Mastering the Technique of Combining a cos x ± b sin x | 合一变形技巧:a cos x ± b sin x 的完全攻略

📚 Mastering the Technique of Combining a cos x ± b sin x | 合一变形技巧:a cos x ± b sin x 的完全攻略

The expression a cos x ± b sin x is one of the most frequently encountered forms in trigonometry, appearing in wave motion, harmonic analysis, and countless examination problems. The technique of rewriting it as a single trigonometric function is called “合一变形” (unification transformation) in Chinese curricula, and it is a cornerstone skill for solving equations, inequalities, and optimization problems.

表达式 a cos x ± b sin x 是三角函数中最常见的形式之一,出现在波动、简谐运动以及无数考题中。将它改写为单一三角函数的方法,在中国课程中被称为“合一变形”,它是解决方程、不等式和最值问题的核心技能。


1. The Core Identity | 核心恒等式

The fundamental formula states that any expression of the form a cos x ± b sin x can be written as R cos(x ∓ α) or R sin(x ± β), where R = √(a² + b²) and α is an auxiliary angle satisfying specific conditions.

基本公式指出,形如 a cos x ± b sin x 的任何表达式都可以写成 R cos(x ∓ α) 或 R sin(x ± β) 的形式,其中 R = √(a² + b²),α 是满足特定条件的辅助角。

a cos x + b sin x = R cos(x − α)

Here R = √(a² + b²), and the angle α is determined by cos α = a/R and sin α = b/R. This choice guarantees that α lies in the correct quadrant.

这里 R = √(a² + b²),辅助角 α 由 cos α = a/R 和 sin α = b/R 确定。这样的选择确保了 α 落在正确的象限中。


2. Determining the Amplitude R | 确定振幅 R

The coefficient R is always the square root of the sum of squares of a and b. It represents the maximum possible value of the combined expression and is independent of the sign between the two terms.

系数 R 始终是 a 与 b 的平方和的平方根。它表示组合表达式的最大可能值,且与两项之间的符号无关。

R = √(a² + b²)

For example, in the expression 3 cos x + 4 sin x, we calculate R = √(3² + 4²) = √(9 + 16) = √25 = 5. The same R applies to 3 cos x − 4 sin x, because the squares eliminate any sign difference.

例如,在表达式 3 cos x + 4 sin x 中,我们计算 R = √(3² + 4²) = √(9 + 16) = √25 = 5。同样的 R 也适用于 3 cos x − 4 sin x,因为平方项消除了任何符号差异。


3. The Auxiliary Angle α | 辅助角 α

Once R is known, the auxiliary angle α is defined by the pair of equations cos α = a/R and sin α = b/R. These two equations together uniquely determine α within the interval [0, 2π).

一旦 R 已知,辅助角 α 由方程组 cos α = a/R 和 sin α = b/R 定义。这两个方程共同在区间 [0, 2π) 内唯一确定 α。

It is essential to use both equations, not just one, to avoid quadrant errors. For instance, if only tan α = b/a were used, angles differing by π would be indistinguishable.

必须同时使用两个方程,而不是只用一个,以避免象限错误。例如,如果只使用 tan α = b/a,则相差 π 的角度将无法区分。

tan α = b/a, but quadrant determined by (a, b)

The sign pair (a, b) directly indicates the quadrant of α. If a > 0 and b > 0, α is in the first quadrant; if a < 0 but b > 0, α is in the second quadrant, and so forth.

符号对 (a, b) 直接指明 α 的象限。若 a > 0 且 b > 0,α 在第一象限;若 a < 0 且 b > 0,α 在第二象限,依此类推。


4. The Four Sign Combinations | 四种符号组合

The expression a cos x ± b sin x yields four distinct cases depending on the signs of a and b. Each case has a preferred unification form.

表达式 a cos x ± b sin x 根据 a 和 b 的符号产生四种不同情形。每种情形都有其偏好的合一形式。

Expression Standard Form Condition
a cos x + b sin x R cos(x − α) cos α = a/R, sin α = b/R
a cos x − b sin x R cos(x + α) cos α = a/R, sin α = b/R
a sin x + b cos x R sin(x + α) sin α = a/R, cos α = b/R
a sin x − b cos x R sin(x − α) sin α = a/R, cos α = b/R

The table above summarizes the four configurations. Notice that the sign inside the final trigonometric function always opposes the sign in the original expression.

上表总结了四种配置。注意最终三角函数内部的符号总是与原始表达式中的符号相反。


5. Worked Example: Positive Coefficients | 示例:正系数情形

Let us transform the expression 4 cos x + 3 sin x into the form R cos(x − α).

