miller (1956), what is the capacity of short-term memory? A. 3 items B. 7±2 items C. Unlimited D. 12 items

问题：根据 Miller (1956) 的研究，短时记忆的容量是多少？ A. 3个组块 B. 7±2个组块 C. 无限 D. 12个组块

Correct answer: B. Miller’s famous paper The Magical Number Seven, Plus or Minus Two found that the average person can hold between 5 and 9 chunks of information in their short-term memory. This is often cited as 7±2 items, although later research suggests the true capacity may be closer to 4±1 chunks when rehearsal is prevented.

正确答案：B。Miller 那篇著名的论文《神奇数字 7±2》发现，普通人的短时记忆中平均能容纳 5 到 9 个信息组块。这通常被引述为 7±2 个项目，虽然后续研究表明，当阻止复述时，真实容量可能更接近 4±1 个组块。

It is crucial not to confuse short-term memory capacity with the vast, potentially unlimited capacity of long-term memory. The key term ‘chunks’ means that we can expand the amount of information by grouping items meaningfully; for example, remembering a phone number as 07895-342-176 instead of eleven separate digits.

关键是不能将短时记忆的容量与长时记忆那巨大、可能无限的容量相混淆。关键术语“组块”意味着我们可以通过有意义地分组来扩展信息量；例如，将电话号码记为 07895-342-176，而不是十一个孤立的数字。

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2. Short-Answer Question: Defining ‘Encoding’ | 简答题：定义“编码”

Question: Explain what is meant by the term ‘encoding’ in the context of memory.

问题：在记忆的情境下，解释术语“编码”的含义。

A strong answer would state that encoding is the process of changing sensory input into a form that can be stored by the memory system. Information enters the brain through our senses and is converted into a code. The three main types of encoding are visual (as a picture), acoustic (as a sound), and semantic (by meaning). For instance, when you read a word, you might encode it visually by its appearance, acoustically by how it sounds in your head, or semantically by linking it to its definition.

一个好的回答会指出，编码是将感觉输入转换为能被记忆系统存储的形式的过程。信息通过我们的感官进入大脑，并被转成一种代码。三种主要的编码类型是视觉编码（如图像）、听觉编码（如声音）和语义编码（通过意义）。例如，当你阅读一个单词时，你可能会通过它的模样进行视觉编码，通过脑海中它的发音进行听觉编码，或者通过联系其定义进行语义编码。

Research by Baddeley (1966) showed that short-term memory tends to rely mainly on acoustic encoding (hence we get easily confused by words that sound similar), whereas long-term memory prefers semantic encoding (we remember the gist of a story rather than the exact words). Using this research in your answer would demonstrate deeper understanding.

Baddeley (1966) 的研究表明，短时记忆主要依赖听觉编码（因此我们容易被发音相似的词混淆），而长时记忆则偏好语义编码（我们记住故事的大意而非确切的措辞）。在答案中运用这项研究能展现更深层次的理解。

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3. Application: Procedural Memory in Action | 应用题：程序性记忆实例

Question: Give one example of procedural memory and explain how you know it is procedural.

问题：给出一个程序性记忆的例子，并解释你如何知道它属于程序性记忆。

A model answer could be: ‘Knowing how to ride a bicycle is an example of procedural memory. I know this because it is a memory for a skill, or how to do something, rather than a memory of facts or personal events. Once learned, riding a bike can be performed automatically without conscious thought, and it is often very difficult to explain the exact muscle movements. These are hallmarks of procedural memory.’

标准答案示例：“知道如何骑自行车是程序性记忆的一个例子。我之所以知道，是因为它是对技能或如何做某事的记忆，而不是对事实或个人事件的记忆。一旦学会，骑自行车就可以无意识地自动完成，且往往很难说清楚确切的肌肉动作。这些都是程序性记忆的特征。”

Other suitable examples include typing on a keyboard, swimming, playing a musical instrument, or tying shoelaces. Procedural memory is one of three types of long-term memory identified by Tulving, alongside episodic (personal experiences) and semantic (facts). Crucially, amnesia patients like H.M. could still learn new motor skills despite being unable to form new conscious memories, showing that procedural memory relies on different brain areas such as the cerebellum and basal ganglia.

