📚 Solving Quadratic Equations | 解二次方程
Quadratic equations are a central topic in the Edexcel IGCSE Mathematics syllabus. This revision guide explains the key methods, useful formulas and common pitfalls.
二次方程是 Edexcel IGCSE 数学大纲的核心内容。本复习指南讲解主要方法、常用公式和常见陷阱。
1. What is a Quadratic Equation? | 什么是二次方程?
A quadratic equation is an equation of the form ax² + bx + c = 0, where a, b and c are constants and a ≠ 0. The highest power of x is 2.
二次方程是形如 ax² + bx + c = 0 的方程,其中 a、b、c 是常数,且 a ≠ 0。x 的最高次数是 2。
If a = 0, the equation becomes linear, so the condition a ≠ 0 is essential.
如果 a = 0,方程就变成一次方程,因此条件 a ≠ 0 至关重要。
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Examples of quadratic equations: x² − 5x + 6 = 0, 2x² + 3x − 2 = 0.
二次方程的例子:x² − 5x + 6 = 0,2x² + 3x − 2 = 0。
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Non-examples: x + 3 = 0, x³ − 1 = 0.
反例:x + 3 = 0,x³ − 1 = 0。
2. Solving by Factorisation | 因式分解法
Factorisation is often the quickest method when the quadratic can be written as a product of two linear factors.
当二次式可以写成两个一次因式相乘时,因式分解通常是最快的方法。
Step 1: Write the equation in the form ax² + bx + c = 0.
第一步:将方程写成 ax² + bx + c = 0 的形式。
Step 2: Factorise the left-hand side into two brackets.
第二步:将左边分解为两个括号的乘积。
Step 3: Set each bracket equal to zero and solve.
第三步:令每个括号等于零并求解。
Example: x² − 5x + 6 = 0 → (x − 2)(x − 3) = 0 → x = 2 or x = 3.
示例:x² − 5x + 6 = 0 → (x − 2)(x − 3) = 0 → x = 2 或 x = 3。
Always check whether the coefficient a has a common factor first.
务必先检查系数 a 是否有公因数。
3. Solving by Completing the Square | 配方法
Completing the square rewrites x² + bx as (x + b/2)² − (b/2)². For the full quadratic, we include the constant term.
配方法将 x² + bx 改写为 (x + b/2)² − (b/2)²。对于完整二次式,我们还要加入常数项。
x² + bx + c = (x + b/2)² − (b/2)² + c.
x² + bx + c = (x + b/2)² − (b/2)² + c。
If a ≠ 1, divide the whole equation by a first, or factor a out of the x terms.
如果 a ≠ 1,先将整个方程除以 a,或者从含 x 的项中提出 a。
Example: x² + 6x + 4 = 0 → (x + 3)² − 5 = 0 → (x + 3)² = 5 → x = −3 ± √5.
示例:x² + 6x + 4 = 0 → (x + 3)² − 5 = 0 → (x + 3)² = 5 → x = −3 ± √5。
This method is particularly useful for solving equations with irrational roots and for finding the turning point of a parabola.
该方法特别适用于求解根为无理数的方程,以及求抛物线的顶点。
4. The Quadratic Formula | 求根公式
The quadratic formula solves any quadratic equation. For ax² + bx + c = 0:
求根公式可以解任意二次方程。对于 ax² + bx + c = 0:
x = (−b ± √(b² − 4ac)) / (2a)
x = (−b ± √(b² − 4ac)) / (2a)
Substitute the values of a, b and c carefully, paying attention to signs.
小心代入 a、b、c 的值,特别注意符号。
Write the two roots separately if required: x = (−b + √Δ)/(2a) and x = (−b − √Δ)/(2a).
如果需要,分别写出两个根:x = (−b + √Δ)/(2a) 和 x = (−b − √Δ)/(2a)。
5. The Discriminant | 判别式
The discriminant is the expression under the square root: Δ = b² − 4ac.
判别式是根号下的表达式:Δ = b² − 4ac。
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If Δ > 0, there are two distinct real roots.
如果 Δ > 0,方程有两个不相等的实数根。
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If Δ = 0, there is exactly one repeated real root.
如果 Δ = 0,方程有一个二重实数根。
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If Δ < 0, there are no real roots; the roots are complex.
如果 Δ < 0,方程没有实数根;根为复数。
For example, x² + 2x + 5 = 0 has Δ = 4 − 20 = −16, so it has no real roots.
例如,x² + 2x + 5 = 0 的 Δ = 4 − 20 = −16,因此没有实数根。
6. Roots and Coefficients | 根与系数的关系
If α and β are the roots of ax² + bx + c = 0, then:
如果 α 和 β 是 ax² + bx + c = 0 的两个根,则:
α + β = −b/a, αβ = c/a
α + β = −b/a,αβ = c/a
These relationships help you check your answers or form a quadratic from given roots.
这些关系可帮助你检验答案,或由已知根构造二次方程。
For example, if the roots are 2 and 5, then the sum is 7 and the product is 10, so the equation is x² − 7x + 10 = 0.
例如,若两根为 2 和 5,则和为 7,积为 10,所对应的方程为 x² − 7x + 10 = 0。
7. Equations Involving Fractions | 含分数的二次方程
Some equations look like fractions but reduce to quadratics after multiplying by the common denominator.
有些方程看似含分数,但乘以公分母后可化为二次方程。
Example: 1/x + 1/(x + 2) = 1
示例:1/x + 1/(x + 2) = 1
Multiply every term by x(x + 2): (x + 2) + x = x(x + 2).
每一项乘以 x(x + 2):(x + 2) + x = x(x + 2)。
Simplify to x² = 2x + 2, or x² − 2x − 2 = 0. Then solve using the formula.
化简得 x² = 2x + 2,即 x² − 2x − 2 = 0。然后使用公式求解。
Always check that your solutions do not make any denominator zero.
务必检查解是否会使分母为零。
8. Quadratic Graphs | 二次函数图像
The graph of y = ax² + bx + c is a parabola. If a > 0, it opens upwards; if a < 0, it opens downwards.
y = ax² + bx + c 的图像是抛物线。如果 a > 0,开口向上;如果 a < 0,开口向下。
The x-intercepts are the real roots of ax² + bx + c = 0. The y-intercept is c.
与 x 轴的交点就是 ax² + bx + c = 0 的实数根。与 y 轴的交点是 c。
The axis of symmetry is x = −b/(2a), and the vertex lies on this line.
对称轴是 x = −b/(2a),顶点就在这条直线上。
Using completing the square, y = a(x − h)² + k, the vertex is (h, k).
利用配方法,y = a(x − h)² + k,顶点为 (h, k)。
9. Setting Up Quadratic Equations from Word Problems | 由实际问题建立二次方程
Many exam questions describe a real-life situation and ask you to form and solve a quadratic equation.
许多考试题目会描述一个实际问题,要求你列出并求解二次方程。
Read the problem carefully and define a variable, for example x for the unknown number.
仔细阅读题目并定义变量,例如用 x 表示未知数。
Translate the words into an equation. Common contexts include area, product of consecutive numbers, and projectile motion.
将文字转化为方程。常见情境包括面积、连续整数之积、抛体运动。
Example: The product of two consecutive positive odd integers is 99. Find them.
示例:两个连续正奇数的乘积是 99,求这两个数。
Let the smaller integer be n, then n(n + 2) = 99, so n² + 2n − 99 = 0.
设较小奇数为 n,则 n(n + 2) = 99,所以 n² + 2n − 99 = 0。
Factorising: (n + 11)(n − 9) = 0, so n = 9 (positive). The integers are 9 and 11.
因式分解
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