Functions and Mappings | 函数与映射

📚 Functions and Mappings | 函数与映射

Functions and mappings are fundamental to Edexcel A-Level Pure Mathematics. This revision guide explains the key definitions, notation, graphical tests and algebraic techniques you need for domain, range, composite functions and inverse functions.

函数与映射是 Edexcel A-Level 纯数学的基础内容。本复习指南讲解关键定义、符号、图像检验以及处理定义域、值域、复合函数和反函数所需的代数技巧。

1. Mapping Terminology | 映射术语

A mapping takes each element of a starting set and assigns it to an element of a finishing set. In A-Level questions, the starting set is usually called the domain and the finishing set is the codomain.

映射将起始集合中的每个元素对应到终止集合中的一个元素。在 A-Level 考题中,起始集合通常称为定义域,终止集合称为上域。

The range is the set of outputs that the mapping actually produces from the given domain. It is always a subset of the codomain, so the two terms must not be confused.

值域是映射在给定定义域下实际产生的所有输出组成的集合。它总是上域的子集,因此这两个术语不能混淆。

Domain → Mapping → Range ⊆ Codomain


2. What Makes a Function? | 什么构成了函数?

A function is a mapping with one crucial rule: every input in the domain must have exactly one output. If a single input can produce two different outputs, the mapping is not a function.

函数是一种映射,但有一条核心规则:定义域中的每个输入必须恰好有一个输出。如果一个输入可能产生两个不同输出,那么该映射就不是函数。

Therefore, one-to-one and many-to-one mappings can be functions, but one-to-many mappings cannot. Graphically, a curve represents a function only if any vertical line crosses it at most once.

因此,一对一和多对一映射可以构成函数,而一对多映射不能。从图像上看,只有当任意一条竖直线与曲线至多相交一次时,该曲线才表示一个函数。


3. Domain, Codomain and Range | 定义域、上域和值域

The domain is the set of allowed input values, often written as x ∈ ℝ, x > 0, x ≠ 2 or using interval notation. The codomain is stated by the function definition; the range must be calculated or deduced from the graph.

定义域是允许输入的集合,通常写作 x ∈ ℝ、x > 0、x ≠ 2 或使用区间表示。上域由函数定义给出,而值域需要通过计算或图像推断。

For example, f(x) = x² with domain x ∈ ℝ has codomain ℝ, but its range is [0, ∞) because squares are never negative. Restrictions such as square roots, logarithms and denominators often limit the domain.

例如,f(x) = x² 的定义域为 x ∈ ℝ,上域为 ℝ,但其值域为 [0, ∞),因为平方永远不会为负。平方根、对数和分母等限制通常会缩小定义域。


4. Function Notation and Evaluation | 函数符号与求值

Function notation f(x) = 3x − 5 means that the rule is applied to an input x. To evaluate f(2), replace x by 2: f(2) = 3(2) − 5 = 1.

函数符号 f(x) = 3x − 5 表示把该规则作用于输入 x。求 f(2) 时,用 2 替换 x:f(2) = 3(2) − 5 = 1。

You may also see mapping notation f : x ↦ 3x − 5. Solving f(x) = k means setting the rule equal to k and finding the input values that satisfy it.

你还会看到映射符号 f : x ↦ 3x − 5。解方程 f(x) = k 就是令规则等于 k,并找出满足该方程的输入值。


5. One-to-One and Many-to-One Functions | 一对一与多对一函数

A one-to-one function, also called injective, gives a different output for every different input. Its graph passes the horizontal line test: any horizontal line meets the graph at most once.

一对一函数又称单射函数,每个不同输入都对应不同的输出。其图像通过水平线检验:任何水平线与图像至多相交一次。

A many-to-one function allows two or more inputs to give the same output, such as f(x) = x². These functions are still valid, but they do not have inverses unless the domain is restricted first.

多对一函数允许多个输入产生相同输出,例如 f(x) = x²。这类函数仍然是有效函数,但除非先限制定义域,否则它们没有反函数。


6. Composite Functions | 复合函数

The composite function gf(x) means apply f first, then apply g to the result. Algebraically, gf(x) = g(f(x)). The order matters: fg(x) is usually different from gf(x).