其他合适的例子包括用键盘打字、游泳、演奏乐器或系鞋带。程序性记忆是 Tulving 识别的三种长时记忆之一，另外两种是情景记忆（个人经历）和语义记忆（事实）。关键的一点是，像 H.M. 这样的失忆症患者尽管无法形成新的有意识记忆，却仍能学习新的运动技能，这表明程序性记忆依赖不同脑区，例如小脑和基底神经节。

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4. Multiple Choice: Types of Long-Term Memory | 单选题：长时记忆的类型

Question: Which type of long-term memory is responsible for storing facts and general knowledge about the world? A. Episodic B. Procedural C. Semantic D. Sensory

问题：哪种类型的长时记忆负责储存事实和对世界的一般知识？ A. 情景记忆 B. 程序性记忆 C. 语义记忆 D. 感觉记忆

Correct answer: C. Semantic memory is our mental encyclopaedia; it contains knowledge of concepts, words, rules, and facts—such as knowing that Paris is the capital of France or that 2+2=4. This type of memory is not time-stamped, meaning you often don’t remember when or where you learned the fact.

正确答案：C。语义记忆是我们的心理百科全书；它包含概念、词汇、规则和事实的知识——比如知道巴黎是法国的首都或 2+2=4。这种类型的记忆没有时间标记，也就是说你经常不记得自己是在何时何地学到这个事实的。

The table below summarises the three long-term memory types according to Tulving (1972):

下表根据 Tulving (1972) 总结了三种长时记忆的类型：

Memory type 记忆类型	What it stores 储存内容	Example 例子	Conscious? 有意识？
Episodic 情景记忆	Personal experiences 个人经历	Your last birthday party 你上一个生日派对	Yes 是
Semantic 语义记忆	Facts and knowledge 事实与知识	Knowing the capital of Italy 知道意大利的首都	Yes 是
Procedural 程序性记忆	Skills and actions 技能与动作	Tying a knot 打结	No (automatic) 否（自动）

Distinguishing between these types is vital because brain scans show they involve different regions. Episodic and semantic memories are both declarative (consciously recalled) and rely heavily on the hippocampus, whereas procedural memory is non-declarative.

区分这些类型至关重要，因为脑部扫描显示它们涉及不同区域。情景记忆和语义记忆都属于陈述性记忆（可有意识回忆），并高度依赖海马体，而程序性记忆则是非陈述性的。

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5. Diagram Labelling: The Multi-Store Model | 图表标注：多储存模型

Question: Label the three main stores in the multi-store model of memory and describe the process that transfers information between short-term and long-term stores.

问题：在多储存记忆模型中，标注三个主要储存库并描述在短时与长时储存库之间传递信息的过程。

The three stores are: Sensory Register, Short-Term Memory (STM), and Long-Term Memory (LTM). Information first enters the sensory register through the five senses, where it is held for a very brief duration (around 0.5 seconds for visual) but has a large capacity. If we pay attention to this sensory information, it passes into STM. STM has a limited capacity of about 7±2 chunks and a duration of around 18-30 seconds without rehearsal.

三个储存库分别是：感觉登记器、短时记忆和长时记忆。信息首先通过五种感官进入感觉登记器，在此处保留非常短暂的时间（视觉信息约 0.5 秒），但容量很大。如果我们注意到这些感觉信息，它便会进入短时记忆。短时记忆的容量有限，约为 7±2 个组块，在不复述的情况下持续时间约为 18-30 秒。

The process that transfers information from STM to LTM is called ‘rehearsal’, specifically maintenance rehearsal if we simply repeat the information over and over. The more something is rehearsed, the longer it stays in STM and the more likely it is to be encoded into LTM. The model also shows that information can be retrieved from LTM back into STM when we need to use it. This reversible flow explains why we can recall old memories into our conscious awareness.

