📚 Simple Harmonic Motion: Basic Concepts & Conditions | 简谐运动的基本概念与条件
Simple harmonic motion (SHM) is one of the most important models in A-Level Physics, describing oscillations that repeat with a constant period and a restoring force proportional to displacement. This article covers the essential definitions, conditions, equations, and graphical representations required for the CIE syllabus.
简谐运动(SHM)是A-Level物理中最重要模型之一,它描述了具有恒定周期、且回复力与位移成正比的往复运动。本文系统梳理CIE考纲要求的核心定义、条件、方程与图像分析。
1. Definition of Simple Harmonic Motion | 简谐运动的定义
Simple harmonic motion is defined as the oscillatory motion of a particle about a fixed equilibrium position, in which the acceleration is directly proportional to the displacement from equilibrium and is always directed towards the equilibrium position.
简谐运动定义为:质点围绕固定平衡位置进行的往复运动,其加速度与相对平衡位置的位移成正比,并且始终指向平衡位置。
a = -ω²x
Here, a is acceleration (m s⁻²), x is displacement from equilibrium (m), and ω is angular frequency (rad s⁻¹). The negative sign indicates the restoring nature of the acceleration.
其中 a 为加速度(m s⁻²),x 为相对平衡位置的位移(m),ω 为角频率(rad s⁻¹)。负号表示加速度具有回复性质。
2. Fundamental Conditions for SHM | 简谐运动的基本条件
For a system to execute true SHM, three conditions must be satisfied simultaneously.
一个系统要真正实现简谐运动,必须同时满足以下三个条件。
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A restoring force must exist that always acts towards the equilibrium position.
必须存在一个始终指向平衡位置的回复力。
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The magnitude of the restoring force must be proportional to the displacement from equilibrium (F ∝ x).
回复力的大小必须与相对平衡位置的位移成正比(F ∝ x)。
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There must be no energy loss; the system is idealised as frictionless and conservative.
系统无能量损失,理想化为无摩擦的保守系统。
These conditions lead directly to the differential equation a = -ω²x, which is the mathematical fingerprint of SHM.
这些条件直接引出微分方程 a = -ω²x,这是简谐运动的数学特征方程。
3. Key Quantities: Displacement, Amplitude, Period | 关键物理量:位移、振幅、周期
Displacement (x) is the distance of the particle from equilibrium at any instant; it is a vector. Amplitude (A) is the maximum displacement from equilibrium; it is always positive.
位移(x)是任意时刻质点相对平衡位置的距离,为矢量;振幅(A)是相对平衡位置的最大位移,恒为正值。
Period (T) is the time taken for one complete oscillation, measured in seconds. Frequency (f) is the number of oscillations per second, measured in hertz (Hz). They are related by f = 1/T.
周期(T)是完成一次全振动所需的时间,单位为秒;频率(f)是每秒内完成振动的次数,单位为赫兹(Hz)。二者关系为 f = 1/T。
T = 2π/ω, f = ω/(2π), ω = 2π/T = 2πf
| Quantity | Symbol | Unit |
| Displacement 位移 | x | m |
| Amplitude 振幅 | A | m |
| Period 周期 | T | s |
| Frequency 频率 | f | Hz |
| Angular frequency 角频率 | ω | rad s⁻¹ |
4. Acceleration and Velocity in SHM | 简谐运动中的加速度与速度
From the defining equation a = -ω²x, we see that acceleration is maximum at the extremes (x = ±A) and zero at equilibrium (x = 0).
由定义方程 a = -ω²x 可知,加速度在两端(x = ±A)处最大,在平衡位置(x = 0)处为零。
Velocity in SHM is given by the formula:
简谐运动的速度公式为:
v = ±ω√(A² – x²)
At equilibrium (x = 0), speed is maximum: v_max = ωA. At the extremes (x = ±A), speed is zero.
在平衡位置(x = 0)处,速率最大:v_max = ωA;在两端(x = ±A)处,速率为零。
This relationship shows that SHM is a continuous exchange between kinetic energy and potential energy, with total mechanical energy remaining constant.
这一关系表明简谐运动是动能与势能之间的持续转换,总机械能保持不变。
5. Displacement-Time Equation | 位移-时间方程
The most general solution to the SHM differential equation, when oscillation starts from the equilibrium position, is a sine function. When it starts from maximum displacement, a cosine function is used.
简谐运动微分方程的最一般解为正弦函数(从平衡位置开始)或余弦函数(从最大位移开始)。
x = A sin(ωt + φ) 或 x = A cos(ωt + φ)
Here, φ is the phase constant (rad), determined by the initial position and velocity of the oscillator.
其中 φ 为初相位(rad),由振子的初始位置与初速度决定。
For CIE examinations, you must be able to interpret the displacement-time graph: amplitude from the peak value, period from the time between successive peaks, and angular frequency from ω = 2π/T.
在CIE考试中,你需要能够解读位移-时间图像:从峰值读取振幅,从相邻峰值的时间间隔读取周期,并用 ω = 2π/T 计算角频率。
6. Energy Changes in SHM | 简谐运动中的能量变化
During SHM, energy continuously interconverts between kinetic energy (KE) and potential energy (PE). At equilibrium, KE is maximum; at extremes, PE is maximum.
在简谐运动中,能量不断在动能(KE)与势能(PE)之间转换。平衡位置处动能最大,两端处势能最大。
Total mechanical energy (E_total) of a simple harmonic oscillator is constant and given by:
简谐振子的总机械能(E_total)恒定,表达式为:
E_total = ½ m ω² A² = ½ k A²
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Kinetic energy: KE = ½ m v² = ½ m ω² (A² – x²)
动能:KE = ½ m v² = ½ m ω² (A² – x²)
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Potential energy: PE = ½ m ω² x²
势能:PE = ½ m ω² x²
At any displacement x, KE + PE = E_total, demonstrating energy conservation in an ideal SHM system.