让我们将表达式 4 cos x + 3 sin x 变换为 R cos(x − α) 的形式。

R = √(4² + 3²) = 5

Next we compute cos α = 4/5 and sin α = 3/5. Since both values are positive, α lies in the first quadrant, and α = arcsin(3/5) ≈ 0.6435 rad.

接着我们计算 cos α = 4/5 和 sin α = 3/5。由于两个值均为正,α 位于第一象限,α = arcsin(3/5) ≈ 0.6435 弧度。

4 cos x + 3 sin x = 5 cos(x − 0.6435)

The original expression reaches its maximum value of 5 when x − α = 0, i.e., when x = α. This illustrates how unification immediately reveals the extrema.

当 x − α = 0,即 x = α 时,原始表达式达到最大值 5。这说明合一变形立即揭示了极值。


6. Worked Example: Negative Term | 示例:含负项情形

Now consider 5 cos x − 12 sin x. We want to write this as a single cosine function.

现在考虑 5 cos x − 12 sin x。我们希望将其写成单一余弦函数。

R = √(25 + 144) = √169 = 13

Using the second row of our table, we write 5 cos x − 12 sin x = R cos(x + α), where cos α = 5/13 and sin α = 12/13.

使用表第二行,我们写出 5 cos x − 12 sin x = R cos(x + α),其中 cos α = 5/13 且 sin α = 12/13。

5 cos x − 12 sin x = 13 cos(x + 1.176)

Here α ≈ 1.176 rad because both 5 and 12 are positive. The plus sign inside the cosine accounts for the original minus sign.

这里 α ≈ 1.176 弧度,因为 5 和 12 均为正。余弦内部的加号对应于原始表达式中的减号。


7. Choosing Sine Form | 选择正弦形式

In many problems, a sine form is more convenient, especially when the given expression contains sin x first. The conversion follows the same logic but anchors the composite function to sine.

在许多问题中,正弦形式更方便,特别是当给定表达式首先含有 sin x 时。转换遵循相同逻辑,但将复合函数锚定在正弦上。

a sin x + b cos x = R sin(x + β)

Here the auxiliary angle β satisfies sin β = b/R and cos β = a/R. Note that β is found from the coefficients of the cosine term and the sine term in reverse order.

这里辅助角 β 满足 sin β = b/R 和 cos β = a/R。注意 β 是通过余弦项和正弦项的系数反序确定的。

For instance, 3 sin x + 4 cos x yields R = 5 with sin β = 4/5 and cos β = 3/5, so β ≈ 0.9273 rad and the expression equals 5 sin(x + 0.9273).

例如,3 sin x + 4 cos x 产生 R = 5,且 sin β = 4/5、cos β = 3/5,故 β ≈ 0.9273 弧度,表达式等于 5 sin(x + 0.9273)。


8. Common Pitfall: Sign Ambiguity | 常见误区:符号模糊性

The most frequent error students make is determining the auxiliary angle using only the tangent ratio without considering the quadrant. For example, for −3 cos x + 4 sin x, using tan α = 4/(−3) = −4/3 might suggest α ≈ −0.927 rad, which is incorrect.

学生最常犯的错误是仅使用正切比值确定辅助角而不考虑象限。例如,对于 −3 cos x + 4 sin x,使用 tan α = 4/(−3) = −4/3 可能会建议 α ≈ −0.927 弧度,这是错误的。

The correct approach uses cos α = −3/5 and sin α = 4/5. Since cosine is negative and sine is positive, α must be in the second quadrant, giving α ≈ 2.214 rad.

正确方法使用 cos α = −3/5 和 sin α = 4/5。由于余弦为负、正弦为正,α 必在第二象限,得到 α ≈ 2.214 弧度。

−3 cos x + 4 sin x = 5 cos(x − 2.214)

Always verify with a quick numerical check: at x = α, the expression should equal R. This catches sign errors immediately.

始终通过快速数值检验进行验证:在 x = α 处,表达式应等于 R。这能立即捕获符号错误。


9. Applications to Equations | 在方程求解中的应用

Unification is particularly powerful when solving trigonometric equations of the form a cos x + b sin x = c. The transformation reduces the problem to a single cosine function equalling a constant.

在求解形如 a cos x + b sin x = c 的三角方程时,合一变形尤为强大。该变换将问题简化为单一余弦函数等于常数。

Consider the equation 6 cos x + 8 sin x = 5. Unification gives R = 10, so the equation becomes 10 cos(x − α) = 5, where α = arctan(8/6) ≈ 0.9273.

