Algebra Mastery: Expressions, Brackets & Equations | 代数精通:表达式、括号与方程

📚 Algebra Mastery: Expressions, Brackets & Equations | 代数精通:表达式、括号与方程

This workbook reviews every core skill from Unit 2 of the Year 8 Higher scheme. Each question is followed by its full model answer, with the key step explained in words and then shown symbolically. Work through it with a notebook: cover the solution, attempt the question yourself, and then compare your method with the one below.

本手册系统复盘八年级高阶(Year 8 Higher)第二单元的全部核心技能。每一道题目之后都给出完整的模型答案,先用文字说明关键步骤,再用数学符号写出过程。建议配合笔记本使用:先遮住答案,独立尝试解题,再把自己的方法与下列解法进行逐项对照。

1. The Language of Algebra | 代数语言

Algebra is a precise language. Before we solve anything, we must name each part of an expression correctly and know exactly what the symbols mean.

代数是一门精准的语言。在解题之前,我们必须准确称呼表达式的各个部分,并明确每一个符号的含义。

  • Variable 变量: a letter that represents an unknown number, such as x, n or y. | 表示未知数的字母,如 x、n 或 y。
  • Term 项: a single number, a variable, or a product of a number and variable(s), such as 5x² or −3x. | 单独的数、变量,或数与变量的乘积,如 5x² 或 −3x。
  • Coefficient 系数: the number multiplying the variable, so in 5x² the coefficient is 5. | 与变量相乘的数,因此 5x² 中系数为 5。
  • Constant 常数: a term with no variable, such as +2. | 不含变量的项,例如 +2。
  • Expression 表达式: a collection of terms without an equals sign, such as 5x² − 3x + 2. | 不含等号的若干项的组合,如 5x² − 3x + 2。
  • Equation 方程: a statement that two expressions are equal, such as 5x − 3 = 12. | 表示两个表达式相等的语句,如 5x − 3 = 12。

Consider the expression 5x² − 3x + 2. Its structure is summarised below.

观察表达式 5x² − 3x + 2,其结构总结如下表。

Part 部分 Name 名称 Meaning 含义
5 coefficient of x² | x² 的系数 the number multiplying x² | 与 x² 相乘的数
quadratic term | 二次项 the variable x, squared | 变量 x 的平方
−3 coefficient of x | x 的系数 the number multiplying x | 与 x 相乘的数
+2 constant | 常数项 a term with no variable | 不含变量的项

2. Collecting Like Terms | 合并同类项

Like terms have exactly the same variable part. Only the coefficients can change; the letter part must stay identical. We cannot add x to x² because the powers are different.

同类项是指变量部分完全相同的项。合并时只能改变系数,字母部分必须保持不变。我们不能把 x 与 x² 相加,因为它们的幂不同。

Question: Simplify 4a + 7b + a − b.

题目:化简 4a + 7b + a − b。

4a + 7b + a − b = 4a + a + 7b − b = 5a + 6b

We group the a-terms: 4a + a = 5a, and the b-terms: 7b − b = 6b. The model answer is 5a + 6b.

我们将 a 项合并:4a + a = 5a;将 b 项合并:7b − b = 6b。模型答案为 5a + 6b。

Question: Simplify 6x² − 2x − 4x² + 3x.

题目:化简 6x² − 2x − 4x² + 3x。

6x² − 2x − 4x² + 3x = 6x² − 4x² − 2x + 3x = 2x² + x

Note that x is the same as 1x, so 3x − 2x = x. The final expression cannot be simplified further because 2x² and x are not like terms.

注意 x 就是 1x,因此 3x − 2x = x。最终表达式无法再化简,因为 2x² 与 x 不是同类项。

Verification tip: substitute a value, for example a = 2 and b = 1. Left side: 4(2) + 7(1) + 2 − 1 = 16; right side: 5(2) + 6(1) = 16. Both sides agree.

验证技巧:代入一个数值,例如 a = 2、b = 1。左边:4(2) + 7(1) + 2 − 1 = 16;右边:5(2) + 6(1) = 16。两边完全一致。


3. Multiplying and Dividing Terms | 单项式的乘除

When multiplying terms, multiply the coefficients first, then multiply the variable parts using the index laws. The same logic applies to division.

单项式相乘时,先乘系数,再用指数法则处理变量部分;除法运算同理。

Rule 法则 Example 示例
x² × x³ = x²⁺³ x² × x³ = x⁵
p⁵ ÷ p² = p⁵⁻² p⁵ ÷ p² = p³
(y²)³ = y²ˣ³ (y²)³ = y⁶

Question: Simplify 3a × 4a.

题目:化简 3a × 4a。

3a × 4a = 3 × 4 × a × a = 12a²

Multiply 3 by 4 to get 12, and multiply a by a to get a². The model answer is 12a².

3 乘 4 得 12,a 乘 a 得 a²。模型答案为 12a²。

Question: Simplify 8m⁶ ÷ 4m².

题目:化简 8m⁶ ÷ 4m²。

8m⁶ ÷ 4m² = (8 ÷ 4) × m⁶⁻² = 2m⁴

Divide 8 by 4 to get 2, and subtract indices: 6 − 2 = 4. Negative coefficients follow the usual sign rules:

Published by TutorHao | Mathematics Revision Series | aleveler.com

更多咨询请联系16621398022(同微信)

Comments

屏轩国际教育cambridge primary/secondary checkpoint, cat4, ukiset,ukcat,igcse,alevel,PAT,STEP,MAT, ibdp,ap,ssat,sat,sat2课程辅导,国外大学本科硕士研究生博士课程论文辅导

This site uses Akismet to reduce spam. Learn how your comment data is processed.

Discover more from aleveler.com

Subscribe now to keep reading and get access to the full archive.

Continue reading