Solving Simultaneous Equations | 解联立方程

📚 Solving Simultaneous Equations | 解联立方程

Simultaneous equations are a core topic in IGCSE Mathematics. They test your ability to handle multiple algebraic relationships at once and appear frequently in both non-calculator and calculator papers. Mastering them opens the door to solving real-world problems involving two or more unknown quantities.

联立方程是IGCSE数学的核心内容。它考察你同时处理多个代数关系的能力,并且在非计算器和计算器试卷中都很常见。掌握联立方程,意味着你能够解决涉及两个或多个未知量的实际问题。


1. What Are Simultaneous Equations? | 什么是联立方程?

Simultaneous equations are a set of equations that share the same variables. A solution to the system is a set of values that satisfies every equation in the system at the same time.

联立方程是共享相同变量的一组方程。该方程组的解是一组同时满足其中每个方程的数值。

For two linear equations with two unknowns, there are three possible outcomes:

对于含有两个未知数的两个线性方程,有且仅有三种可能的结果:

  • One unique solution — the lines intersect at a single point.

    唯一解——两条直线相交于一点。

  • No solution — the lines are parallel and never intersect.

    无解——两条直线平行,永不相交。

  • Infinitely many solutions — the lines are coincident (the same line).

    无穷多解——两条直线重合(是同一条直线)。

x + y = 8, x − y = 2 → x = 5, y = 3

The values x = 5 and y = 3 satisfy both equations, so they form the unique solution of the system.

数值 x = 5 和 y = 3 同时满足两个方程,因此它们构成该方程组的唯一解。


2. The Elimination Method | 消元法

The elimination method involves adding or subtracting the equations to remove one variable. This reduces the system to a single equation in one variable.

消元法通过将两个方程相加或相减来消去一个变量,从而把方程组化为一元一次方程。

Example | 例题:

3x + y = 7 … (1)

2x − y = 3 … (2)

Add equation (1) and equation (2). The y terms cancel because +y and −y sum to zero.

将方程(1)和方程(2)相加,y 项相互抵消,因为 +y 与 −y 的和为零。

3x + 2x = 7 + 3

5x = 10 → x = 2

Now substitute x = 2 into equation (1):

再将 x = 2 代入方程(1):

3(2) + y = 7 → y = 1

Therefore, the solution is x = 2, y = 1.

因此,解为 x = 2,y = 1。

If the coefficients are not opposites, first multiply one or both equations by a constant to make them match or cancel.

如果对应项的系数不是相反数,可以先将一个或两个方程同乘某个常数,使系数相同或相反,再进行加减消元。


3. The Substitution Method | 代入法

The substitution method is especially useful when one variable already has a coefficient of 1, or when one equation is explicitly solved for a variable.

当某个变量系数为1,或者某个方程已经写成“y = …”的形式时,代入法尤为方便。

Example | 例题:

y = 2x + 1 … (1)

x + y = 10 … (2)

Substitute y = 2x + 1 from (1) into (2):

将(1)中的 y = 2x + 1 代入(2):

x + (2x + 1) = 10

3x + 1 = 10 → 3x = 9 → x = 3

Then substitute x = 3 back into (1):

然后把 x = 3 代回(1):

y = 2(3) + 1 = 7

The solution is x = 3, y = 7.

解为 x = 3,y = 7。

Always check your answer by substituting both values into the original equations.

务必把两个值代回原方程进行检验。


4. The Graphical Method | 图象法

Graphically, the solution of two linear equations is the point of intersection of their straight-line graphs.

从图象上看,两个线性方程的解就是两条直线图象的交点坐标。

Example | 例题:

y = x + 1

y = −2x + 7

Plot both lines on the same axes. The point where they cross is the solution.

在同一坐标系中画出两条直线,它们相交的点坐标就是方程组的解。

x 0 1 2
y = x + 1 1 2 3
y = −2x + 7 7 5 3

Both points (2, 3) appear in the tables, so the lines intersect at (2, 3). Hence x = 2, y = 3.

两个表格中都有点 (2, 3),因此两条直线相交于 (2, 3),即 x = 2,y = 3。

The graphical method is useful for estimation, but in an exam you should use algebraic methods when an exact answer is required.

图象法适用于估算,但考试中需要精确答案时,应使用代数方法。


5. Linear and Quadratic Systems | 一次方程与二次方程联立

IGCSE examiners often combine a linear equation with a quadratic equation, such as y = x² − 5. The substitution method is the standard approach here.

IGCSE考试常将一次方程与二次方程结合,例如 y = x² − 5。代入法是比较标准的方法。

Example | 例题:

y = x + 1 … (1)

y = x² − 3 … (2)

Substitute (1) into (2):

将(1)代入(2):

x + 1 = x² − 3

x² − x − 4 = 0

This quadratic does not factorise easily, so use the quadratic formula:

该二次方程不易因式分解,因此使用求根公式:

x = [−(−1) ± √((−1)² − 4 × 1 × (−4))] / (2 × 1)

x = (1 ± √17) / 2

So x ≈ 2.56 or x ≈ −1.56. Use y = x + 1 to find the corresponding y-values:

因此 x ≈ 2.56 或 x ≈ −1.56。再由 y = x + 1 求出对应的 y 值:

y ≈ 3.56 or y ≈ −0.56

There are two solutions: (2.56, 3.56) and (−1.56, −0.56).

方程组有两组解:(2.56, 3.56) 和 (−1.56, −0.56)。

Remember: a line and a quadratic curve can intersect at 0, 1, or 2 points.