考虑方程 6 cos x + 8 sin x = 5。合一变形给出 R = 10,因此方程变为 10 cos(x − α) = 5,其中 α = arctan(8/6) ≈ 0.9273。

cos(x − α) = 0.5 ⇒ x − α = ±π/3 + 2kπ

Hence x = α ± π/3 + 2kπ for integer k. Without unification, solving such an equation directly would be far more cumbersome.

因此 x = α ± π/3 + 2kπ,其中 k 为整数。若无合一变形,直接求解此类方程将繁琐得多。


10. Applications to Extrema | 在最值问题中的应用

Finding the maximum and minimum values of a cos x ± b sin x over the real numbers is trivial once unified: the range is [−R, R].

一旦完成合一变形,求 a cos x ± b sin x 在实数范围内的最大值和最小值就变得非常简单:其值域为 [−R, R]。

For the function f(x) = 7 cos x − 24 sin x, we have R = √(49 + 576) = 25. Thus the maximum value is 25 and the minimum is −25.

对于函数 f(x) = 7 cos x − 24 sin x,我们有 R = √(49 + 576) = 25。因此最大值为 25,最小值为 −25。

Moreover, the x-values achieving these extrema are exactly x = −α (for the maximum in the cosine form) and x = π − α (for the minimum), where α is the auxiliary angle.

此外,达到这些极值的 x 值恰好是 x = −α(余弦形式中取最大值)和 x = π − α(取最小值),其中 α 是辅助角。

This technique extends naturally to any expression of the form A cos²x + B sin x cos x + C sin²x, which can first be converted to the a cos 2x ± b sin 2x form using double-angle identities.

此技巧自然扩展到形如 A cos²x + B sin x cos x + C sin²x 的任何表达式,可先通过二倍角恒等式转换为 a cos 2x ± b sin 2x 形式。


11. Graphical Interpretation | 图形解释

Graphically, the expression a cos x + b sin x represents the horizontal component of a vector sum. The original function is the projection of a phasor of length R rotating at angular frequency 1, shifted by the phase angle α.

从图形上看,表达式 a cos x + b sin x 表示向量和的水平分量。原始函数是长度为 R、以角频率 1 旋转的相量在水平方向上的投影,并移动了相位角 α。

The unification transformation is equivalent to finding the resultant of two perpendicular vectors: one of length |a| along the cosine axis and one of length |b| along the sine axis.

合一变形等价于求两个垂直向量的合向量:一个沿余弦轴、长度为 |a|,另一个沿正弦轴、长度为 |b|。

R = √(a² + b²), α = atan2(b, a)

The atan2 function, which takes both coordinates into account, is the robust way to compute α programmatically without quadrant ambiguity.

atan2 函数同时考虑两个坐标,是在编程中计算 α 的稳健方法,不产生象限歧义。


12. Practice Blueprint | 练习蓝图

To master this technique, follow this practice sequence until each step becomes automatic.

要掌握此技巧,请遵循以下练习顺序,直至每一步都变得自动化。

  • Step 1: Identify the coefficients a and b, including their signs.
  • Step 2: Compute R = √(a² + b²).
  • Step 3: Determine the auxiliary angle using both cos α = a/R and sin α = b/R.
  • Step 4: Write the unified form with the correct opposite sign inside the function.
  • Step 5: Verify by expanding the result back to the original.
  • 步骤一:识别系数 a 和 b,包括它们的正负号。
  • 步骤二:计算 R = √(a² + b²)。
  • 步骤三:使用 cos α = a/R 和 sin α = b/R 两者确定辅助角。
  • 步骤四:写出合一形式,函数内部使用相反的符号。
  • 步骤五:通过展开结果验证回原始表达式。

Work through at least twenty problems covering all four sign combinations. Pay special attention to cases where a or b is negative, as these produce the majority of errors.

至少完成二十道覆盖全部四种符号组合的练习。特别关注 a 或 b 为负的情形,因为这些情形产生了大多数错误。


By internalising the unification method, you transform a seemingly complex trigonometric expression into a single, easily analysed function. This skill unlocks solutions to a wide family of problems, from wave superposition in physics to signal processing in engineering, and of course to countless examination questions at A-level and beyond.

通过内化合一变形方法,你将看似复杂的三角函数表达式转化为单一、易于分析的函数。这项技能开启了广泛问题的解决之门,从物理学中的波叠加到工程学中的信号处理,当然还包括 A-level 及更高层次无数考题。

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