复合函数 gf(x) 表示先作用 f,再将结果代入 g。代数上,gf(x) = g(f(x))。顺序很重要:fg(x) 通常与 gf(x) 不同。

The domain of gf consists of inputs x that belong to the domain of f and for which f(x) lies in the domain of g. This is a common Edexcel pitfall.

复合函数 gf 的定义域由既属于 f 的定义域、又能使 f(x) 落在 g 的定义域中的输入组成。这是 Edexcel 考试中的常见失分点。

gf(x) = g(f(x)) ≠ f(g(x))


7. Inverse Functions | 反函数

The inverse function f⁻¹(x) reverses the effect of f. Only one-to-one functions have an inverse over their whole domain; a many-to-one function must first have its domain restricted.

反函数 f⁻¹(x) 逆转函数 f 的作用。只有一对一函数在整个定义域上才有反函数;多对一函数必须先限制定义域。

To find an inverse, write y = f(x), rearrange to make x the subject, then swap x and y. The domain and range of f and f⁻¹ are swapped.

求反函数时,先写 y = f(x),整理使 x 成为主项,然后交换 x 和 y。f 与 f⁻¹ 的定义域和值域互相交换。

f(x) = 2x + 3 → f⁻¹(x) = (x − 3)/2


8. Restricting the Domain | 限制定义域

To make a many-to-one function invertible, choose a section of the graph that passes the horizontal line test. For f(x) = x², the usual restriction is x ≥ 0, giving f⁻¹(x) = √x.

要使多对一函数可逆,需选取图像中通过水平线检验的一段。对于 f(x) = x²,通常限制为 x ≥ 0,从而得到 f⁻¹(x) = √x。

For quadratic functions, complete the square to find the vertex. Restricting to one side of the vertex, such as x ≥ 2 for f(x) = (x − 2)², creates a one-to-one function.

对于二次函数,可通过配平方找到顶点。限制在顶点的一侧,例如 f(x) = (x − 2)² 取 x ≥ 2,就可构造出一对一函数。


9. Modulus Functions as Mappings | 绝对值函数作为映射

The modulus function f(x) = |x| is defined by |x| = x when x ≥ 0 and |x| = −x when x < 0. Its graph is a V-shape with vertex at the origin and range y ≥ 0.

绝对值函数 f(x) = |x| 定义为:当 x ≥ 0 时 |x| = x,当 x < 0 时 |x| = −x。其图像是以原点为顶点的 V 形,值域为 y ≥ 0。

Because |−3| = |3| = 3, the modulus mapping is many-to-one. It can be used inside composite functions, and solving modulus equations often produces two cases.

由于 |−3| = |3| = 3,绝对值映射是多对一的。它可出现在复合函数中,解绝对值方程时通常会产生两种情形。


10. Graphical Tests and Exam Tips | 图像检验与考试技巧

Use the vertical line test to confirm a graph represents a function, and the horizontal line test to check whether it is one-to-one. Sketching graphs helps identify the range and any restrictions.

使用竖直线检验确认图像是否表示函数,使用水平线检验判断是否一对一。画草图有助于确定值域和任何限制。

Common mistakes include confusing range with codomain, forgetting to check the domain of a composite function, and finding an inverse without first proving the function is one-to-one. Always write domain and range using correct set notation.

常见错误包括混淆值域与上域、忘记检查复合函数的定义域,以及在未证明函数一对一之前就求反函数。务必使用正确的集合符号书写定义域和值域。


Published by TutorHao | Mathematics Revision Series | aleveler.com

更多咨询请联系16621398022(同微信)

Comments

屏轩国际教育cambridge primary/secondary checkpoint, cat4, ukiset,ukcat,igcse,alevel,PAT,STEP,MAT, ibdp,ap,ssat,sat,sat2课程辅导,国外大学本科硕士研究生博士课程论文辅导

This site uses Akismet to reduce spam. Learn how your comment data is processed.

Discover more from aleveler.com

Subscribe now to keep reading and get access to the full archive.

Continue reading