📚 Functions and Graphs: Domain, Range, and Transformations | 函数与图像:定义域、值域与变换
In this chapter, we explore the fundamental concepts of functions and their graphical representations. We will learn how to determine the domain and range of a function, and how transformations such as translations, reflections, and stretches affect the graph of a function. These ideas are essential for understanding many topics in IGCSE Mathematics and beyond.
在本章中,我们将探讨函数的基本概念及其图形表示。我们将学习如何确定函数的定义域和值域,以及平移、反射和伸缩等变换如何影响函数的图像。这些概念对于理解 IGCSE 数学及其他领域的许多主题至关重要。
1. What is a Function? | 什么是函数?
A function is a relation that maps each input value (x) to exactly one output value (y). For example, y = 2x + 1 is a function because every x gives a unique y. We often write this as f(x) = 2x + 1.
函数是一种关系,它将每个输入值(x)恰好映射到一个输出值(y)。例如,y = 2x + 1 是一个函数,因为每个 x 都对应唯一的 y。我们通常将其写为 f(x) = 2x + 1。
The set of all possible input values is called the domain, and the set of all possible output values is called the range.
所有可能输入值的集合称为定义域,所有可能输出值的集合称为值域。
Example | 示例: For f(x) = x², the domain is all real numbers, but the range is y ≥ 0 because squaring any real number never gives a negative result.
示例:对于 f(x) = x²,定义域是所有实数,但值域是 y ≥ 0,因为任何实数的平方都不会是负数。
2. Finding the Domain | 求定义域
The domain is the set of x-values that can be substituted into a function to produce a valid output. We look for values that cause problems, such as division by zero or square roots of negative numbers.
定义域是可以代入函数并产生有效输出的 x 值集合。我们需要找出会导致问题的值,例如分母为零或负数开平方。
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For f(x) = 1/x, x ≠ 0.
对于 f(x) = 1/x,x ≠ 0。
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For f(x) = √x, x ≥ 0.
对于 f(x) = √x,x ≥ 0。
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For f(x) = 2x + 3, the domain is all real numbers.
对于 f(x) = 2x + 3,定义域是所有实数。
Worked Example | 例题: Find the domain of f(x) = √(x – 2).
例题:求 f(x) = √(x – 2) 的定义域。
Since the square root of a negative number is undefined, we need x – 2 ≥ 0, so x ≥ 2. Thus, the domain is x ≥ 2.
因为负数的平方根没有定义,我们需要 x – 2 ≥ 0,即 x ≥ 2。因此,定义域是 x ≥ 2。
3. Finding the Range | 求值域
The range is the set of all possible output values (y) of a function. To find it, consider what values y can take as x varies over the domain.
值域是函数所有可能输出值(y)的集合。要求值域,考虑当 x 在定义域内变化时,y 可以取哪些值。
Example | 示例: For f(x) = x², since x² ≥ 0 for all x, the range is y ≥ 0.
示例:对于 f(x) = x²,因为对所有 x 都有 x² ≥ 0,所以值域是 y ≥ 0。
For a quadratic function in the form f(x) = ax² + bx + c, we can complete the square to find the maximum or minimum y-value.
对于形如 f(x) = ax² + bx + c 的二次函数,我们可以通过配方法找到最大或最小 y 值。
Worked Example | 例题: Find the range of f(x) = x² – 4x + 5.
例题:求 f(x) = x² – 4x + 5 的值域。
Complete the square: f(x) = (x – 2)² + 1. Since (x – 2)² ≥ 0, the smallest value of f(x) is 1. Therefore, the range is y ≥ 1.
配方:f(x) = (x – 2)² + 1。因为 (x – 2)² ≥ 0,所以 f(x) 的最小值是 1。因此,值域是 y ≥ 1。
4. Function Notation and Evaluating Functions | 函数记号与求值
Function notation f(x) allows us to evaluate a function at a specific x. For instance, if f(x) = 3x – 2, then f(4) = 3(4) – 2 = 10.
函数记号 f(x) 允许我们在特定的 x 处求函数值。例如,若 f(x) = 3x – 2,则 f(4) = 3(4) – 2 = 10。
Sometimes we encounter composite functions like f(g(x)). This means we first apply g to x, then apply f to the result.
有时我们会遇到复合函数,如 f(g(x))。这意味着我们先对 x 应用 g,再对结果应用 f。
Example | 示例: If f(x) = x + 1 and g(x) = 2x, find f(g(3)).
示例:若 f(x) = x + 1,g(x) = 2x,求 f(g(3))。
First, g(3) = 6. Then f(6) = 7. So f(g(3)) = 7.