注意:一条直线与一条抛物线可能没有交点、有一个交点或两个交点。


6. Special Cases | 特殊情况

Not every system has a single unique solution. Recognising special cases quickly will save you time.

并非每个方程组都有唯一解。快速识别特殊情况可以为你节省时间。

  • Parallel lines: both equations have the same coefficient ratio but different constant terms, e.g. y = 2x + 3 and y = 2x − 5. No solution.

    平行线:两个方程中变量系数之比相同但常项不同,例如 y = 2x + 3 与 y = 2x − 5。无解。

  • Identical lines: one equation is a constant multiple of the other, e.g. 2x + y = 5 and 4x + 2y = 10. Infinitely many solutions.

    重合直线:一个方程是另一个方程的常数倍,例如 2x + y = 5 与 4x + 2y = 10。有无穷多解。

  • Inconsistent system: elimination leads to a false statement such as 0 = 5. No solution.

    矛盾方程组:消元后得到诸如 0 = 5 的错误等式。无解。

In exam questions, if you get a false statement, double-check your working before concluding there is no solution.

在考试中,如果得到错误等式,先检查运算过程,再下“无解”的结论。


7. Word Problems | 应用题

Simultaneous equations are powerful tools for modelling real situations. You need to translate words into mathematical equations.

联立方程是解决现实问题的有力工具。你需要把文字描述转化为数学方程。

Example | 例题:

The sum of two numbers is 15, and their difference is 3. Find the numbers.

两数之和为15,之差为3。求这两个数。

Let the numbers be x and y, where x > y:

设两数为 x 与 y,其中 x > y:

x + y = 15 … (1)

x − y = 3 … (2)

Add the equations:

两式相加:

2x = 18 → x = 9

Then 9 + y = 15, so y = 6.

于是 9 + y = 15,所以 y = 6。

The two numbers are 9 and 6.

这两个数是9和6。

Key steps: define variables clearly, write two independent equations, solve, and give your final answer as a sentence.

关键步骤:清晰设变量,写出两个相互独立的方程,求解,并用完整句子写出最终答案。


8. Common Mistakes | 常见错误

Many students lose marks on this topic due to careless errors. Watch out for the following:

许多学生在这一专题上因粗心而失分。请注意以下几点:

  • Forgetting to multiply both sides of an equation when using elimination.

    用消元法时忘记两边同乘。

  • Making sign errors when substituting negative values, e.g. x − (−3) written as x − 3.

    代入负数时符号出错,例如把 x − (−3) 写成 x − 3。

  • Not checking the solution in both original equations.

    没有把解代回原方程进行验证。

  • When solving quadratic systems, including only one of the two possible solutions.

    解二次方程组时,只写出两个解中的一个。

  • Writing coordinates in the wrong order, (y, x) instead of (x, y).

    坐标顺序写反,写成 (y, x) 而不是 (x, y)。

Developing a checking habit is the single most effective way to avoid these errors.

养成检验的习惯是避免这些错误最有效的方法。


9. Exam Tips | 考试技巧

Use the following strategies to maximise your marks:

以下策略可以帮助你在这类题目中拿到更高的分数:

  • Choose the method that best fits the question: elimination for matching coefficients, substitution for a variable isolated or for quadratic systems.

    选择合适的方法:系数匹配时用消元法;变量已单独写出或含二次方程时用代入法。

  • Show every step. An incorrect final answer still earns method marks if your working is clear.

    写出每一步。即使最终答案错误,清晰的步骤也可获得方法分。

  • If time allows, substitute your answer back into the equations honestly.

    时间允许时,务必把答案代回方程进行验证。

  • For word problems, state what your variables represent before writing equations.

    对于应用题,先声明变量表示什么,再写方程。

  • Round to a sensible degree of accuracy only when the question asks, e.g. 3 significant figures.

    只有在题目要求时才按指定精度取近似值,例如保留3位有效数字。


10. Practice Questions | 练习

Try these questions on your own before checking the answers.

先独立思考完成下面几题,再核对答案。

Question 1 | 题1: Solve x + 2y = 8 and 3x − 2y = 12.

Solution: x = 5, y = 1.5

Question 2 | 题2: Solve y = 3x − 2 and y = 2x² − 5x + 1.

Solution: x = 3, y = 7 and x = 0.5, y = −0.5

Question 3 | 题3: Two pens and three pencils cost $4. Four pens and one pencil cost $6. Find the price of one pen and one pencil.

Solution: pen = $1.40, pencil = $0.40

If you got all three correct, you have mastered the topic. If not, review the relevant section and try again.

三题全对,说明你已经掌握了这一专题。若有不擅长的,请回顾对应章节后再次尝试。


11. Summary | 总结

Simultaneous equations require two key skills: forming equations from information, and solving them accurately. Master elimination, substitution, and the graphical method, and practise enough past-paper questions to build speed.

联立方程需要两种关键能力:从已知信息中构建方程,以及准确求解。掌握消元法、代入法和图象法,并勤练真题以提升速度。

Remember that every method should give the same solution if applied correctly. Use one method to solve and another to check.

记住:方法只要应用正确,结果必然相同。可以用一种方法求解,用另一种方法检验。

With consistent practice, simultaneous equations will become one of the most reliable scoring areas in your IGCSE Mathematics exam.

只要坚持练习,联立方程将成为你IGCSE数学考试中最稳定的得分点之一。


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