📚 Inverse Trigonometric Functions | 反三角函数
Inverse trigonometric functions, often called arcus functions, reverse the action of sine, cosine and tangent. For the Edexcel A-Level Mathematics specification, arcsin x, arccos x and arctan x are essential tools in differentiation, integration and the solution of trigonometric equations. They appear year after year in Pure Mathematics papers, so a secure understanding of their domains, ranges and calculus is non-negotiable for top grades.
反三角函数(也称反圆函数)用于逆转正弦、余弦和正切的作用。在 Edexcel A-Level 数学考纲中,arcsin x、arccos x 与 arctan x 是微分、积分及解三角方程的必备工具。它们在纯数试卷中年年出现,因此扎实掌握它们的定义域、值域以及相关微积分结论,是冲击高分的必要条件。
1. Why Trig Functions Must Be Restricted | 为什么必须限制三角函数的定义域
A function can only have an inverse if it is one-to-one, meaning every output corresponds to exactly one input. Sine, cosine and tangent are periodic, so they take the same value infinitely many times across their natural domains. For instance, sin(0) = sin(π) = sin(2π) = 0, so without restrictions there would be no unique value for sin⁻¹(0).
一个函数只有满足一一对应时才有反函数,即每个函数值只对应唯一一个自变量。正弦、余弦和正切都是周期函数,在自然定义域上同一个函数值会出现无数次。例如 sin(0) = sin(π) = sin(2π) = 0,若不施加限制,sin⁻¹(0) 就没有唯一确定的值。
To fix this, we restrict each trigonometric function to a chosen principal interval on which it is strictly monotonic (always increasing or always decreasing). On such an interval the function is one-to-one, and the inverse can be defined cleanly. The inverse functions are usually written as arcsin x, arccos x and arctan x (the notation sin⁻¹x is also used).
为解决这一问题,我们将每个三角函数限制在一个选定的“主区间”上,使函数在该区间上严格单调(始终递增或始终递减)。在这样的区间上函数是一一对应的,反函数便可被干净地定义。反函数通常写作 arcsin x、arccos x 与 arctan x(有时也写作 sin⁻¹x)。
2. Defining arcsin x | 反正弦函数 arcsin x
If y = arcsin x, then x = sin y, where the principal value of y is chosen in the interval -π/2 ≤ y ≤ π/2. The domain of arcsin x is -1 ≤ x ≤ 1, and its range is -π/2 ≤ y ≤ π/2. On this interval sine is strictly increasing, so arcsin x is also strictly increasing.
若 y = arcsin x,则 x = sin y,其中 y 的主值选在区间 -π/2 ≤ y ≤ π/2 内。arcsin x 的定义域为 -1 ≤ x ≤ 1,值域为 -π/2 ≤ y ≤ π/2。由于正弦函数在该区间上严格递增,arcsin x 也严格递增。
Three values are especially worth memorising:
三个特殊值特别值得记住:
-
arcsin(0) = 0 because sin(0) = 0
arcsin(0) = 0,因为 sin(0) = 0
-
arcsin(1) = π/2 because sin(π/2) = 1
arcsin(1) = π/2,因为 sin(π/2) = 1
-
arcsin(-1) = -π/2 because sin(-π/2) = -1
arcsin(-1) = -π/2,因为 sin(-π/2) = -1
3. Defining arccos x | 反余弦函数 arccos x
If y = arccos x, then x = cos y, where the principal value of y is chosen in the interval 0 ≤ y ≤ π. The domain of arccos x is -1 ≤ x ≤ 1, and its range is 0 ≤ y ≤ π. On this interval cosine is strictly decreasing, so arccos x is strictly decreasing as well.
若 y = arccos x,则 x = cos y,其中 y 的主值选在区间 0 ≤ y ≤ π 内。arccos x 的定义域为 -1 ≤ x ≤ 1,值域为 0 ≤ y ≤ π。由于余弦函数在该区间上严格递减,arccos x 也严格递减。
Key values include:
关键值包括:
-
arccos(0) = π/2 because cos(π/2) = 0
arccos(0) = π/2,因为 cos(π/2) = 0
-
arccos(1) = 0 because cos(0) = 1
arccos(1) = 0,因为 cos(0) = 1
-
arccos(-1) = π because cos(π) = -1
arccos(-1) = π,因为 cos(π) = -1
4. Defining arctan x | 反正切函数 arctan x
If y = arctan x, then x = tan y, where the principal value of y is chosen in the open interval -π/2 < y < π/2. Unlike arcsin x and arccos x, the domain of arctan x is all real numbers, ℝ. The range is the open interval -π/2 < y < π/2.
