📚 Simplifying a cos x ± b sin x: The Harmonic Form | 辅助角形式:化简 a cos x ± b sin x
This revision guide covers the Edexcel A-Level Pure Mathematics topic of rewriting expressions of the form a cos x ± b sin x as a single sine or cosine function. This technique, often called the harmonic form or R-form, is essential for solving trigonometric equations, finding maximum and minimum values, and modelling periodic behaviour.
本复习指南涵盖 Edexcel A-Level 纯数学中把 a cos x ± b sin x 形式改写为单一正弦或余弦函数的内容。这种技巧通常称为辅助角形式或 R 形式,对于解三角方程、求最大值与最小值以及建立周期模型至关重要。
1. What Is the Harmonic Form? | 什么是辅助角形式?
An expression such as 3 cos x + 4 sin x contains both sine and cosine terms with the same angle x. It is not immediately clear what its maximum value is or how to solve an equation like 3 cos x + 4 sin x = 2. The harmonic form rewrites the expression as a single trigonometric function, usually R cos(x − α) or R sin(x + α).
像 3 cos x + 4 sin x 这样的表达式同时含有同角 x 的正弦项和余弦项。我们很难直接看出它的最大值,也不容易解出 3 cos x + 4 sin x = 2 这样的方程。辅助角形式把它改写为单一三角函数,通常写成 R cos(x − α) 或 R sin(x + α)。
The letters R and α are chosen so that the original two-term expression becomes one term with an amplitude R and a phase shift α. This makes many problems much easier to handle.
我们选取 R 和 α,使原来的两项表达式变成一项,振幅为 R,相移为 α。这样很多问题都更容易处理。
2. Why Do We Need It? | 为什么需要它?
In Edexcel exam questions, you may be asked to express a cos x + b sin x in the form R cos(x − α). Once this is done, you can read off the maximum and minimum values instantly, solve equations that would otherwise require complicated identities, and sketch transformations of basic trigonometric curves.
在 Edexcel 考试题中,你可能会被要求把 a cos x + b sin x 表示成 R cos(x − α) 的形式。完成后,你可以立刻读出最大值和最小值,解出原本需要复杂恒等式的方程,并画出基本三角曲线的变换图形。
Without the harmonic form, solving an equation like 5 cos x + 12 sin x = 6 would be very difficult. With the harmonic form, it reduces to a simple equation such as 13 cos(x − 67.4°) = 6.
如果没有辅助角形式,解 5 cos x + 12 sin x = 6 这样的方程会非常困难。使用辅助角形式后,它就化简为 13 cos(x − 67.4°) = 6 这样的简单方程。
3. The Standard Forms | 标准形式
There are four standard ways to write the harmonic form. The two most common in Edexcel exams are given below, where R > 0 and α is an acute angle or an angle adjusted to the correct quadrant.
辅助角形式有四种标准写法。Edexcel 考试中最常见的两种如下,其中 R > 0,α 是锐角或按正确象限调整后的角。
a cos x + b sin x = R cos(x − α)
a cos x + b sin x = R sin(x + α)
You can also use the equivalent forms a cos x − b sin x = R cos(x + α) or a sin x ± b cos x = R sin(x ± β). The key is to match the coefficients of cos x and sin x correctly.
你也可以使用等价形式 a cos x − b sin x = R cos(x + α) 或 a sin x ± b cos x = R sin(x ± β)。关键是要正确匹配 cos x 和 sin x 的系数。
4. Deriving R and α | R 与 α 的推导
Consider the identity for cos(x − α):
考虑 cos(x − α) 的恒等式:
R cos(x − α) = R cos x cos α + R sin x sin α
If this must equal a cos x + b sin x, then comparing coefficients gives
如果它必须等于 a cos x + b sin x,那么比较系数可得
R cos α = a, R sin α = b
Squaring and adding these two equations eliminates α and gives R:
将两式平方后相加可消去 α,得到 R:
R = √(a² + b²)
Dividing the second equation by the first gives α:
用第二式除以第一式可得到 α:
tan α = b/a
Therefore α is found by taking the inverse tangent, but you must always check the quadrant using the signs of a and b.