在任意位移 x 处,均有 KE + PE = E_total,体现了理想简谐运动系统中的能量守恒。
7. The Spring-Mass System | 弹簧-质量系统
The simplest SHM system is a mass attached to an ideal spring obeying Hooke’s law (F = -kx). The angular frequency and period are related to the mass and spring constant.
最简单的简谐运动系统是连接在满足胡克定律(F = -kx)的理想弹簧上的质量块。其角频率与周期和质量、劲度系数相关。
ω = √(k/m), T = 2π√(m/k)
Key experimental fact: the period does not depend on the amplitude. This property is called isochronism and is fundamental to timekeeping devices.
关键实验事实:周期与振幅无关。这一性质称为等时性,是计时装置的基本原理。
8. The Simple Pendulum | 单摆
A simple pendulum performs SHM only for small angular displacements (typically θ < 10°), where sin θ ≈ θ (in radians). The restoring force is the component of weight tangential to the arc.
单摆仅在摆角较小(通常 θ < 10°)时近似作简谐运动,此时 sin θ ≈ θ(θ 以弧度为单位)。回复力为重力沿圆弧切线方向的分量。
T = 2π√(L/g)
Here, L is the pendulum length (m) and g is gravitational field strength (m s⁻²). The period is independent of the mass and amplitude (for small angles).
其中 L 为摆长(m),g 为重力场强度(m s⁻²)。周期与摆球质量和摆角(小角度下)无关。
9. Displacement, Velocity, Acceleration, and Energy Graphs | 位移、速度、加速度与能量图像
Graphs are essential for exam success. When displacement is described by x = A cos(ωt), the corresponding velocity and acceleration graphs are phase-shifted.
图像分析是考试得分的关键。当位移为 x = A cos(ωt) 时,对应的速度与加速度图像发生相位移动。
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x graph: starts at maximum displacement (+A)
位移图像:从最大位移处(+A)开始
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v graph: starts at zero, 90° (π/2) ahead of displacement
速度图像:从零开始,领先位移 90°(π/2)
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a graph: starts at maximum negative, 180° (π) ahead of displacement, opposite to x
加速度图像:从最大负值开始,领先位移 180°(π),与位移相反
Energy graphs: KE and PE vary sinusoidally at twice the frequency of the motion, while total energy remains a horizontal straight line.
能量图像:动能与势能以运动频率的二倍作正弦变化,而总能量为水平直线。
10. Damping and Forced Oscillations | 阻尼与受迫振动
Real systems experience energy loss, termed damping. In lightly damped SHM, the amplitude gradually decreases while the period remains nearly constant.
实际系统存在能量损耗,称为阻尼。在轻度阻尼的简谐运动中,振幅逐渐减小而周期近似不变。
Oscillators driven by a periodic external force are called forced oscillators. When the driving frequency equals the natural frequency of the system, resonance occurs, producing a sharp increase in amplitude.
由周期性外力驱动的振荡称为受迫振动。当驱动频率等于系统固有频率时发生共振,振幅急剧增大。
Underdamping: T ≈ constant, A decreases exponentially
Critical damping: returns to equilibrium fastest without oscillation
欠阻尼:T ≈ 不变,A 呈指数衰减
临界阻尼:无振荡地最快回到平衡
11. Common Errors in Exams | 考试常见错误
Several misconceptions repeatedly cause mark loss in CIE examinations. Avoiding them will significantly improve your performance.
以下误区在CIE考试中反复导致失分,避免它们将显著提高成绩。
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Confusing velocity and acceleration: at equilibrium, velocity is maximum while acceleration is zero; at extremes, acceleration is maximum while velocity is zero.
混淆速度与加速度:平衡位置处速度最大、加速度为零;两端处加速度最大、速度为零。
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Forgetting the negative sign in a = -ω²x; it represents the direction towards equilibrium.
遗漏 a = -ω²x 中的负号;负号代表方向指向平衡位置。
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Using degrees instead of radians for the phase angle in displacement equations.
在位移方程中把相位角用度而非弧度表示。
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Stating that period depends on amplitude; in ideal SHM, it does not.
错误地认为周期与振幅有关;在理想简谐运动中,周期与振幅无关。
12. Problem-Solving Strategy | 解题策略
A systematic approach to SHM numerical problems leads to higher accuracy and fewer errors.
对简谐运动计算题采用系统化的方法可以提高准确率、减少失误。
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Identify the equilibrium position and the extreme positions; choose the sign convention.
找出平衡位置与两端位置,选定正方向。
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Write down the known quantities (A, T, ω, m, k, x, v, a) and identify the unknown.
列写已知量(A、T、ω、m、k、x、v、a),确定未知量。
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Select the appropriate equation: x = A sin(ωt + φ), v = ±ω√(A² – x²), or a = -ω²x.
选择合适的方程:x = A sin(ωt + φ)、v = ±ω√(A² – x²) 或 a = -ω²x。
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Use energy conservation as an independent check: ½ m v² + ½ k x² = ½ k A².
用能量守恒作为独立检验:½ m v² + ½ k x² = ½ k A²。
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Sanity-check: maximum speed at equilibrium, maximum acceleration at extremes, period independent of amplitude.
合理性检查:平衡位置速度最大、两端加速度最大、周期与振幅无关。
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