首先,g(3) = 6。然后 f(6) = 7。所以 f(g(3)) = 7。
5. Graphs of Basic Functions | 基本函数图像
Knowing the shape of basic function graphs helps us understand transformations quickly.
了解基本函数的图像形状有助于我们快速理解变换。
| Function | Graph shape | Key features |
| y = x | Straight line through origin | Slope 1 |
| y = x² | Parabola, vertex at origin | Symmetric about y-axis |
| y = 1/x | Hyperbola | Two branches, asymptotes at x=0, y=0 |
| y = √x | Half-parabola | Starts at origin |
Notice that y = x² and y = √x are related, but their domains and ranges differ.
注意 y = x² 和 y = √x 相关,但它们的定义域和值域不同。
6. Translations | 平移变换
A translation shifts the graph horizontally or vertically without changing its shape. If f(x) is a function, then:
平移变换在不改变图像形状的情况下,将图像水平或垂直移动。若 f(x) 是一个函数,则:
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y = f(x) + a shifts the graph vertically up by a units.
y = f(x) + a 将图像向上平移 a 个单位。
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y = f(x) – a shifts the graph vertically down by a units.
y = f(x) – a 将图像向下平移 a 个单位。
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y = f(x – a) shifts the graph horizontally right by a units.
y = f(x – a) 将图像向右平移 a 个单位。
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y = f(x + a) shifts the graph horizontally left by a units.
y = f(x + a) 将图像向左平移 a 个单位。
Example | 示例: The graph of y = (x – 3)² is the graph of y = x² shifted right by 3 units.
示例:y = (x – 3)² 的图像是 y = x² 的图像向右平移 3 个单位。
7. Reflections | 反射变换
Reflections flip the graph across a line. There are two common reflections:
反射变换是将图像关于某条直线翻转。常见的反射有两种:
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y = -f(x) reflects the graph in the x-axis.
y = -f(x) 将图像关于 x 轴反射。
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y = f(-x) reflects the graph in the y-axis.
y = f(-x) 将图像关于 y 轴反射。
Example | 示例: If f(x) = x², then y = -x² flips the parabola upside down, while y = (-x)² = x² is unchanged because the parabola is symmetric.
示例:若 f(x) = x²,则 y = -x² 将抛物线翻转,而 y = (-x)² = x² 不变,因为抛物线是对称的。
8. Stretches and Compressions | 伸缩变换
A stretch multiplies the graph in a particular direction. The rules are:
伸缩变换是在特定方向上将图像放大或缩小。规则如下:
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y = kf(x) vertically stretches the graph if k > 1, and compresses it if 0 < k < 1.
y = kf(x) 若 k > 1,则纵向拉伸;若 0 < k < 1,则纵向压缩。
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y = f(kx) horizontally compresses the graph if k > 1, and stretches it if 0 < k < 1.
y = f(kx) 若 k > 1,则横向压缩;若 0 < k < 1,则横向拉伸。
Example | 示例: y = 3x² is the parabola y = x² stretched vertically by a factor of 3. y = (x/2)² = x²/4 is stretched horizontally by a factor of 2.
示例:y = 3x² 是 y = x² 纵向拉伸 3 倍。y = (x/2)² = x²/4 是横向拉伸 2 倍。
9. Combining Transformations | 组合变换
When multiple transformations are applied in sequence, the order matters. For example, to graph y = 2(x – 1)² + 3, we start with y = x², shift right by 1 unit, stretch vertically by a factor of 2, and shift up by 3 units.
当连续应用多个变换时,顺序很重要。例如,要绘制 y = 2(x – 1)² + 3,我们从 y = x² 开始,向右平移 1 个单位,纵向拉伸 2 倍,再向上平移 3 个单位。
Worked Example | 例题: Describe the transformations from y = 1/x to y = 1/(x – 2) + 4.
例题:描述从 y = 1/x 到 y = 1/(x – 2) + 4 的变换。
First, y = 1/(x – 2) is a translation of y = 1/x by 2 units to the right. Then y = 1/(x – 2) + 4 is a translation by 4 units upward. So the graph shifts right 2 and up 4.
首先,y = 1/(x – 2) 是 y = 1/x 向右平移 2 个单位。然后 y = 1/(x – 2) + 4 是向上平移 4 个单位。因此,图像向右平移 2 个单位,再向上平移 4 个单位。
10. Reading Graphs | 读图
To find the domain and range from a graph, look at the x-values covered by the curve and the y-values covered by the curve.
要从图像中求定义域和值域,需观察曲线覆盖的 x 值范围和 y 值范围。
For example
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