因此 α 可以通过取反正切求得,但你必须根据 a 和 b 的符号检查象限。
5. Choosing the Correct Quadrant | 选择正确的象限
The equation tan α = b/a alone does not uniquely determine α because the tangent function has period 180°. You must also look at the signs of a = R cos α and b = R sin α to decide which quadrant α lies in.
仅凭 tan α = b/a 无法唯一确定 α,因为正切函数的周期是 180°。你还必须根据 a = R cos α 和 b = R sin α 的符号判断 α 所在的象限。
The table below summarises the quadrant choice for α when writing a cos x + b sin x = R cos(x − α).
下表总结了在写 a cos x + b sin x = R cos(x − α) 时 α 的象限选择。
| Sign of a | Sign of b | Quadrant of α | α range |
|---|---|---|---|
| positive | positive | First | 0° to 90° |
| negative | positive | Second | 90° to 180° |
| negative | negative | Third | 180° to 270° |
| positive | negative | Fourth | 270° to 360° |
In many basic exam questions, a and b are both positive, so α is simply an acute angle. When one sign is negative, you must add or subtract 180° or use a negative angle such as −60° instead of 300°.
在许多基础考试题中,a 和 b 都是正数,所以 α 就是一个锐角。当有一个符号为负时,你必须加或减 180°,或者使用 −60° 这样的负角而不是 300°。
6. Worked Example 1: 3 cos x + 4 sin x | 例题1:3 cos x + 4 sin x
Express 3 cos x + 4 sin x in the form R cos(x − α), where R > 0 and 0° < α < 90°.
把 3 cos x + 4 sin x 表示成 R cos(x − α) 的形式,其中 R > 0,0° < α < 90°。
First find R using R = √(a² + b²):
首先用 R = √(a² + b²) 求 R:
R = √(3² + 4²) = √(9 + 16) = √25 = 5
Then find α using tan α = b/a:
然后用 tan α = b/a 求 α:
tan α = 4/3, α = arctan(4/3) ≈ 53.13°
Since both a = 3 and b = 4 are positive, α is in the first quadrant. Therefore
因为 a = 3 和 b = 4 都是正数,所以 α 在第一象限。因此
3 cos x + 4 sin x = 5 cos(x − 53.13°)
In radians, this is approximately 5 cos(x − 0.927 rad). This single-term form immediately shows that the maximum value is 5 and the minimum value is −5.
用弧度表示,这大约是 5 cos(x − 0.927 rad)。这个单项形式立刻表明最大值是 5,最小值是 −5。
7. Worked Example 2: cos x − √3 sin x | 例题2:cos x − √3 sin x
Express cos x − √3 sin x in the form R cos(x + α), where R > 0 and 0° < α < 90°.
把 cos x − √3 sin x 表示成 R cos(x + α) 的形式,其中 R > 0,0° < α < 90°。
First compare with R cos(x + α) = R cos x cos α − R sin x sin α. Here the coefficient of cos x is 1 and the coefficient of sin x is −√3. We set R cos α = 1 and R sin α = √3, which makes the expression R cos(x + α) because the sine term is negative.
首先与 R cos(x + α) = R cos x cos α − R sin x sin α 比较。这里 cos x 的系数是 1,sin x 的系数是 −√3。我们令 R cos α = 1,R sin α = √3,这样该表达式就是 R cos(x + α),因为正弦项为负。
Find R:
求 R:
R = √(1² + (√3)²) = √(1 + 3) = √4 = 2
Find α:
求 α:
tan α = √3/1 = √3, α = 60°
Therefore
因此
cos x − √3 sin x = 2 cos(x + 60°)
This is an important check: a negative sine coefficient produces a plus sign inside the cosine bracket.
这是一个重要的检查:正弦项系数为负时,余弦括号内会出现加号。
8. Solving Equations with the Harmonic Form | 用辅助角形式解方程
Once an expression is in harmonic form, solving equations becomes straightforward. For example, solve 3 cos x + 4 sin x = 2 for 0° ≤ x ≤ 360°.
一旦表达式化为辅助角形式,解方程就变得简单。例如,解 3 cos x + 4 sin x = 2,其中 0° ≤ x ≤ 360°。
From Worked Example 1, we have 5 cos(x − 53.13°) = 2, so
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