若 y = arctan x,则 x = tan y,其中 y 的主值选在开区间 -π/2 < y < π/2 内。与 arcsin x 和 arccos x 不同,arctan x 的定义域是全体实数 ℝ。其值域为开区间 -π/2 < y < π/2。
Because tan y approaches +∞ as y → (π/2)⁻ and -∞ as y → (-π/2)⁺, the graph of arctan x has two horizontal asymptotes, y = π/2 and y = -π/2. The function is strictly increasing and passes through the origin.
由于当 y → (π/2)⁻ 时 tan y 趋于 +∞,当 y → (-π/2)⁺ 时 tan y 趋于 -∞,arctan x 的图像有两条水平渐近线 y = π/2 与 y = -π/2。该函数严格递增且经过原点。
5. Summary Table of Domains and Ranges | 定义域与值域总结表
The three principal inverse trigonometric functions are compared below. You should be able to reproduce this table from memory in an exam.
下表对比三个主要反三角函数。你应当能够在考试中凭记忆写出这张表。
| Function 函数 | Domain 定义域 | Principal Range 主值范围 | Monotonicity 单调性 |
| arcsin x | -1 ≤ x ≤ 1 | -π/2 ≤ y ≤ π/2 | Increasing 递增 |
| arccos x | -1 ≤ x ≤ 1 | 0 ≤ y ≤ π | Decreasing 递减 |
| arctan x | x ∈ ℝ | -π/2 < y < π/2 | Increasing 递增 |
A common exam trap is writing the range of arcsin x as [0, π], which actually belongs to arccos x. Always match the range to the function explicitly.
一个常见考场陷阱是把 arcsin x 的值域写成 [0, π],那其实是 arccos x 的值域。务必把值域与函数一一对应起来。
6. Graphs and Key Features | 图像与关键特征
The graph of y = arcsin x is obtained by reflecting the graph of y = sin x restricted to [-π/2, π/2] in the line y = x. Likewise, y = arccos x is the reflection of restricted cosine, and y = arctan x is the reflection of restricted tangent.
y = arcsin x 的图像是将限制在 [-π/2, π/2] 上的 y = sin x 关于直线 y = x 反射得到。同理,y = arccos x 是限制余弦的反射,y = arctan x 是限制正切的反射。
-
y = arcsin x passes through (-1, -π/2), (0, 0) and (1, π/2), with vertical-looking tangents at the endpoints.
y = arcsin x 经过 (-1, -π/2)、(0, 0) 和 (1, π/2),在端点处切线近乎竖直。
-
y = arccos x passes through (-1, π), (0, π/2) and (1, 0), falling from left to right.
y = arccos x 经过 (-1, π)、(0, π/2) 和 (1, 0),从左到右递减。
-
y = arctan x passes through the origin and approaches the asymptotes y = π/2 and y = -π/2 without crossing them.
y = arctan x 经过原点,并无限接近渐近线 y = π/2 与 y = -π/2 但永不相交。
7. The Identity arcsin x + arccos x = π/2 | 恒等式 arcsin x + arccos x = π/2
For every x in [-1, 1], the relationship arcsin x + arccos x = π/2 always holds. This is a direct analogue of the complementary angle identity sin θ = cos(π/2 – θ), written in inverse form.
对任意 x ∈ [-1, 1],恒有 arcsin x + arccos x = π/2。这是余角恒等式 sin θ = cos(π/2 – θ) 的反函数形式,二者完全对应。
A quick proof: let θ = arcsin x. Then sin θ = x, so cos(π/2 – θ) = sin θ = x. Since θ ∈ [-π/2, π/2], we have π/2 – θ ∈ [0, π], which is exactly the principal range of arccos x. Hence arccos x = π/2 – θ, and arcsin x + arccos x = π/2.
简要证明:令 θ = arcsin x,则 sin θ = x,故 cos(π/2 – θ) = sin θ = x。由于 θ ∈ [-π/2, π/2],可得 π/2 – θ ∈ [0, π],恰好落在 arccos x 的主值范围内。因此 arccos x = π/2 – θ,即 arcsin x + arccos x = π/2。
Similarly, for x > 0, arctan x + arctan(1/x) = π/2. This follows from the symmetry of the tangent function about θ = π/4 and is useful in integration problems.
Published by TutorHao | A-Level Mathematics Revision Series | aleveler.com
更多咨询请联系16621398022(同微信)
屏轩国际教育cambridge primary/secondary checkpoint, cat4, ukiset,ukcat,igcse,alevel,PAT,STEP,MAT, ibdp,ap,ssat,sat,sat2课程辅导,国外大学本科硕士研究生博士课程论文辅导