将信息从短时记忆传递到长时记忆的过程称为“复述”，如果我们仅仅是不断重复信息，那就特指维持性复述。信息被复述得越多，它在短时记忆中保留的时间就越长，也就越有可能被编码进入长时记忆。该模型还表明，当我们需要使用信息时，可以从长时记忆中提取回短时记忆。这种可逆的流动解释了我们为何能将旧记忆回溯到意识中。

Atkinson and Shiffrin (1968) proposed this model, which is often likened to a computer with input (senses), processing (STM), and storage (LTM). However, it has been criticised for being too simplistic, as it suggests information must pass through STM to reach LTM, yet patients like K.F. showed impaired STM but intact LTM, suggesting separate systems that can operate independently.

Atkinson 和 Shiffrin 于 1968 年提出了这一模型，它常被比拟为一台拥有输入（感官）、处理（短时记忆）和储存（长时记忆）的计算机。不过，该模型被批评过于简化，因为它暗示信息必须经过短时记忆才能进入长时记忆，然而像 K.F. 这样的病人却表现出短时记忆受损而长时记忆完好，这表明存在能独立运作的各别系统。

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6. Short-Answer Question: The Power of Chunking | 简答题：组块的威力

Question: Using an example, explain what psychologists mean by the term ‘chunking’.

问题：运用一个例子，解释心理学家所说的“组块”一词的含义。

Chunking is a technique used to increase the capacity of short-term memory by grouping individual pieces of information into larger, meaningful units, or ‘chunks’. For example, the string of letters I B M F B I C I A U S A might look like 12 individual items, which exceeds the typical capacity of STM. However, if you rearrange them into the chunks IBM, FBI, CIA, USA, they become four meaningful acronyms, well within the 7±2 limit and far easier to recall.

组块是一种通过将单个信息片段组合成更大、有意义单元（即“组块”）来增加短时记忆容量的技巧。例如，字母串 I B M F B I C I A U S A 可能看起来像 12 个单独的项目，超出了短时记忆的典型容量。但如果你将它们重组成 IBM、FBI、CIA、USA 这些组块，它们就变成了四个有意义的首字母缩略词，完全在 7±2 的限度内，且更容易回忆。

This technique exploits our existing semantic knowledge stored in long-term memory. Because each chunk becomes a single item held in STM, we can dramatically increase the total amount of information we can keep in mind. Phone numbers, credit card numbers, and even chess positions are commonly organised into chunks by experts to enhance memory.

这种技巧利用了我们储存在长时记忆中的已有语义知识。由于每个组块在短时记忆中只算作一个项目，我们便能大幅增加可以记住的信息总量。电话号码、信用卡号，甚至棋类布局都常被专家组织成组块以提高记忆效率。

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7. Research Methods: Spotting the Independent Variable | 研究方法：识别自变量

Question: A psychologist wants to test whether listening to classical music improves memory recall. Participants learn a list of 20 words either in silence or while listening to Mozart. They are then tested on how many words they can remember. Identify the independent variable (IV) in this experiment.

问题：一位心理学家想测试听古典音乐是否能提升记忆回想。参与者在安静状态下或听着莫扎特的音乐学习一份包含 20 个单词的列表，然后测试他们能记住多少单词。请识别本实验中的自变量。

The independent variable (IV) is the factor that the researcher manipulates, changes, or compares. In this experiment, the IV is the presence or type of music (silence vs. Mozart). It is also acceptable to say ‘the listening condition’ or ‘whether participants listened to music’. The dependent variable (DV), which is the outcome measured, is the number of words correctly recalled.

自变量是研究者操纵、改变或比较的因素。在本实验中，自变量是音乐的有无或类型（安静 vs. 莫扎特）。也可以说“聆听条件”或“参与者是否听音乐”。因变量是测量的结果，即正确回忆的单词数量。

Being able to identify the IV and DV is a core skill in KS3 psychology because it allows you to assess the validity of a study. In an exam, always check that the IV is operationalised—in this case, clearly defined as silence versus a specific composer—so the experiment can be replicated. Extraneous variables, such as participants’ natural memory ability, should be controlled through random allocation to conditions.

能够识别自变量和因变量是 KS3 心理学的核心技能，因为它让你能够评估研究的效度。在考试中，务必检查自变量是否被操作化——在本例中，明确定义为安静状态与某位特定作曲家的音乐——这样实验才能被重复。诸如参与者天生记忆能力这样的额外变量，应通过随机分配到不同条件来加以控制。

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8. Ethics: The Role of Informed Consent | 伦理：知情同意的作用

Question: Explain why obtaining informed consent is essential before a psychological investigation.

问题：解释为什么在心理学研究前获得知情同意是必不可少的。

Informed consent means that participants must be given enough clear information about the study’s aims, procedures, their right to withdraw, and how their data will be used, so they can make a voluntary decision about whether to take part. It is essential because it respects the ethical principle of autonomy—the right of individuals to make decisions about their own lives. Without informed consent, a study could involve deception and cause psychological harm, which breaches the British Psychological Society (BPS) code of ethics.

知情同意意味着，必须向参与者提供关于研究目的、程序、退出权利以及数据将如何被使用的足够的清晰信息，以便他们能够就是否参与做出自愿决定。它之所以必不可少，是因为它尊重了自主权这一伦理原则——即个体对自己生活做出决定的权利。没有知情同意，研究可能涉及欺骗并造成心理伤害，这就违反了英国心理学会的伦理守则。

At KS3 level, you can support your answer with an example: Milgram’s famous obedience study would not be permitted today in its original form because participants were not truly informed; they were told it was a study on memory and learning, and were put under extreme stress believing they were harming another person. Modern studies often use a consent form and a debrief at the end to ensure participants leave understanding the true purpose and without negative feelings.

在 KS3 阶段，你可以举一个例子来支撑回答：Milgram 著名的服从研究如今不可能以其原始形式获批，因为参与者并未被真正告知真相；他们被告知这是一项关于记忆与学习的研究，并在相信自己正在伤害他人的极度压力之下。现代研究通常使用同意书并在结束时进行事后解释，以确保参与者离开时了解真实目的且没有负面感受。

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9. Evaluation: Weakness of the Multi-Store Model | 评价题：多储存模型的弱点

Question: Outline one weakness of the multi-store model of memory.

问题：概述多储存记忆模型的一个弱点。

One key weakness is that the model oversimplifies the role of rehearsal. Atkinson and Shiffrin proposed that the more information is rehearsed, the more likely it is to transfer from STM to LTM. However, in everyday life, we often remember things that we have not actively rehearsed, and we can forget things that we have rehearsed many times. Craik and Lockhart’s levels of processing framework argues that it is the depth of processing—whether we think about the meaning of information—that determines long-term retention, not simply rehearsal.

一个关键弱点是，该模型过度简化了复述的作用。Atkinson 和 Shiffrin 提出，信息被复述得越多，就越有可能从短时记忆转入长时记忆。然而，在日常生活中，我们常常记住那些并未主动复述的事情，也可能忘记那些反复复述的事情。Craik 和 Lockhart 的加工层次框架认为，决定长时记忆保留的是加工 深度——即我们是否思考信息的含义——而不仅仅是复述。

Another compelling weakness comes from clinical case studies. The patient K.F. suffered brain damage that severely impaired his short-term memory, yet he could still form new long-term memories. According to the model, if STM is defective, information should not be able to pass into LTM. K.F.’s case suggests that STM and LTM are not simply sequential but may operate in parallel, challenging the linear flow of the model.

另一个强有力的弱点来自临床案例研究。病人 K.F. 遭受脑损伤，其短时记忆严重受损，但他仍然能形成新的长时记忆。按照该模型，如果短时记忆有缺陷，信息便不应能进入长时记忆。K.F. 的案例表明，短时记忆与长时记忆并非简单的先后顺序，而可能是并行运作的，这挑战了模型的线性流程。

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10. Extended Response: Describing a Key Memory Study | 扩展回答：描述一项关键记忆研究

Question: Describe the aim, method, and findings of one study into the duration of short-term memory.

问题：描述一项关于短时记忆持续时间的研究的目的、方法和发现。

A classic study is Peterson and Peterson (1959). The aim was to investigate how long information stays in short-term memory when rehearsal is prevented. They used 24 undergraduate students. On each trial, participants were given a consonant trigram (e.g., TGH, PLK) to remember, and then immediately asked to count backwards in threes from a three-digit number for varying periods of 3, 6, 9, 12, 15, or 18 seconds. Counting backwards acted as an interference task to stop rehearsal.

一项经典研究是 Peterson 和 Peterson (1959)。其目的是调查当复述被阻止时，信息在短时记忆中能保留多久。他们使用了 24 名大学生。在每次试验中，参与者被给予一个辅音三字母组（如 TGH、PLK）去记忆，然后立刻要求他们从一个三位数开始每隔三倒数，持续时间分别为 3、6、9、12、15 或 18 秒。倒数作为一个干扰任务来阻止复述。

The findings showed a sharp decline in recall as the delay increased. After 3 seconds, recall was about 80%, but after 18 seconds it had fallen to below 10%. This suggests that short-term memory has a very brief duration of around 18-30 seconds without rehearsal. The study supports the multi-store model’s claim that STM is a temporary store and that rehearsal is necessary to keep information there or move it to LTM.

研究结果显示，随着延迟时间增加，回忆率急剧下降。3 秒后回忆率约为 80%，但 18 秒后已降至 10% 以下。这表明，在没有复述的情况下，短时记忆的持续时间非常短暂，大约为 18-30 秒。该研究支持了多储存模型的主张，即短时记忆是一个临时储存库，复述对于将信息保持在那里或移入长时记忆是必需的。

For full marks in an extended response, you should also include a brief evaluation point, such as noting that the study had high control—trigrams were artificial and without personal meaning, which allowed the researchers to isolate a pure measure of STM. However, this also makes the task artificial and low in ecological validity, meaning it may not reflect how we use memory in real life where information often has meaning.

在扩展回答中为了拿到满分，你还应包含一个简要的评价点，例如指出该研究具有高度控制力——三字母组是人为的、没有个人意义，这使得研究者能够分离出纯粹的短时记忆测量。然而，这也使任务变得不自然，生态效度低，意味着它可能不能反映我们在现实生活中（信息常常具有含义）使用记忆的方式。

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11. Exam Skills: Command Words and Mark Schemes | 应试技巧：指令词与评分方案

Understanding command words is half the battle. ‘Identify’ or ‘State’ questions require a brief, single point—often one word or phrase. ‘Describe’ asks for a detailed account of something (aim, method, findings). ‘Explain’ means you must give reasons or use psychological theory to account for something. ‘Evaluate’ requires you to discuss strengths and weaknesses, drawing on evidence or alternative theories.

理解指令词是成功的一半。’Identify’ 或 ‘State’ 类问题要求简短的、单个要点——通常是一两个词或短语。’Describe’ 要求对某事物进行详细叙述（目的、方法、发现）。’Explain’ 意味着你必须给出理由或运用心理学理论来说明某事。’Evaluate’ 则要求你利用证据或替代理论讨论优点和弱点。

Always check how many marks a question offers. A 2-mark question typically expects two separate points or one point with elaboration. A 6-mark extended response follows the structure: description (AO1) and then evaluation (AO2/AO3). Writing in full sentences, using key terminology like ‘encoding’, ‘semantic’, ‘IV’, and ‘informed consent’ demonstrates your psychological knowledge and will boost your marks significantly.

务必查看题目提供的分数。一道 2 分的题通常期望两个独立的要点，或一个要点加上展开说明。一道 6 分的扩展回答遵循如下结构：先描述（AO1），然后评价（AO2/AO3）。用完整句子书写，使用诸如“编码”、“语义”、“自变量”、“知情同意”等关键术语，能展现出你的心理学知识，并会显著提升你的得分。

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